MATHEMATICS HIGH SCHOOL

H(n)=2n-5
Find h(-5)

Answers

Answer 1

Answer:

Answer: h(-5) = -15

Step-by-step explanation:

h(-5)= 2(-5) -5

h(-5)= -10-5

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Your mortgage is $135,400.00 at a 5.25% APR. If you pay $1,500.00 towards the mortgage each month, how much of your second month's payment is applied to the principal?

Answers

in the 1st month, the accrued interest is ___ (1/12) * .0525 * 135400

subtract the interest from the payment to find the change in the principal for the 2nd month

find the 2nd month's interest and subtract from the payment to find the amount applied to principal

Answer:

Correct answer D. $707.50

Step-by-step explanation:

I just took the test

What are two addition equations that each have a sum of -21.5?

Answers

Final answer:

Two example addition equations resulting in -21.5 could be -10.75 + -10.75 = -21.5 and -30 + 8.5 = -21.5. These illustrate the addition of negative and positive numbers to achieve a negative sum.

Explanation:

Two addition equations that each have a sum of -21.5 could be as follows:

Equation 1:-10.75 + -10.75 = -21.5

In this equation, we're adding two identical numbers (-10.75 and -10.75), which together give us a sum of -21.5.

Equation 2:-30 + 8.5 = -21.5

In this equation, we're adding -30 and 8.5, which together also give us a sum of -21.5. In both cases, we're practicing addition of negative and positive numbers to get a negative sum.

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Answer:

-21.5 + 0

-22.5 - 1

Step-by-step explanation:

lol

there are 94 suitcases in number one cargo bin. there are two cargo bins to be loaded on the airplane. the second bin contains 214 suitcases and the third 103 suitcases. if all three of these cargo bins are loaded onto the 747 airplane,how many total suitcases will be in the cargo area?

Answers

isnt it simple addition? i'm aint sure because i'm french but if i understand well, it suppose to be 411

Final answer:

The total suitcases in all three cargo bins, when added up (94 + 214 + 103), equals 411. Consequently, there will be 411 suitcases in the cargo area of the 747 airplane.

Explanation:

Total suitcase calculation involves simply adding up the numbers from all three cargo bins. The first bin contains

94 suitcases, the second bin 214 suitcases, and the third contains 103 suitcases. Adding all these up gives a total suitcase number as follows: 94 + 214 + 103 = 411. Therefore, if all these cargo bins are loaded onto the 747 airplane, here will be 411 suitcases in the cargo area.

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The difference between the highest and lowest single game point totals for the MIDDLE HALF of the data is ______ points less for Joe's data than Sam's data. Therefore, the MIDDLE HALF of Joe's single game point totals are less varied than Sam's.

Answers

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required data to answer the question are missing.

However, the interpretation of the question is to determine the interquartile range (IQR) of a certain dataset.

Then get the difference between the calculated IQR & Joe's data and also the difference between the calculated IQR & Sam's data

Then, make comparison

To do this, I will use the following assumed datasets.

$Data: 62, 63, 64, 64, 70, 72, 76, 77, 81, 81$

IQR is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is $the\ median$ of the upper half

$Q_1$ is $the\ median$ of the lower half

For Joe, we have:

$Lower\ half: 62, 63, 64, 64, 70$

$Upper\ half: 72, 76, 77, 81, 81$

The median is then calculated as:

$M = (N + 1)/(2)$

For, the lower half:

$Q_1 = (5 + 1)/(2) = (6)/(2) = 3rd$

So:

$Q_1 = 64$

For the upper half:

$Q_3 = (5 + 1)/(2) = (6)/(2) = 3rd$

So:

$Q_3 = 77$

When the same process is applied to Sam's data,

$Q_1 = 52$

$Q_3 = 58$

$IQR = Q_3 - Q_1$

$IQR = 77 - 64$

$IQR = 13$

Assume that:

$Joe = 60$

$Sam = 65$

$Joe - IQR = 60 - 13 = 47$

$Sam- IQR = 65- 13 = 52$

Hence, the IQR is 47 points less for Joe's data than Sam's

Donna's company reimburses her expenses on food, lodging, and conveyance during business trips. The company pays $50 a day for food and lodging and $0.60 for each mile traveled. Donna drove 200 miles and was reimbursed $1,620. Part A: Create an equation that will determine the number of days on the trip. (3 points) Part B: Solve this equation justifying each step with an algebraic property of equality. (6 points) Part C: How many days did Donna spend on this trip? (1 point)

Answers

Answer:

See below

Step-by-step explanation:

Part A

Let number of days be d, then the equation is:

50d + 200*0.6 = 1620

Part B

Solution of the equation

50d + 120 = 1620
50d + 120 - 120 = 1620 - 120 ⇒ subtraction property of equality
50d = 1500
50d / 50 = 1500/50 ⇒ division property of equality
d = 30

Part C

30 days as above

A MAN walked for 1/3 hour and then got an automobile ride for 1/2 hour. what part of time consumed he ride on automobile ????(a) 1/3
(b) 3/5
(c) 5/6

Answers

Walk - $(1)/(3) h$
Ride - $(1)/(2)h$
Journey took $(1)/(3)+(1)/(2) = (2+3)/(6) = (5)/(6) h$ = 50 minutes
and $(1)/(2)$ it's a $(3)/(5)$ of time

answer B

Final answer:

To find the part of time consumed riding the automobile, subtract the time spent walking from the total time. The correct answer is 5/9 hour.

Explanation:

To find the part of time consumed riding the automobile, we need to compare the time spent walking to the total time. The total time is 1/3 hour + 1/2 hour, which is equal to 5/6 hour. To find the part of time consumed riding, we subtract the time spent walking from the total time. So, the part of time consumed riding the automobile is 5/6 hour - 1/3 hour, which is equal to 10/18 hour. Simplifying this fraction, we get 5/9 hour. Therefore, the correct answer is (c) 5/9.