MATHEMATICS COLLEGE

PLS HELPPP ITS NOT THAT HARD

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

1. System A is consistent and independent and unique solution

2. System B: inconsistent and no solutions

3. System C: consistent and dependent and infinite many solutions

Related Questions

Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the following exercise. Find the following sums without using a calculator or a formula. Hint: Apply the procedure used by Gauss. (See the Math Matters on page 31.) (a) 1 + 2 + 3 + 4 + . . . + 397 + 398 + 399 + 400 (b) 1 + 2 + 3 + 4 + . . . + 542 + 543 + 544 + 545 (c) 2 + 4 + 6 + 8 + . . . + 72 + 74 + 76 + 78
482 – 412 + 286 - 12 x 204solve
Kalvin sells bottles of water at baseball games he pays 0.75 per bottle and 3.78 for the ice to keep cold let b represent the number of bottles of water he buys c represent his total cost
Given: JK tangent, KH=16, HE=12 Find: JK.
6.Valdez Construction signed a note with a payment of $5,200 per quarter for 5 years.Find the amount they must set aside today to satisfy this capital requirement in an account earning 8% compounded quarterly.$30,506.32$126,346.32$51,054.38$85,027.44

Helen rolls a dice and flips a coin.Calculate the probability that she gets a 4 and a tail.

Answers

Answer:

1/12

Step-by-step explanation:

Probability of 4 = 1/6

Probability tail = 1/2

Multiply them

Answer:

1/12

Step-by-step explanation:

Probability of 4 = 1/6

Probability tail = 1/2

1/6 x 1/2 = 1/12

Consider the following information about travelers on vacation: 40% check work email, 30% use a cell phone to stay connected to work, 25% bring a laptop with them, 23% both check work email and use a cell phone to stay connected, and 50% neither check work email nor use a cell phone to stay connected nor bring a laptop. In addition, 84 out of every 100 who bring a laptop also check work email, and 70 out of every 100 who use a cell phone to stay connected also bring a laptop. (a) What is the probability that a randomly selected traveler who checks work email also uses a cell phone to stay connected? (b) What is the probability that someone who brings a laptop on vacation also uses a cell phone to stay connected? (c) If the randomly selected traveler checked work email and brought a laptop, what is the probability that he/she uses a cell phone to stay connected? (Round your answer to four decimal places.)

Answers

The probability that a randomly selected traveller who checks work email also uses a cell phone to stay connected is 57.5%.

The probability that someone who brings a laptop on vacation also uses a cell phone to stay connected is 70%.

If the randomly selected traveller checked their work email and brought a laptop, the probability that he/she uses a cell phone to stay connected is 58.8%.

We have,

Let:

C = Check work email

P = Use a cell phone to stay connected

L = Bring a laptop

Given information:

P(C) = 0.40 (Probability of checking work email)

P(P) = 0.30 (Probability of using a cell phone to stay connected)

P(L) = 0.25 (Probability of bringing a laptop)

P(C ∩ P) = 0.23 (Probability of both checking work email and using a cell phone to stay connected)

P(Neither) = 0.50 (Probability of neither checking work email, using a cell phone to stay connected, nor bringing a laptop)

Additional information:

P(C | L) = 0.84 (Probability of checking work email given that a laptop is brought)

P(P | L) = 0.70 (Probability of using a cell phone to stay connected given that a laptop is brought)

a. For the value of P(P | C), use the conditional probability formula:

P(P | C) = P(C ∩ P) / P(C)

P(P | C) = 0.23 / 0.40

P(P | C) = 0.575

b. For the value of P(P | L), use the conditional probability formula:

P(P | L) = P(P ∩ L) / P(L)

P (P | L) = 0.70

c. For the value of P(P | C ∩ L), use the conditional probability formula:

P(P | C ∩ L) = P(C ∩ P ∩ L) / P(C ∩ L)

Since we don't have the direct probability of P(C ∩ P ∩ L), we can use the information provided:

P(C | L) = 0.84

P(P | C ∩ L) = P(C | L) × P(P | L)

P(P | C ∩ L) = 0.84 × 0.70

P(P | C ∩ L) = 0.588

Thus, The probability that a randomly selected traveller who checks work email also uses a cell phone to stay connected is 57.5%.

The probability that someone who brings a laptop on vacation also uses a cell phone to stay connected is 70%.

If the randomly selected traveller checked their work email and brought a laptop, the probability that he/she uses a cell phone to stay connected is 58.8%.

Learn more about probability here:

brainly.com/question/14099682

#SPJ12

2 x 6
Pls I’m 9 years old plsssssssssssss

Answers

It is 12. I hope it helps!! :)

A Triangle has an angle that measures 137.3 degrees. The other two angles are in a ratio of 3:4. What are the measures of those two angles?

Answers

so we start off by subtracting 137.3 from 180 getting 42.5. If you add the ratios up (3+4) you get 7 and 7 should equal 42.5. thus,

42.5/7= 85/14

(85/14)*3=18.2 or (255/14 to be exact)
(85/14)*4= 24.29 or (170/7 to be exact)

the cube of the sum of 4 and 9 times x divided by the product of 5 times x and the difference of x and 1