if n represents a number, write an expression for the quantity three less than twice this number divided by the quantity 7 more than the square of this number .

Answers

Answer 1
Answer:

The mathematical expression will be (2n / n² + 7) - 3.

What is an expression?

The mathematical expression is the combination of numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also be used to denote the logical syntax's operation order and other properties.

Given that the quantity three is less than twice this number divided by the quantity 7 more than the square of this number.

The required expression will be written as:-

E=  (2n / n² + 7) - 3.

Therefore, the mathematical expression will be (2n / n² + 7) - 3.

To know more about an expression follow

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Determine two pairs of polar coordinates for the point (5, 5) with 0Á _ _ < 360Á

Answers

the polar coordinates are given by  M(x, y), such tha x=rcos(teta), and y=rsin(teta), it was given M(5,5), so 5=rcos(teta) and 5=rsin(teta), the ratio gives us 5/5= cotan (teta), 1= cotan (teta), implies 1= tan(teta), so teta = Pi/4, let's find r
5=rsin(Pi/4)=r . sqrt(2)/2, so r =10/sqrt(2)=10sqrt(2)
finally the polar coordinates are (r, teta) = (10sqrt(2), Pi/4)

Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas? (2 points)Select one:
a. Al
b. Bi
c. Na
d. Fe

Answers

I think the correct answer from the choices listed above is option C. It is the metal Na that will react with water to produce a metal hydroxide and hydrogen gas. It reacts violently with water forming sodium hydroxide and the hydrogen gas.

For 100​ births, P(exactly 55 ​girls)equals0.0485 and ​P(55 or more ​girls)equals0.184. Is 55 girls in 100 births a significantly high number of​ girls? Which probability is relevant to answering that​ question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less

Answers

Answer: 55 can not be considered a significantly high number of girls.

The probability is relevant to answering that​ question = \text{P(55 or more girls)}=0.184.

Step-by-step explanation:

Given : For 100​ births, \text{P(exactly 55 girls)}=0.0485

and \text{P(55 or more girls)}=0.184.

Also it is said that consider a number of girls to be significantly high if the appropriate probability is 0.05 or less

To check :- If 55 girls in 100 births a significantly high number of​ girls .

We can see that \text{P(exactly 55 girls)}=0.0485<0.05

and \text{P(55 or more girls)}=0.184>0.05 , it means it is likely to occur 55 or more girls .

So 55 can not be considered a significantly high number of girls.

Please help me with these 3 problems ASAP.

Answers

Answer:

For the first question(B)

x=-2

x=5

For part C, the question is not clear

For the last question, the approximated value is -5/4

Which equation is true?9x2 – 25 = (3x – 5)(3x – 5)
9x2 – 25 = (3x – 5)(3x + 5)
9x2 – 25 = –(3x + 5)(3x + 5)
9x2 – 25 = –(3x + 5)(3x – 5)

Answers

Answer : 9x^2 - 25 = (3x - 5)(3x + 5)

(1) 9x^2 - 25 = (3x - 5)(3x - 5)

Use FOIL method to mulitply (3x – 5)(3x – 5)

(3x - 5)(3x - 5) = 9x^2 - 30x + 25

(2) 9x^2 - 25 = (3x - 5)(3x + 5)

Use FOIL method to mulitply (3x - 5)(3x + 5)

(3x - 5)(3x - 5) = 9x^2 - 15x + 15x - 25 = 9x^2 - 25

(3) 9x^2 - 25 = -(3x + 5)(3x + 5)

Use FOIL method to mulitply -(3x + 5)(3x + 5)

-(3x + 5)(3x + 5) = -(9x^2 + 30x + 25) = -9x^2 -30x -25

(4) 9x^2 - 25 = -(3x + 5)(3x - 5)

Use FOIL method to mulitply -(3x + 5)(3x - 5)

-(3x + 5)(3x - 5) = -(9x^2 - 25) = -9x^2 + 25

So equation 2 is true

Hello,

Answer B


But this is not an equation!!!!! (only an expression)

Solve by multiplication and addition. Show each step of your work. 4x – 3y = 11
3x + y = 18

Answers

basically eliminate
try eliminate y's
multiply second equaiton by 3
9x+3y=54

add to other equation
4x-3y=11
9x+3y=54 +
13x+0y=65


13x=65
divide 13 both sides
x=5

sub back
3x+y=18
3*5+y=18
15+y=18
minus 15
y=3

x=5
y=3
(5,3)