MATHEMATICS HIGH SCHOOL

Priya drew a triangle with the side lengths 3, 4, 5. She wants to draw a triangle that is a SMALLER scaled copy. Which of the following are scale factors she could use to make the triangle smaller?

Answers

Answer 1

Answer:

scale factors she could use to make the triangle smaller is $(1)/(2)$

Given :

Priya drew a triangle with the side lengths 3, 4, 5

Given options are :

1.) 1/2

2.) 1

3.) 2

4.) 6

Explanation :

The ratio of the measurement of the corresponding sides of a triangle is a scale factor .

When we multiply the side length by a scale factor >1 that gives a bigger scaled copy

When we multiply the side length by a scale factor <1 that gives a smaller scaled copy

From the given options , scale factor 1/2 is less than 1

So 1/2 is the scale factor that could use to make the triangle smaller

Learn more :

brainly.com/question/17819925

Answer 2

Answer:

Answer:

She could make the triangle smaller by making the same triangle but smaller and add the same sides to the small triangle.

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Which function is odd? Check all that apply.A. y = sec x
B. y = sin x
C. y = cot x
D. y = csc x

Answers

To know if the function is odd or even, we have to substitute x with -x. If the function remains positive, that would mean the function is even. If the function is negative then the function is odd.

A. y = sec(x) is also equal to 1/cos(x). Substitute x with -x
1/cos(-x) =1/cos(x) = sec(x) = y (EVEN)

B. y = sin(x) Substitute x with -x
sin(-x) = -sin(x) = -y (ODD)

C. y= cot(x) is also equivalent to cos(x)/sin(x) Substitute x with -x
cos(-x) / sin(-x) = cos(x)/ (-sin (x)) = - cot(x) = -y (ODD)

D. y = csc(x) is also equivalent to 1 / sin(x) Substitute x with -x
1/ sin(-x) = 1/ (-sin (x))=-csc(x) =-y (ODD) ----------> odd

Answer: y= cos x

y=sec x

Step-by-step explanation:

Negative one plus negative four

Answers

Answer:

-5

Step-by-step explanation:

-4+(-1) A negative number added by another negative number will stay negative.( like a positive number by a positive will be positive.)

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?

Answers

The equation of line passes through points $\left({ - \,4, - \,3}\right)$ and $\left({12,1}\right)$ in standard form is $\boxed{{\mathbf{x - 4y = 8 }}}$ .

Further explanation:

It is given that a line passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ .

The slope of a line passes through points $\left({{x_1},{y_1}}\right)$ and $\left({{x_2},{y_2}}\right)$ is calculated as follows:

$m=\frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}{\text{ }}$ ......(1)

Here, the slope of a line is denoted as and points are $\left({{x_1},{y_1}}\right)$ and $\left({{x_2},{y_2}}\right)$ .

Substitute for ${x_1}$ , $-3$ for ${y_1}$ , $12$ for ${x_2}$ and $1$ for ${y_2}$ in equation (1) to obtain the slope of a line that passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ .

$\begin{aligned}m&=\frac{{1 - \left({ - 3}\right)}}{{12 - \left({ - 4}\right)}}\n&=\frac{{1 + 3}}{{12 + 4}}\n&=\frac{4}{{16}}\n&=(1)/(4)\n\end{aligned}$

Therefore, the slope is $(1)/(4)$ .

The point-slope form of the equation of a line with slope $m$ passes through point $\left({{x_1},{y_1}}\right)$ is represented as follows:

$y - {y_1}=m\left({x - {x_1}}\right){\text{}}$ ......(2)

Substitute for ${x_1}$ , $1$ for ${y_1}$ and $(1)/(4)$ for $m$ in equation (2) to obtain the equation of line.

$\begin{aligned}y - 1&=(1)/(4)\left({x - 12}\right)\n4\left({y - 1}\right)&=x - 12\n4y - 4&=x - 12\nx - 4y&=8\n\end{aligned}$

Therefore the standard equation of line that passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ is $x - 4y = 8$ .

Thus, theequation of line passes through points $\left({ - 4, - 3}\right)$ and $\left({12,1}\right)$ in standard form is $\boxed{{\mathbf{x - 4y = 8 }}}$

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3. What are the values of x?brainly.com/question/2093003

Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords:Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics,equation of line, line, passes through point

I don’t understand how to do this. Someone please help me understand how to determine the solutions using the zero product property.

Answers

Set each pair of parentheses to zero. Solve them as separate equations.

What is the elapsed time between 2:16 AM and 8:10 PM

Answers

So we wan't to know how much time has passed from 2:16 AM till 8:10 PM. If we know that one day has 24 hours and that AM and PM are two 12 hour periods we can say the following: 2:16 AM is 2:16 h in the 24 hour cycle. and 8:10 PM is 20:10 h in the 24 hour cycle. so from 2:16 hours to 20:10 hours there is a time interval of 17 hours and 54 minutes.

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(15−x)∙4=10
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Answers

(15-12.5)*4=10

x=12.5

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