HEY CAN ANYONE PLS HELP ME IN DIS! Which prefix represents a unit that is larger than "centi-" ? a. "nano-" b. "pico-" c. "milli-" d. "deci-" e. "micro-"

Answers

Answer 1
Answer: i believe it’s d.)deci

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What does the term heat death refer to?a. a danger of increasing entropy
b. the hot and fiery end to the universe
c. the unavailability of energy to do work
d. a theoretical violation of the second law of thermodynamics

Answers

The term heat death refers to a danger of increasing entropy. The correct option among all the options that are given in the question is the first option or option "a". This theory stems from the second law of thermodynamics and it states that entropy tends to increase in any isolated system. I hope the answer helps you.

A 5.0-kg object is pulled along a horizontal surface at a constant speed by a 15-n force acting 20° above the horizontal. How much work is done by this force as the object moves 6.0 m?

Answers

A 5.0 kg object is pulled by a 15-N force acting 20 °C above the horizontal. After moving for 6.0 m, the work done is 85 J.

What is work?

In physics, work is the energy transferred to or from an object via the application of force along a displacement.

A 5.0 kg object is pulled by a 15-N force acting 20 ° above the horizontal. We can calculate the work done after the object moved 6.0 m using the following expression.

W = F × s × cosθ

W = 15 N × 6.0 m × cos 20° = 85 J

where,

  • W is the work.
  • F is the force.
  • s is the displacement.
  • θ is the angle between F and s.

A 5.0 kg object is pulled by a 15-N force acting 20 °C above the horizontal. After moving for 6.0 m, the work done is 85 J.

Learn more about work here: brainly.com/question/62183

Answer:

84.6 J

Explanation:

The work done by the force is given by

W=Fd cos \theta

where

W is the work done

F = 15 N is the force applied

d = 6.0 m is the displacement

\theta=20^(\circ) is the angle between the force's direction and the displacement

Substituting the numbers into the equation, we find

W=(15 N)(6.0 m)cos 20^(\circ) =84.6 J

An object that has a height of 0.4 meter is placed at a distance of 0.7 meter from a concave spherical mirror. An image is formed in front of the mirror and has a height of 0.35 meter. How far from the mirror is the image located?A. 0.2000 m
B. 0.4275 m
C. 0.6125 m
D. 0.8000 m

Answers

Answer

C. 0.6125 m

Explanation

The magnification of an image produced by curved mirrors can be given in two ways;

Magnification, M = (Height of the image) / (height if the object) and

M = (image distance,V) / (Object distance, U).

Using the first formula,

M = 0.35/0.4

= 0.875

Now from the second formula,

M = V/U

0.875 = V/0.7

V = 0.875 × 0.7

= 0.6125 m



Answer : v = 0.1625 m.

Explanation :

It is given that,

Height of an object, h_o=0.4\ m

Object distance, u=-0.7\ m

Height of an image, h_i=0.35\ m

We have to find the image distance (v).

We know that the magnification of mirror is the ratio of height of image to the height of object.

i.e. m=(h_i)/(h_o)..............(1)

Also, magnification is the ratio of image distance to that of object distance.

i.e m=(-v)/(u)............(2)

So, from equation (1) and (2)

(-v)/(u)=(h_i)/(h_o)

(-v)/(-0.7\ m)=(0.35\ m)/(0.4\ m)

v=0.6125\ m

So, image is located at a distance of 0.6125 m.

A 2210 kg 2210 kg space station orbits Earth at an altitude of 5.39 × 10 5 m. 5.39×105 m. Find the magnitude of the force with which the space station attracts Earth. The mass and mean radius of Earth are 5.98 × 10 24 kg 5.98×1024 kg and 6.37 × 10 6 m, 6.37×106 m, respectively.

Answers

Answer:

18466.68 N

Explanation:

mass of satellite, m = 2210 kg

mass of earth, M = 5.98 x 10^24 kg

distance between surface of earth and the satellite, h = 5.39 x 10^5 m

radius of earth, R = 6.37 x 10^6 m

The force between the earth and the satellite is given by

F = (GMm)/(\left (R+h  \right )^(2))

F = (6.67* 10^(-11)* 5.98* 10^(24)* 2210)/(\left (6.37+0.539 \right )^(2)* 10^(12))

F = 18466.68 N

If a cup of coffee is at 90°C and a person with a body temperature of 36'C touches it,how will heat flow between them

Answers

Answer:

the heat always transfers from high temperature to low temperature body without aid of any external energy to this law the heat transfers from cup of coffee to the person body until both bodies reaches to the equilibrium state    

Explanation:

Which of the following changes would make a heat engine less efficient

Answers

A heat engine would be less efficient due to many factors 
For instance, a heat engine is more efficient when it uses in cold weather because there is a greater temperature difference ( Carnot Efficient )
A heat engine could be less efficient because of friction
Hope it helps I am a beginner