What is the [h3o ] in a buffer that consists of 0.30 m hcooh and 0.20 m hcoona? ka = 1.7 × 10-4 i just need the steps to do it, not the answer ?
Answers
The concentration of H₃O⁺ in a buffer system formed by 0.30 M HCOOH and 0.20 M HCOONa is 2.5 × 10⁻⁴ M.
We have a buffer system formed by 0.30 M HCOOH and 0.20 M HCOONa.
We can calculate the pH of the buffer using Henderson-Hasselbach's equation.
Given the pH is 3.6, we can calculate the concentration of H₃O⁺ using the following expression.
The concentration of H₃O⁺ in a buffer system formed by 0.30 M HCOOH and 0.20 M HCOONa is 2.5 × 10⁻⁴ M.
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Given:
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100.0oC is cooled to 82.0 °C
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This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
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hope that's right and hope i helped
This reaction occurs more quickly when powdered iron is used instead of a single piece of iron of the same mass because the powdered iron
(1) acts as a better catalyst than the single piece of iron
(2) absorbs less energy than the single piece of iron
(3) has a greater surface area than the single piece of iron
(4) is more metallic than the single piece of iron
Answers
Answer: Option (3) is the correct answer.
Explanation:
One of the important factor on which rate of reaction depends is surface area. That is, when a compound is crushed into powdered form then there will be increase in surface area of the compound.
Hence, now more number of particles can interact, therefore, there will be increase in rate of reaction.
Thus, we can conclude that reaction occurs more quickly when powdered iron is used instead of a single piece of iron of the same mass because the powdered iron has a greater surface area than the single piece of iron.