If mUV= (8x-17) and mWV= (5x+52) find mWV

Answers

Answer 1
Answer:

Answer:

equation is (5x,±52) = (8x±17) first u want to add 52 and 17 to get 69 then 8x subtracted by 5x to get 3x then divide 3 by 69 to get 23


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What is the sum of r + s when r = –17.6 and s = 12.2? A. –29.8 B. –5.4 C. 5.4 D. 29.8

Answers

c. -5.4 -17.6+12.2= -5.4 because -17.6 goes first in the calculator but also its a negative

What is 70/6 as a mixed number

Answers

70/6 is basically saying "divide 70 by 6". So to get to a mixed numer, thats what you have to do.

70/6=11.666666...
(.666666..... is 2/3 as a fraction)

The answer is 11 2/3.


hope i helped!! :))
11 4/6 because 6 can go into 70 11 times and its just 4/6 so 11 4/6

Express the number of inches n (d) as a function of the number of yards d

Answers

An= a1+(r-1)d
Is the formula for an arithmetic function involving D

How much is 2/3 of 9 marbles?

Answers

6 marbles
Explanation: Take 9 and ÷ by 3, then take 2 and multiply it by 2.

Answer:

6

Step-by-step explanation:

First divide 9 by 3 to get 3, then multiply 3 by 2 to get 6.

Trust me on this, also can I have brainiest please?

Hope you do well! :D

What is three fractions equivalent to 3/11

Answers

3/11 *2 = 6/22
3/11 *3= 9/33
3/11 *4 = 12/44

Is relation t a function? Is the inverse of relation t a function? Relation t:

x; 0 , 2 , 4 , 6
y; -10 , -1 , 4 , 8

Relation t is not a function. The inverse of relation t is not a function.

Relation t is a function. The inverse of relation t is a function.

Relation t is a function. The inverse of relation t is not a function.

Relation t is not a function. The inverse of relation t is a function.

( I think its a, but not sure ? )

Answers

Answer:

Hence, Relation t is a function. The inverse of relation t is a function.


Step-by-step explanation:

We are given the relation as:


x:    0 , 2 , 4 , 6


y:   -10 , -1 , 4 , 8

Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).

Hence, the corresponding relation is a function.

Now we have to find whether the inverse of this relation is a function or not.

When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.

Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.

Hence, Relation t is a function. The inverse of relation t is a function.




Relation t is a function and the inverse of relation t is a function because each domain element unique and it is paired to an unique range element.