A potassium ion (K+) would most likely bond with _____.

Mg+
O
Cl-
Na+

Answers

Answer 1
Answer:

Answer:

Chlorine

Explanation:

Answer 2
Answer:

Answer:

That would be the negative ion:  Cl-.


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Name the following : [Ni(NH3) 4(H2O)2(NO3)2​

Answers

Any member of the family of chemicals known as coordination compounds has a core metal atom that is surrounded by nonmetal atoms or groups of atoms, known as ligands, that are connected to it by chemical bonds. The name of the compound is tetraaminodiaquanickel (II)nitrate.

The additional molecular compounds known as coordination compounds are those that are stable in both the solid and dissolved states. In these compounds, ions or molecules connected by coordinate bonds connect the main metal atom or ion.

Coordination compounds are used in both vital catalytic processes that lead to the polymerization of organic molecules like polyethylene and polypropylene as well as hydrometallurgical processes that remove metals like nickel, cobalt, and copper from their ores.

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Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:(a) V³⁺ (b) Cd²⁺ (c) Co³⁺ (d) Ag⁺

Answers

Answer and Explanation :

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

(a) V³⁺

The electronic configuration is -  

[Ar]3d^1

The electrons in 3d orbital = 1 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(b) Cd²⁺

The electronic configuration is -  

[Kr]4d^(10)

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

(c) Co³⁺

The electronic configuration is -  

[Ar]3d^6

The electrons in 3d orbital = 6 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(d) Ag⁺

The electronic configuration is -  

[Kr]4d^(10)

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

Question 1Ernest Rutherford completed his famous gold foil experiment in 1911. In this experiment, alpha particles were fired at a thin sheet of gold foil. He observed that most of the alpha particles passed straight through the gold foil unimpeded, but a small number of alpha particles were deflected. Which of the following conclusions about atomic structure were made from Rutherford’s gold foil experiment?

Answers

The conclusions drawn by Ruthford after the experiment are that most of the atom is empty and that the nucleus of the atom is positively charged.

What is the atom?´

  • It is the particular mentor of the matter.
  • It is the element that makes up matter.

After the discovery of the atom, many scientists sought to understand this element more specifically, especially in relation to its composition. These discoveries were strengthened over time, and Rutherford was the one who established how the atom really is, with a positive charge in the nucleus and an electrosphere around it.

Complete question:

Ernest Rutherford completed his famous gold foil experiment in 1911. In this experiment, alpha particles were fired at a thin sheet of gold foil. He observed that most of the alpha particles passed straight through the gold foil unimpeded, but a small number of alpha particles were deflected. Which of the following conclusions about atomic structure were made from Rutherford’s gold foil experiment?

Most of the atom is empty.

The nucleus is positively charged.

The atom is a massive sphere.

The atom is indivisible.

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Answer: gold foil. It's in the experiment's name

What is the partial pressure of nitrogen in a container that contains 3.96mol of oxygen, 7.49 mol of nitrogen and 1.19 mol of carbon dioxide when the total pressure is 563 mmHg?

Answers

Answer:

333.6 atm

Explanation:

The following data were obtained from the question:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Next, we shall determine the total number of mole in the container.

This can be obtained as follow:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total mole =?

Total mole = nO2 + nN2 + nCO2

Total mole = 3.96 + 7.49 + 1.19

Total mole = 12.64 moles

Next, we shall determine the mole fraction of N2.

This can be obtained as follow:

Mole fraction = mole of substance/total mole

Mole of N2 (nN2) = 7.49 moles

Total mole = 12.64 moles

Mole fraction of N2 =?

Mole fraction of N2 = 7.49/12.64

Finally, we shall determine the partial pressure of N2.

This can be obtained as follow:

Mole fraction of N2 = 7.49/12.64

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Partial pressure = mole fraction x total pressure

Partial pressure of N2 = 7.49/12.64 x 563

Partial pressure of N2 = 333.6 atm

The, the partial pressure of nitrogen, N2 is 333.6 atm

Calculate the pH of the solution formed when 45.0 mL of 0.100M NaOH solution is added to 50.0 mL of 0.100M CH3COOH (Ka for acetic acid = 1.8 x10-5 ).

Answers

The study of chemicals and bonds is called chemistry. There are two types of elements are there and these rare metals and nonmetals.

The correct answer is 5.59.

What is PH?

  • pH, historically denoting "potential of hydrogen" is a scale used to specify the acidity or basicity of an aqueous solution.
  • Acidic solutions are measured to have lower pH values than basic or alkaline solutions

The pH of the solution will be due to excessive acid left and the salt formed. Thus, it will form a buffer solution.

The pH of buffer solution is calculated from Henderson Hassalbalch's equation, which is:

pH= pka+log(salt)/(acid)

pka= -log(ka)

pka =-log(1.8*10^(-5)

The moles of acid are taken as:-

moles = M*V

0.5*50=5

The moles of the base are taken as:-

moles = M*V

0.1*45=4.5


moles of acid left is 0.5

Place all the values to the equation:-

pH=4.74+log(4.5)/(0.5) \n=5.69

Hence, the correct answer is 5.69.

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Answer:

pH of soltion will be 5.69

Explanation:

The pH of the solution will be due to excessive acid left and the salt formed. Thus, it will form a buffer solution.

The pH of buffer solution is calculated from Henderson Hassalbalch's equation, which is:

pH=pKa+log(([salt])/([acid]) )

pKa=-log(Ka)

pKa=-log(1.8X10^(-5))=4.74

The moles of acid taken :

moles=molarityXvolume=0.1X50=5mmol

The moles of base taken:

moles=molarityXvolume=0.1X45=4.5mmol

The moles of acid left after reaction :

5-4.5=05mmol

The moles of salt formed = 4.5mmol

Putting values in equation

pH=pKa+log(([salt])/([acid]) )=4.74+log((4.5)/(0.5))=5.69

Question 51 pts A breathalyzer is a device used to estimate the blood alcohol content of a suspected drunk driver by measuring the amount of alcohol in one's breath. The fuel cell breathalyzer employs the reaction below: CH3CH2OH(g)+O2(g)→HC2H3O2(g)+H2O(g) When a suspected drunk driver blows his or her breath through the fuel-cell breathalyzer, the device measures the current produced by the reaction and calculates the percent alcohol in the breath. How many moles of electrons are transferred per mole of ethanol, CH3CH2OH, in the reaction?

Answers

Answer:

Four moles of electrons

Explanation:

The reactions in a breathalyzer are redox reactions. Fuel cell breathalyzers consists of fuel cells with platinum electrodes. The current produced depends on the amount of alcohol in the breath. Detection of alcohol involves the oxidation of ethanol to ethanoic acid. The two half cells set in the process are;

Anode;

C2H5OH(aq) + 4OH^-(aq) ----------> CH3COOOH(aq) + 3H2O(l) + 4e

Cathode;

O2(g) + 2H2O(l) +4e--------> 4OH^-(aq)

Hence four electrons are transferred in the process.