MATHEMATICS HIGH SCHOOL

At noon, train A leaves Bridgton headingeast at 90 mi/h to Cogsville. At 12:30 PM,
train B leaves Bridgton and heads east at
100 mi/h. At what time will train B catch
up to train A?

Answers

Answer 1
Answer:

Train B will catchup to Train A at 5:30 PM.

We have,

d = distance covered by both trains when they meet

t = time it takes for train B to catch up to train A

For train A:

Distance = Speed × Time

d = 90t

For train B:

Distance = Speed × Time

d = 100(t - 0.5) (train B departs 30 minutes (0.5 hours) later than train A)

Since both equations represent the samedistance, we can set them equal to each other:

90t = 100(t - 0.5)

Let's solve for t:

90t = 100t - 50

10t = 50

t = 5

It will take 5 hours for train B to catchup to train A.

To determine the time when train B catches up to train A, we add the 5 hours to the departure time of train B, which is 12:30 PM:

12:30 PM + 5 hours = 5:30 PM

Therefore,

Train B will catchup to Train A at 5:30 PM.

Learn more about speed here:

brainly.com/question/7359669

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Answer 2
Answer:

I'd say maybe by 5:30 b would

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Hello,

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