Answer:
0.1
Step-by-step explanation:
hope this helps
Find, if possible, the slope of the line through the points (2 , 5) and (-4 , 5)
Answer:
0
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(5-5)/(-4-2)
m=0/-6
m=0
A polynomial multiple by a polynomial is always a polynomial. The given statement is true.
Polynomials are those algebraic expressions that consist of variables, coefficients, and constants. The standard form of polynomials has mathematical operations such as addition, subtraction, and multiplication.
When two polynomials are multiplied by each other, then each term of the first polynomial is multiplied by each term of the second polynomial.
The result is always a polynomial, regardless of what the coefficients might be of any of the terms, including the leading coefficients.
Thus, A polynomial multiples by a polynomial is always a polynomial.
Learn more about polynomials;
If Whitley park is a rectangular park with a perimeter of 70 yards. One side of Whitley park is 18 feet long then 174 yards is the area.
Area of rectangle is length times of breadth.
We know that 18 feet=6 yards.
It is given that One side of Whitley park is 18 feet long, so one side of length is 6 yards.
2(Lenght+breadth)=70
2(L+6)=70
2l+12=70
2l=70-12
2l=58
l=29 yards
Now
Area =Length×breadth
=29×6
= 174 square yards
Hence 174 square yards is the area of Whitley park.
To learn more on Area of Rectangle click:
#SPJ2
Answer:
174 yards squared
Step-by-step explanation:
Due soon!!
Answer:
6
Step-by-step explanation:
got it right
(a + 2)^2 + (b - 5)^2 + (c - 6)^2
c.
a + b + c -(-2 + 5 + 6)
b.
sqrt((a+2)^2+(b-5)^2+(c-6)^2)
d.
((a + 2) + (b - 5) + (c - 6))^2
Answer:
b. sqrt(a+2)^2+(b-5)^2+(c-6)^2
Step-by-step explanation:
Use distance formula
sqrt (a-(-2)^2 + (b-5)^2 + (c-6) ^2
sqrt (a+2)^2 +(b+5)^2 + (c-6)^2
Answer:
B
Step-by-step explanation:
took it on edge, it's the right answer :)
Answer:
10
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
To find the lowest common denominator, you can use prime factorization on the denominators to find their least common multiple. In this case, you don't need to do that because both denominators are already prime, so you can just multiply 2 by 5 to get 10.