The difference between two times a number and four is eight. Write the phrase as a algebraic equation

Answers

Answer 1

Answer:

The algebraic equation will be written in this way 2x - 4 = 8.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the difference between two times a number and four is eight. The expression will be written as below:-

2x - 4 = 8.

2x = 8 + 4

x = 12 / 2

x = 6

Therefore, the algebraic equation will be written in this way 2x - 4 = 8.

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Answer 2

Answer:

Step-by-step explanation:

Let x represent the number.

Then 2x - 4 = 8.

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Find the rational number halfway between 5/16 and 7/8

Answers

$\left((5)/(16)+(7)/(8)\right):2=\left((5)/(16)+(14)/(16)\right):(2)/(1)=(5+14)/(16)\cdot(1)/(2)=(19)/(16)\cdot(1)/(2)=(19)/(32)$

A coin is tossed and a six-sided die numbered 1 through
6 is rolled. Find the probability of tossing a
head and then rolling a number greater than 4.

Answers

The probability of tossing a head and then rolling a number greater than 4 is 1/6. The probability says the number of possible outcomes from the total outcomes of an event.

What is probability?

The probability is defined as the ratio of the count of the favorable outcomes to the total count of the outcomes of the sample.

P(A) = n(A)/n(S) where A is n event, n(S) is the total count of the sample, and n(A) is the count of favorable outcomes.

Calculating the probability:

The given events are tossing a coin and rolling a dice.

The favorable outcomes for these events are given as tossing a head and rolling a number greater than 4.

Calculating the probability of tossing a coin:

The total outcomes of the event are 2 (head and tail)

The favorable outcome = 1 (only head)

So, the probability of tossing a head = 1/2

Calculating the probability of rolling a dice:

The total outcomes of the event are 6 ( a dice has 6 faces with a number on each face (1 to 6))

So, there are only two numbers that are greater than 4 (5, 6)

The favorable outcomes = 2

So, the probability of rolling a numbergreater than 4 = 2/6 =1/3

Calculating the probability of two events at the same time:

To get this probability- multiply both the probabilities.

⇒ 1/2 × 1/3 =1/6

Therefore, the required probability is 1/6.

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tossing a head = 1/2
rolling a number greater then 4 = 2/6 = 1/3

1/2 * 1/3 = 1/6 <==

What is the answer for N+4=6

Answers

The answer would be n=2

6-4=2 so n must be 2

Convert to vertex form.
y=2x^2+14x-4

Answers

$y=2x^2+14x-4\n\na=2;\ b=14;\ c=-4\n\nvertex\ form:y=a(x-h)^2+k\n\nwhere:h=(-b)/(2a)\ and\ k=(-(b^2-4ac))/(4a)\n\nh=-(-14)/(2\cdot2)=-(7)/(2)\n\nk=(-(14^2-4\cdot2\cdot(-4)))/(4\cdot2)=(-(196+32))/(8)=(-228)/(8)=-(57)/(2)\n\n\nAnswer:y=2(x+(7)/(2))^2-(57)/(2)$

$To \ convert \ the \ standard \ form \ y = ax^2 + bx + c \ of \ a \ function \ into \ vertex \n \nform \ y = a(x - h)^2 + k \n \n Here \ the \ point \ (h, k) \ is \ called \ as \ vertex \n \n h=(-b)/(2a) , \ \ \ \ k= c - (b^2)/(4a)$

$y=2x^2+14x-4 \n \na=2 ,\ b=14 , \ c=-4 \n \n h=(-14)/(2*2)=-(14)/(4)=-3.5 \n \nk= -4 - (14^2)/(4\cdot 2)=-4-(196)/(8)=-4-24.5=-28.5 \n \n y=2(x+3.5)^2 -28.5$

Can some help me fast!

Answers

Answer:

5x +2y =38

5(6) +2y = 38

30 +2y= 38

2y= 8

y= 4

(6, 4)

5(0) +2y =38

2y= 38

y= 19

(0,19)

5(-2) +2y= 38

-10 +2y =38

2y= 48

y=24

(-2,24)

At a local hospital, 35 babies were born. if 23,were boys, what percentage of the newborns were boys?

Answers

The percentage of newborns who were boys is 65.71%.

Given that

At a local hospital, 35 babies were born.

There are 23 were boys.

We have to determine

What percentage of the newborns were boys?

According to the question

At a local hospital, 35 babies were born.

There are 23 were boys.

Then,

The percentage of the newborns were boys is determined by,

$\rm Percentage \ of \ new \ born \ boys = (Total \ number\ of \ boys * 100)/(Total \ number \ of \ babies)$

Substitute all the values in the formula.

$\rm Percentage \ of \ new \ born \ boys = (Total \ number\ of \ boys * 100)/(Total \ number \ of \ babies)\n\n\rm Percentage \ of \ new \ born \ boys = (23 * 100)/(35)\n\n\rm Percentage \ of \ new \ born \ boys = (2300)/(35)\n\n\rm Percentage \ of \ new \ born \ boys = 65.71 \ percent$

Hence, the percentage of newborns who were boys is 65.71%.

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so the fraction would be 23/35 are boys. If you do the division (23 ÷ 35) the answer is around 0.657.

That converted into a percentage (×100) is 65.7%

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