Find the 30th term of the following sequence.2, 8, 14, 20, ...

174
176
180
182
Can someone please help me?

Answers

Answer 1

Answer: Hello,

$u_(1) =2\n u_(2) =2+6\n u_(3) =2+2*6\n u_(4) =2+3*6\n...\n u_(n) =2+(n-1)**6\n u_(30) =2+29*6=176\n$

Answer B

Answer 2

Answer: So first u have to find the nth term, here the nth term is : 6n-4
Then replace the n with term that u want so:
6(30) - 4
= 180-4
=176
So it's B

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Explain how to do the factor tree for 75

Answers

separate 75 into two numbers. Lets use 15 and 5. 15 can be reduced into 3 and 5, while 5 cannot be reduced. The remaining numbers you have will be 5, 5, and 3.

75
/ \
15 5
/ \
3 5

Like this- . 75 . /. \. . 25. 3 . /. \. . 5. 5. So the factors are- 3x5x5. Hope I helped!

Can someone please explain how I would figure this out

Answers

[1], [3] => a = 49,000/2 = 24,500 => b +c = 24,500 => c = 24,500 - b;
[2] => 25*24,500 + 20b + 15c = 1,052,000 => 20b + 15c = 1,027,500;
20b + 15*(24,500 - b) = 1,027,500 => 5b = 733,500 => b = 146,700 =>
c = - 122,200;

Which expressions are completely factored?Choose all answers that are correct.

Question 4 options:

18x^4 – 12x^2 = 6x(3x^3 – 2x)

12x^5 + 8x^3 = 2x^3(6x^2 + 4)

20x^3 + 12x^2 = 4x^2(5x + 3)

24x^6 – 18x^5 = 6x^5(4x – 3)

Answers

Hello

1)False 18x^4-12x²=6x(3x^3-2x)=6x²(3x²-2)

2) False 12x^5+8x^3=2x^3(6x²+4)=4x^3(3x²+2)

3)True 20x^3+12x²=4x²(5x+3)

4)True 24x^6-18x^5=6x^5(4x-3)

4)

The value of a car depreciates by 18% per year. Work out the current value of a car bought 4 years ago for £20000

Answers

Given:
depreciation rate: 18%
Value of the car : 20,000
Age of the car : 4 years.

The depreciation is based on the current value of the car. Therefore, the amount of depreciation varies.

yr Beginning Value Dep. Rate Depreciation Ending Value
1   20,000.00   18% 3,600.00 16,400.00
2   16,400.00   18%      2,952.00    13,448.00
3   13,448.00   18% 2,420.64 11,027.36
4   11,027.36   18% 1,984.92 9,042.44

The current value of a car bought 4 years ago is 9,042.44

Beginning value : purchased amount on 1st year. then, ending balance of the previous year from 2nd year onwards.
Depreciation : Beginning value * depreciation rate
Ending value : Beginning value - depreciation

20000 = 100%18 x 4 = 72%20000 / 100 = 200200 = 1%200 x 72 = 14,40020000 - 14,400 = 5600The value of it now should be £5600

Quadrilateral A’B’C’D’ is the image of quadrilateral ABCD under a translation.A translation by ____ units to the _right/left_ and ____ units _up/down_.