MATHEMATICS HIGH SCHOOL

(will give brainliest)a hiker, whose eye is 1.6 meters above ground, stands 50 meters from the base of connecting her eye and the top of the cliff and a horizontal line is 58°. draw a diagram representing the situation and find the height of the cliff

Answers

Answer 1

Answer:

Answer:

The height of the cliff is 81.6m

Step-by-step explanation:

Please see the attachment below for an illustrative diagram representing the situation.

Step-by-step explanation:

From the diagram

x = /AB/

The height of the cliff is given by ( x + 1.6m)

Considering triangle ABC which is a right-angle triangle

/AB/ is the opposite and

/BC/ is the adjacent ; /BC/ = 50m

Angle of elevation is 58°

Then, we can write that

$Tan 58^(o) = (/AB/)/(50m)$

$/AB/ = 50 (tan58^(o))\n$

$/AB/ = 50 * 1.600$

$/AB/ = 80.0m$

Hence, Side /AB/ = 80.0m

Since, /AB/ = x

∴ x = 80.0 m

Recall, the height of the cliff is given by

x + 1.6m

= 80.0m + 1.6m

= 81.6 m

Hence, the height of the cliff is 81.6m

Answer 2

Answer:

Answer:

80.02m

Step-by-step explanation:

Find the diagram attached. Using SOH, CAH, TOA to find the height of the cliff AC,

AC is the opposite side and BC is the adjacent

Given BC = 50m and ∠ABC = 58°

tan∠ABC = AC/BC

tan58° = AC/50

cross multiply

AC = 50tan58°

AC = 80.02m

Hence the height of the cliff is 80.02m

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Write the following number in expanded form 46,371

Answers

46,371 = 40,000 + 6,000 + 300 + 70 + 1

Y=10 when x=8 what is x when y=30

Answers

Answer:

X= 24

Step-by-step explanation:

Y was multiplied by 3 to equal 30, so same rules are applied and you multiply 8 by 3

Answer:

28 or 24 im not sure which

What is the value of x in the equation x-2/3 + 1/6 =5/6 ?

Answers

x is a negative one (-1). The negative one makes it so that the -2/3 is a positive when they multiply.

So in this problem we can see that 2 out of 3 of the fractions have a denominator of 6. One of the fractions (2/3) has a denominator of 3. But we can make the denominator 6 by multiplying it by 2!

Now the equation is:

x - 4/6 + 1/6 = 5/6

So now let's solve for x!

x - 4/6 + 1/6 = 5/6

x + 1/6 = 9/6 (Addition property of equality)

x = 8/6 (Subtraction property of equality)

Now we divide...

8 divided by 6 equals 1.33

Now if we plug that into the equation as 1 and 1/3...

1 and 1/3 - 2/3 + 1/6

2/3 + 1/6

4/6 + 1/6 = 5/6

So that means your answer is decimal 1.33 or mixed fraction 1 and 1/3

Which expressions are perfect square trinomials? Check all that apply. A. x2 + 16x + 8
B. x2 + 14x + 49
C. x2 – 5x + 25
D. x2 – 24x + 144
E. x2 + 9x – 81

Answers

perfect square trinomials are in the form
ax^2+bx+c such that
a=1
(b/2)^2=c

check each
all of them have 1 in front so skipt that step

A. (16/2)^2=8? false so no
B. (14/2)^2=49? true, this is
C. (-5/2)^2=25? false, this is not
D. (-24/2)^2=144? true, this is
E. (-9/2)^2=-81? false (easy way is that x^2 is never equal to a negative unless it is complex

B and D are answers

A. Doesn't work
B. (x + 7)(x + 7) = Works
C. Doesn't work
D. (x - 12)(x - 12) = Works
E. Doesn't work

Therefore the answers are B and D
The other don't work because they do not become perfect squares.

In the graph above, the cordinates of the vertices of quadrilateral QPRS are Q(2,4), P(2,4), R(3,1), and S(1,1). If quadrilateral QPRS is reflected across the x-axis to create quadrilateral GHIJ l, find tge coordinates of point j

Answers

In the following graph, the coordinates of the vertices of quadrilateral QPRS are Q(2,4), P(4,4), R(3,1), and S(1,1). If quadrilateral QPRS is reflected across the x-axis to create quadrilateral GHIJ l, these coordinates are G(1,-1), H(3,-1) , I(2,-4) and J(4,-4).

Answer:

As, when Graph is reflected across the X axis

1. The two, Image which is Quadrilateral G H I J and Pre image which is Quadrilateral QPRS will be congruent.

2. Distance from X axis to each of the vertices of Quadrilateral QPRS will be same as distance from each of the vertices of Quadrilateral G H I J from X axis.

As, Quadrilateral QPRS lies in first Quadrant, so when it is reflected across X axis, it moves in Second Quadrant which is Quadrilateral GHIJ.

Q→→G, P→→H, R→→I, S→→J.

Coordinates of S=(1,1)

Coordinates of J=(-1,1)

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