A space probe has two engines. Each generates the same amount of force when fired, and the directions of these forces can be in- dependently adjusted. When the engines are fired simultaneously and each applies its force in the same direction, the probe, starting from rest, takes 28 s to travel a certain distance. How long does it take to travel the same distance, again starting from rest, if the engines are fired simultaneously and the forces that they apply to the probe are perpendicular

Answers

Answer 1
Answer:

Answer:

t = 39.60 s

Explanation:

Let's take a careful look at this interesting exercise.

In the first case the two motors apply the force in the same direction

            F = m a₀          

           a₀ = F / m

with this acceleration it takes t = 28s to travel a distance, starting from rest

           x = v₀ t + ½ a t²

           x = ½ a₀ t²

           t² = 2x / a₀

           28² = 2x /a₀          (1)

in a second case the two motors apply perpendicular forces

we can analyze this situation as two independent movements, one in each direction

           

in the direction of axis a, there is a motor so its force is F/2

               

the acceleration on this axis is

          a = F/2m

          a = a₀ / 2

so if we use the distance equation

             x = v₀ t + ½ a t²

as part of rest v₀ = 0

             x = ½ (a₀ / 2) t²

             

let's clear the time

             t² = (2x / a₀)  2

we substitute the let of equation 1

             t² = 28² 2

             t = 28 √2

             t = 39.60 s


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1. A surfboarder rides a wave for 23.7 m at a constant rate of 4.1 m/s. How long did his triptake?

Answers

Answer:

His trip took 5.78 seconds

Explanation:

23.7m divided by 4.1m/s = 5.78048780488

A train travels 64 kilometers in 5hours and then 93 kilometers in 2hours. What is it’s average speed?

Answers

I believe the answer is about 22.43 kilometers per hour. However I am not 100% sure.

How I got this: first you add 64 and 93, then 5 and 2. That would leave you with the kilometers traveled (157) over the number of hours (7). You’d have to divide, which would leave you with an estimated 22.4285. Round to the nearest hundredth and you get 22.43 . Please correct me if I’m wrong!

An artificial satellite circling the Earth completes each orbit in 144 minutes. (a) Find the altitude of the satellite.

Answers

Answer:

Explanation:

given,

time taken to complete the each orbit = 144 minutes

                      t = 144 x 60 = 8640 s

mass of the earth = 5.98 x 10²⁴ Kg

radius of earth,R = 6.38 x 10⁶ m

Using Kepler's 3rd law

T^2 = ((4\pi^2)/(GM_e))r^3

r = ((T^2GM_e)/(4\pi^2))^(1/3)

r = ((8640^2* 6.67 * 10^(-11)* 5.98* 10^(24))/(4\pi^2))^(1/3)

r = 9.1 x 10⁶ m

the altitude of the satellite

H = r - R

H =  9.1 x 10⁶  - 6.38 x 10⁶

H = 2.72 x 10⁶ m

A 2,000 kg car travels with a tangentialvelocity of 12 m/s around a circular
track with a radius of 30 meters. What
is the car's rate of centripetal
acceleration?

Answers

The car's rate of centripetal acceleration in the circular path is 4.8 m/s².

The given parameters;

  • mass of the car, m = 2,000 kg
  • velocity of the car, v = 12 m/s
  • radius of the circular path, r = 30 m

The centripetal acceleration of the car is calculated as follows;

a_c = (v^2)/(r)

where;

  • v is the tangential speed of the car
  • r is the radius of the circular path

Substitute the given parameters and solve for the centripetal acceleration;

a_c = (12^2)/(30) \n\na_c = 4.8 \ m/s^2

Thus, the car's rate of centripetal acceleration is 4.8 m/s².

Learn more here:brainly.com/question/11700262

a= v²/R
a = 12²/30 =4.8 m/s²

What is the weight of a 5.0-kilogram object at the surface of Earth?A
5.0 kg
B
25 N
C
49 kg
D
49 N

Answers

The weight of a 5.0-kilogram object at the surface of Earth is 49 N. Hence, option (C) is correct.

What are mass and weight?

Mass is a fundamental quantity in physics and the most fundamental attribute of matter. Mass can be defined as the amount of matter contained in a body. Kilogram is the SI unit of mass (kg).

A body's mass does not alter at any time. Only in severe instances where a massive amount of energy is provided or removed from the body.

The force of gravity acting on a body is measured by weight. The weight formula is as follows: w = mg. Because weight is a force, it has the same SI unit as force; the SI unit of weight is Newton (N).

The weight of the  object is = 5.0 × 9.8 N

= 49.0 N.

Hence, option (B) is correct.

Learn more about weight here:

brainly.com/question/10069252

#SPJ2

Answer:

49 N (d)

Explanation:

w= mg = 5 kg * 9.8 m/s^2 = 49 N

A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 27.0 m/s by a 7850 N braking force acting opposite the car’s motion. What is the car's velocity after 2.52s?
How far does the car move during the 2.52 s?
How long does it take the car to come to a complete stop?

Answers

Answer:

19.1 m/s

58.1 m

8.60 s

Explanation:

Take north to be positive and south to be negative.

Use Newton's second law to find the acceleration.

∑F = ma

-7850 N = (2500 kg) a

a = -3.14 m/s²

Given:

v₀ = 27.0 m/s

a = -3.14 m/s²

Find: v given t = 2.52 s

v = at + v₀

v = (-3.14 m/s²) (2.52 s) + 27.0 m/s

v = 19.1 m/s

Find: Δx given t = 2.52 s

Δx = v₀ t + ½ at²

Δx = (27.0 m/s) (2.52 s) + ½ (-3.14 m/s²) (2.52 s)²

Δx = 58.1 m

Find: t given v = 0 m/s

v = at + v₀

0 m/s = (-3.14 m/s²) t + 27.0 m/s

t = 8.60 s