MATHEMATICS HIGH SCHOOL

IMPORTANT PLEASE I NEED NOW:Find the area of each face of the cube whose volume is 729 cm

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

square root of 729= 9

9×9=81

Answer 2

Answer:

Answer:

Step-by-step explanation:

Formula of Volume= $a^(3)$ - a = side

Therefore since the volume is given you just need to find the side.

729= $a^(3)$ = $\sqrt[3]{729}$ = a

= 9 = a

Now you know that 9 is the side, so using that find the area of one face-

Area of a square= 9 x 9 = 81 $cm^(2)$

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A country's population in 1993 was 72 million. In 1996 it was 76 million. Estimate the population in 2003 using exponential growth.

Answers

We use the formula for exponential growth:
P = Po exp(kt)
Using the population data from 1993 to 1996, we can solve for the growth rate k
76 = 72 exp(k(3))
76/72 = exp(3k)
ln (76/72) = 3k
k = ln(76/72) / 3 = 0.0180

In 10 years (2003), the population will be:
P = Po exp(0.0180t)
P = 72 exp(0.0180(10))
P = 86.22 million

Hagrid is correct but its asking to the nearest million so it's 86 mill so just type in 86 then press enter

What is the unit rate of 2,16 and 4,32

Answers

Answer:

( 1/2 0.5 mph )

Step-by-step explanation:

In a unit rate, the denominator is always 1. So, to find unit rate, divide the denominator with the numerator in a way that the denominator becomes 1.

The path of a roller coaster after it has reached the top of the first hill follows a polynomial function as shown in the graph below....

Answers

The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.

Hello there.

The path of a roller coaster after it has reached the top of the first hill follows a polynomial function as shown in the graph below....

Option A

(−2x0y3 )(4x2y4 )+(2y5 )(3xy)2

Answers

$(-2*x^0*y^3)*(4x^2y^4)+(2y^5)*(3xy)^2$

$-2*y^3*4x^2*y^4+2y^5*9*x^2*y^2$

$-2*y^3*4*x^2*y^4+2*y^5*9x^2y^2$

$-8x^2y^7+18*x^2*y^7$

therefore

$\boxed{\boxed{10*x^2*y^7}}$

Step-by-step explanation:

Answered

(-2*x^0*y^3)*(4x^2y^4)+(2y^5)*(3xy)^2

-2*y^3*4x^2*y^4+2y^5*9*x^2*y^2

-2*y^3*4*x^2*y^4+2*y^5*9x^2y^2

-8x^2y^7+18*x^2*y^7

therefore

\boxed{\boxed{10*x^2*y^7}}

What is the perimeter of a rectangle 33 sq m by 3 m

Answers

The answer is 72 because the permeter is 33 by 3 so you multiply 33 and 3 by 2 and add them up
66+6=72

What is the relationship between the sine and cosine of complementary angles? Please give an example to support your answer.

Answers

The sine of any acute angle is equal to the cosine of its complement. Meanwhile, the cosine of any acute angle is equal to the sine of its complement. Sine and cosines are called "cofunctions".

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