Which layer of the earth can only be studied by indirect means

Answers

Answer 1

Answer:

The mantle stretches down 2,890 kilometers, making it the Earth's thickest layer and the core that can be studied only by indirect means.

What are the layers of earth?

The layers of earth can be defined as the layer which is present inside the earth surface.

There are basically three different layers of earth.

Crust - It is defined as the a rocky planet's, dwarf planet's, or natural satellite's outermost solid shell.
Mantle - It is defined as the thick layer of heated, solid rock between the Earth's crust and the molten iron core.
Core - It is defined as the center of gravity where all the movements begins.

Thus, the mantle stretches down 2,890 kilometers, making it the Earth's thickest layer and the core that can be studied only by indirect means.

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Answer 2

Answer: Everything except for the crust, including the Mantle and the core.

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What is the approximate hydronium ion concentration and hydroxide ion concentration in a cup of tea? Which is higher?

Answers

suppose pH = 5 then pOH = 14-5 = 9
[OH-] = 10^-pOH
= 10^-9
= 1.00x 10^-9
hope it helps

The negative log of hydrogen or hydronium ions concentration gives the pH of the solution. The concentration of hydronium is more than the hydroxide ions.

What are pH and pOH?

The pH of the solution is the concentration of the hydrogen or the hydronium ion in the aqueous solution, whereas the concentration of the hydroxide ion in the solution gives the pOH.

Let the pH of the tea = 5 then,

The concentration of hydronium ion is calculated as:

$\begin{aligned}\rm pH &=\rm -log[H_(3)O^(+)]\n\n\rm [H_(3)O^(+)] &= \rm 10^(-pH)\n\n&= 10 ^(-5)\end{aligned}$

The concentration of hydroxide ion is calculated as:

$\begin{aligned} \rm pH &= \rm 14 - pOH \n\n&= 14 - 5\n\n&= 9\end{aligned}$

Calculating further:

$\begin{aligned}\rm pOH &= \rm -log[OH^(-)]\n\n\rm [OH^(-)]& =\rm 10^(-pOH)\n\n&= 10^(-9)\end{aligned}$

Therefore, the concentration of the hydronium ion is much higher than that of the hydroxide ion.

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show me the steps for solving this problem how many grams of O2 are required to burn 46.0 grams of C5H12

Answers

(MM)C5H12=5x12+12x1=72g/mol
(MM)O2=2x16=32g/mol
Acoording to equation:
C5H12 + 8O2 => 5CO2 + 6H2O

The proportion between C5H12 and O2 is 1:8 in mol

So: 72/16=46/x finale x=10,2g of O2

Its atom contains 50 electrons and 70 neutrons

Answers

Tin-120 because an atom has to have a neutral charge. If an atom has 50 electrons it must have 50 protons unless it's an ion. Add 70 to the atomic mass because it has 70 neutrons on top of 50 protons. That equals to 120. Tin has an atomic number of 50 (meaning it has 50 protons) and it has roughly an atomic mass of about 118. If the given has 70 neutrons then it's a isotope of tin.

What are the states of matter

Answers

solid, liquid, gas, and plasma.

A 0.0489 mol sample of a nutrient substance, with a formula weight of 114 g/mol, is burned in a bomb calorimeter containing 6.56 × 10² g h2o. given that the fuel value is 2.04 × 10⁻¹ in nutritional cal when the temperature of the water is increased by 1.73°c, calculate the fuel value in kj.

Answers

To calculate the fuel value in kJ, we need to convert the nutritional calories to kilojoules.

1 nutritional calorie (cal) = 4.184 kilojoules (kJ)

First, let's calculate the energy released by burning the 0.0489 mol sample of the nutrient substance in calories:

Energy released = moles of nutrient substance * formula weight * fuel value

Energy released = 0.0489 mol * 114 g/mol * 2.04 × 10⁻¹ cal

Next, let's convert the energy released from calories to kilojoules:

Energy released (kJ) = Energy released (cal) * 4.184 kJ/cal

Now, let's substitute the given values into the equations:

Energy released = 0.0489 mol * 114 g/mol * 2.04 × 10⁻¹ cal
Energy released ≈ 0.11185 cal

Energy released (kJ) = 0.11185 cal * 4.184 kJ/cal
Energy released (kJ) ≈ 0.467 kJ

Therefore, the fuel value of the nutrient substance is approximately 0.467 kJ.

Final answer:

To calculate the fuel value in kJ, convert nutritional calories to joules and then to kilojoules.

Explanation:

To calculate the fuel value in kJ, we need to convert the nutritional calories to joules and then to kilojoules. We can use the equation: fuel value (in kJ) = fuel value (in cal) x 4.184 / 1000. Given that the fuel value is 2.04 × 10⁻¹ nutritional cal, we can substitute it into the equation to get the fuel value in kJ.

fuel value (in kJ) = 2.04 × 10⁻¹ x 4.184 / 1000 =8.5288 x 10⁻³ kJ

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Calculate the pH of the aqueous solution of 0.0243 M HNO3(aq).

Answers

pH= -log [ $H^(+)$ ]
= 1.61

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