The sum of the
square root of a number and six *

Answers

Answer 1
Answer: the equation would be 6 + x(exponent 2)

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a line passes through the origin and has a slope of –3. what is the equation of the line that is perpendicular to the first line and passes through the point (3, 4)?

When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?A.
decrease your scale values
B.
increase your scale values
C.
plot more points
D.
plot fewer points

Answers

The correct answer for this question is this one: "B. increase your scale values"

When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by increasing your scale values
Hope this helps answer your question and have a nice day ahead.

Answer:

Option: B is correct.

B) Increase your scale values.

Step-by-step explanation:

When creating a scatterplot, if the points are too close together to see the relationship,then we must increase the scale value of our graph .

"  Because by doing so the point will seem to be farther and we could see the clear relationship between the points and hence it will not create any confusion regarding the visual of the points and hence easily the inference could be drawn"

Hence, option: B is true.

(B) Increase the scale value)

Set A(18, 12), (20, 17), (24, 10), (25, 6), (28, 4), (30, 4), (32, 2), (34, 3)
Set B
(12, 18), (17, 20), (10, 24), (6, 25), (4, 28), (4, 30), (2, 32), (3, 34)
a. Graph A, Set A
b. Graph A, Set B
c. Graph B, Set A
d. Graph B, Set B

Answers

Answer:

b graph A, set B

Step-by-step explanation:

B—> Graph A, Step B

Explanation

Name the property for the given statement. (4 6)(3) = (4)(3) (6)(3)

Answers

DISTRIBUTIVE PROPERTY IS THE PROPERTY USED IN THE GIVEN STATEMENT...



Answer:

distributive property because you must distribute the numbers in parenthesis

Step-by-step explanation:


HELP! i don’t understand at all

Answers

Answer:

m∠TYW = 93°

Step-by-step explanation:

When naming anangle, the three letters used in the name represent specific points or vertices that define the angle. Each letter has a distinct meaning:

  • First Letter (Initial Point): This represents the starting point for one of the rays or line segments that form the angle.
  • Second Letter (Vertex): This represents the point where the two rays or line segments that form the angle meet.
  • Third Letter (Terminal Point): This represents the terminal point, which is the endpoint for the other ray or line segment that forms the angle.

Therefore, the angle named "VYU" refers to an angle that starts at point V, has a vertex at point Y, and ends at point U. This is shown on the attached diagram in red. Given m∠VYU = 93°:

  • m∠VYU = m∠6 = 93°

The angle named "TYW" refers to an angle that starts at point T, has a vertex at point Y, and ends at point W. This is shown on the attached diagram in blue.

  • m∠TYW = m∠4

Assuming that lines TU and VW are straight lines, ∠6 and ∠4 are vertically opposite angles.

According to the Vertical Angles Theorem, when two straight lines intersect, the opposite vertical angles are congruent.

Therefore, ∠4 ≅ ∠6, so:

  • m∠TYW = m∠VYU

As m∠VYU = 93°, then m∠TYW = 93°.

Answer:

VYW and TYW are opposite interior angles and thus have the same value of 93 deg.

In triangle ABC, angle A measures 33 degrees and angle C measures 122 degrees. What is the measure of angle B?

Answers

Answer:

∠ B = 25°

Step-by-step explanation:

the sum of the three angles in a triangle = 180° , that is

∠ A + ∠ B +∠ C = 180° ( substitute values for A and C )

33° + ∠ B + 122° = 180° , that is

155° + ∠ B = 180° ( subtract 155° from both sides )

155° - 155° + ∠ B = 180° - 155° , that is

∠ B = 25°

A point moves on the x-axis in such a way that its velocity at time t (t>0) is given by v=lnt/t. At which value of t does v attain its maximum? (A) 1
(B) e^(1/2)
(C) e
(D) e^(3/2)
(E) There is no maximum value for v.

Answers

(D) e^(3/2)

v = ln(t) / t 

max of v when dv/dt = 0 
dv/dt = (t/t - ln(t))/t² 
= [1 - ln(t)]/t² = 0 
ln(t) = 1 
t = e (option C) 

check this is a max and not a min 
d²v/dt² = [t²(-1/t) - 2t(1 - ln(t))]/t^4 
= [-1 - 2t + 2t ln(t)]/t^4 

= [-1 - 2e + 2e ln(e)]/e^4 
= [-1 - 2e + 2e]/e^4 
= -1/e^4 < 0 so it is a max