An element with a mass of 570 grams decays by 26.7% per minute. To the nearest minute, how long will it be until there are 40 grams of the element remaining?

Answers

Answer 1
Answer:

Answer: x ≈ 9

Step-by-step explanation:

Near the end of the picture 8.553364=x

x ≈ 9


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Write the four equivalent fraction of 9/13​

Answers

Step-by-step explanation:

18/26

27/39

36/52

45/65

An equivalent fraction for a/b is found by multiplying the numerator and denominator by a common integer (n)

Will wanted to track the growth of various fruits in his garden, so he decided to label them. His garden had APPLES labeled 1,2,3,4,5,6, LEMONS labeled 1,2, and MELONS labeled 1,2,3. If a single fruit is picked at random, what is the probability that the fruit is an APPLE or has an EVEN number?

Answers

Using the probability concept, it is found that there is a 0.7273 = 72.73% probability that the fruit is an APPLE or has an EVEN number.

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

  • There are 11 options, hence T = 11.
  • Of those, there are 6 options which land on Apple, plus 2 options which does not land on apple but have an even number, hence D = 6 + 2 = 8

Then, the probability is:

p = (D)/(T) = (8)/(11) = 0.7273

0.7273 = 72.73% probability that the fruit is an APPLE or has an EVEN number.

A similar problem involving the probability concept is given at brainly.com/question/15536019

Answer:

8 in 11 or 0.7272

Step-by-step explanation:

Between 6 apples. 2 lemons and 3 melons, Will has a total of 11 fruits in his garden. There are three apples labeled with even numbers (2,4 and 6), one melon (2) and one lemon (2), for a total of five fruits.

The probability that a randomly selected fruit is an APPLE or has an EVEN number is given by the probability that it is an apple, P(A), added to the probability that it is even, P(E), minus the probability that it is an even apple, P(A and E):

P(A\ or\ E) = P(A) +P(E) - P(A\ and\ E)\nP(A\ or\ E) = (6)/(11)+(5)/(11)-(3)/(11) \nP(A\ or\ E) = 0.7272

There is a 8 in 11, or a 0.7272 chance that the fruit is an APPLE or has an EVEN number.

Which point represents the intersection of given lines AE and DE

Answers

I am pretty sure it is "E" because both lines AE and De share point e.

Answer:

Hey! the answer is e

Step-by-step explanation:

If you were to draw two lines intercepting each other, one point would be the same, right?

Here there is line AE, and line DE. The repeated point is E, which means it's the intersection.

I can't add visuals at the moment, but imagine like an x, a being on one end, d on the other, and e in the middle.

Hope this helps!

You want to create an 80% confidence interval for the average age of people who attend U of O football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. Do not round your answer. Write your answer in decimal form, not as a fraction or percent.

Answers

Answer:

80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].

Step-by-step explanation:

We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.

So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;

          P.Q. = (\bar X - \mu)/((s)/(√(n) ) ) ~ t_n_-_1

where, \mu = sample average age = 43.7 years old

            \sigma = sample standard deviation = 7 years

            n = sample of attendees = 100

            \mu = population average age of people

So, 80% confidence interval for the average age of people, \mu is ;

P(-1.2915 < t_9_9 < 1.2915) = 0.80

P(-1.2915 < (\bar X - \mu)/((s)/(√(n) ) ) < 1.2915) = 0.80

P( -1.2915 * {(s)/(√(n) ) < {\bar X - \mu} < 1.2915 * {(s)/(√(n) ) ) = 0.80

P( \bar X -1.2915 * {(s)/(√(n) ) < \mu < \bar X +1.2915 * {(s)/(√(n) ) ) = 0.80

80% confidence interval for\mu = [ \bar X -1.2915 * {(s)/(√(n) ) , \bar X +1.2915 * {(s)/(√(n) ) ]

                                                 = [ 43.7 -1.2915 * {(7)/(√(100) ) , 43.7 +1.2915 * {(7)/(√(100) ) ]

                                                 = [42.795 , 44.604]

Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].

What is the solution to the equation? 8q + 4 = 20 q = 2 q = 4 q = 16 q = 24

Answers

Isolate the q. Note the equal sign. What you do to one side, you do to the other.

Subtract 4 from both sides

8q + 4 (-4) = 20 (-4)

8q = 20 - 4

8q = 16

Next, divide 8 from both sides to isolate the q

8q/8 = 16/8

q = 16/8

q = 2

q = 2 is your answer

hope this helps

What is a variable term in mathematics?

Answers

A variable is a symbol for a unknown number. It does not have a fixed number. In fact, it could be any number until you find out what it is in a equation. Or, you can never find out what it is. Yes, it is conserved a term. Hope this helped!