MATHEMATICS COLLEGE

A comic book store is having sale. You can buy 20 comic books for $35. What is cost of 8 comic books during the sale

Answers

Answer 1

Answer:

Answer:

The cost of 8 comic books is $14

Step-by-step explanation:

Given

$20\ books = \$35$

Required

Determine the cost of 8 books

First, we need to determine the cost of 1 book

$20\ books = \$35$

Divide through by 20

$20\ books/20 = \$35/20$

$1\ book = \$35/20$

$1\ book = \$1.75$

Then multiply both sides by 8 to get the cost of 8

$8 * 1\ book = \$1.75 * 8$

$8 \ books = \$14$

Hence;

The cost of 8 comic books is $14

Answer 2

Answer:

answer: is 2.5 and c.15 are equivalent ratios what isvalue of C?

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2x + 3y = 12Complete the missing value in the solution to the equation.,8)

Write the products

6 tens =
9 tens =
12 tens=
10 elevens=

Answers

Answer:

see below

Step-by-step explanation:

6 tens = 6 * 10 = 60

9 tens =9* 10 = 90

12 tens=12 * 10 = 120

10 elevens=10 * 11 = 110

At a basketball game, a vender sold a combined total of 108 sodas and hot dogs. The number of sodas sold was three times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.

Answers

Answer:

Hot dogs - 27, soda - 81

Step-by-step explanation:

Soda to Hot dog ratio = 3:1

If the total is 108, we can divide 108/4 ---> 27

now, multiply 3 and 1 by 27 and there you go!

edit: also if you don't know why I divided 108 by 4, its because you add together both sides of the ratio

Three instrument panel designs are being considered. We are interested in pilot response times as a function of these panel designs. Randomly selected pilots are randomly given simulated emergency situations and response times are measured. We are concerned that pilot experience may also influence our results. Analyze the data both including and not including the covariate of experience. Does including the covariate matter in this case? Is there another covariate we should have included?

Answers

Answer:

see the analysis below

Step-by-step explanation:

Suppose that is in standard position and the given point is on the terminal side of 0. Give the exact value of the indicated trig function for 0. 15) (-5, 12); Find sin

Answers

Answer:

12/13

Step-by-step explanation:

The length of the segment from the origin to the terminal point is ...

r = √((-5)² +12²) = √169 = 13

The sine of the angle is the ratio of the y-coordinate to this distance

sin(θ) = y/r = 12/13

_____

Additional comment

The other trig functions are ...

cos(θ) = x/r = -5/13

tan(θ) = y/x = -12/5

This is a 2nd-quadrant angle, where the sine is positive, but the cosine and tangent are negative.

One normally distributed with mean value 20 in. and standard deviation .5 in. The length of the second piece is a normal rv with mean and standard deviation 15 in. and .4 in., respectively. The amount of overlap is normally distributed with mean value 1 in. and standard deviation .1 in. Assuming that the lengths and amount of overlap are independent of each other, what is the probability that the total length after insertion is between 34.5 and 35 in.

Answers

Answer:

The probability that the the total length after insertion is between 34.5 and 35 inches is 0.1589.

Step-by-step explanation:

Let the random variable X represent the length of the first piece, Y represent the length of the second piece and Z represents the overlap.

It is provided that:

$X\sim N(20,\ 0.50^(2))\nY\sim N(15,\ 0.40^(2))\nZ\sim N(1,\ 0.10^(2))$

It is provided that the lengths and amount of overlap are independent of each other.

Compute the mean and standard deviation of total length as follows:

$E(T)=E(X+Y-Z)\n=E(X)+E(Y)-E(Z)\n=20+15-1\n=34$

$SD(T)=√(V(X+Y-Z))\n=√(V(X)+V(Y)+V(Z))\n=\sqrt{0.50^(2)+0.40^(2)+0.10^(2)}\n=0.6480741\n\approx 0.65$

Since X, Y and Z all follow a Normal distribution, the random variable T, representing the total length will also follow a normal distribution.

$T\sim N(34, 0.65^(2))$

Compute the probability that the the total length after insertion is between 34.5 and 35 inches as follows:

$P(34.5<T<35)=P((34.5-34)/(0.65)<(T-\mu_(T))/(\sigma_(T))<(35-34)/(0.65))\n\n=P(0.77<Z<1.54)\n\n=P(Z<1.54)-P(Z<0.77)\n\n=0.93822-0.77935\n\n=0.15887\n\n\approx 0.1589$