MATHEMATICS HIGH SCHOOL

The histogram shows the heights in meters of trees in a certain section of a park.How many trees are less than 16 meters tall?



A histogram titled Heights of Trees with Height in meters on horizontal x-axis and Frequency on vertical y-axis


5


9


16


12

Answers

Answer 1
Answer:

Answer:

16

Step-by-step explanation:
Answer 2
Answer:

Final answer:

In a histogram, the total number of trees that are less than 16 meters tall would be the sum of frequencies of all the bars representing heights less than 16 meters. To find this, locate the 16-meter mark on the x-axis and add up the frequencies of all intervals up to and including that point.

Explanation:

The total number of trees that are less than 16 meters tall would be the sum of frequencies of all the bars on the histogram representing heights less than 16 meters. Histograms provide a visual representation of data distribution. The x-axis lists the categories or numbers for the data, in this case tree heights, and the y-axis represents the frequency, or how often a particular height occurs. To find the total number of trees less than 16 meters tall, locate the 16-meter mark on the x-axis and add up the frequencies (height of the bars) of all intervals up to and including that point.

Learn more about Histogram Interpretation here:

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Yannick’s class measured the width of one leaf several times. The values that the class recorded included 10 mm, 8 mm, 15 mm, 5 mm, and 13 mm. What is lacking from the measurements that the class made?A.calibration
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Answers

"Precision" is the one among the following choices given in the question that is lacking from the measurements that the class made. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has come to your desired help.

Answer:

The answer is b i just took the test

Step-by-step explanation:

2 more than the product of 4 times m Express algebraically

Answers

The product of 4 times 'm' . . . . . 4m

2 more than that . . . . . . . . . . . . 4m + 2

Solve.
3/4x=18 please show work ...?

Answers

18 = 3/4x
3 = 18 x 4x
4x = 3/18
4x = 1/6
x = 1/24
4/3 times 3/4 to cancel out

18 times 4/3
this will be 72/3

72 divided by 3 is 24

X = 24

Help on logarithmic equation

Answers

\log _( 2 ){ \left( 3-x \right) } +\log _( 2 ){ 5 } =2\log _( 3 ){ 5 } \n \n \log _( 2 ){ \left( 5\left( 3-x \right) \right) } =\log _( 3 ){ \left( { 5 }^( 2 ) \right) } \n \n { 2 }^{ \log _( 3 ){ 25 } }=5\left( 3-x \right) \n \n { 2 }^{ \log _( 3 ){ 25 } }=15-5x\n \n 5x=15-{ 2 }^{ \log _( 3 ){ 25 } }\n \n x=\frac { 15 }{ 5 } -\frac { { 2 }^{ \log _( 3 ){ 25 } } }{ 5 } \n \n x=3-\frac { { 2 }^{ \log _( 3 ){ 25 } } }{ 5 }

36 & 64 are both square numbers. They Have a sum of a 100 Find Two Square numbers that have a sum of 130

Answers

81 and 49 would have a sum of 130
81 and 49 would make 130

In a right triangle, one acute angle is 22º and the hypotenuse is 70 cm. Find thelengths of the legs and the other angle measure.

Answers

Answer:

Adjacent leg (In relation to the angle that is measure 22 degrees)= 70*Cosine 22 or 64.9; Opposite leg (In relation to the angle that is measure 22 degrees)=70* Sin 22 or 26.22

Step-by-step explanation:

The other angle measure is 90-22 or 68.

To find the length of the adjacent leg (a) use cosine. Remember cosine is Adjacent leg over hypotenuse.

Cosine 22= a/70- Multiply by 70

70* Cosine 22=a or about 64.9

To find the length of the opposite leg (o) use sine. Remember sine is Opposite leg over hypotenuse

Sine 22= o/70

70*Sine 22=o

o= about 26.22
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