Earlier we analyzed the revenue earned by the junior class at East High School from their discount card fundraiser. They hada goal to earn a profit of more than $10,000 from the fundraiser.
Since the local area businesses are supporting the fundraiser, the only cost to the students is the production cost. So, the
profit from the cards is found by subtracting the total production cost from the total revenue. Each card costs $0.20 to
produce and is sold for $20.
Select the correct answer from each drop-down menu.
If the class sold c cards, the inequality that represents their profit goal is
This year's class sold 520 cards, so they
their goal because they sold more than
cards.

Answers

Answer 1
Answer:

Approximately 520 cards actually sold this year in the class, more than 505, have fulfilled their objective.

According to the question,

If the students sell c cards the,

The total revenue,

  • 20c

The total production costs,

  • 0.2c

`

The inequality of profit, or income, which is less than 10 thousand dollars represents their objective, such as:

20c-0.2c>10,000

→         19.8c>10,000

→               c > (10,000)/(19.8c)

→               c> 505.05

or,

→               c>505

The class had to sell more than 505 cards just to meet their goals.

Thus the above answer is right.

Learn more:

brainly.com/question/8846865

Answer 2
Answer:

Answer:

Sample Answer for Edmentum


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Good bless you brother I wish I can help you

At a basketball game, a vender sold a combined total of 108 sodas and hot dogs. The number of sodas sold was three times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.

Answers

Answer:

Hot dogs - 27, soda - 81

Step-by-step explanation:

Soda to Hot dog ratio = 3:1

If the total is 108, we can divide 108/4 ---> 27

now, multiply 3 and 1 by 27 and there you go!

edit: also if you don't know why I divided 108 by 4, its because you add together both sides of the ratio

What sample size, including the 20 observations in the initial study, would be necessary to have a confidence of 95.44 percent that the observed time was within 4 percent of the true value?

Answers

Completed question:

An initial time study resulted in an average observed time of 2.2 minutes per cycle, and a standard deviation of .3 minutes per cycle. The performance rating was 1.20. What sample size, including the 20 observations in the initial study, would be necessary to have a confidence of 95.44 percent that the observed time was within 4 percent of the true value?

Answer:

47

Step-by-step explanation:

When doing a statistic study, a sample of the total amount must be taken. This sample must be done randomly, and, to be successful, the sample size (n) must be determined, by:

n = ((Z_(\alpha/2)*S )/(E))^2

Where Z(α/2) is the value of the standard normal variable associated with the confidence, S is the standard deviation, and E is the precision. The confidence indicates if the study would have the same result if it would be done several times. For a confidence of 95.44, Z(α/2) = 2.

The standard deviation indicates how much of the products deviate from the ideal value, and the precision indicates how much the result can deviate from the ideal. So, if it may vary 4% of the true value (2.2), thus E = 0.04*2.2 = 0.088.

n = [(2*0.3)/0.088]²

n = 46.48

n = 47 observations.

Answer this fast and I’ll make you Brainly!!

Answers

Answer:

8.5 or 4.25 i think pretty sure its 8.5 tho

Step-by-step explanation:

The ratio of cats to dogs at the shelter is 3 to 2 if there are 15 cats at the shelter how many dogs are there

Answers

Answer:

3/2=15/x

Step-by-step explanation:

Solve that and you’ll get x, which is your answer

In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time college students who earn a​ bachelor's degree in four years or less. Find the sample size needed to estimate that percentage. Use a 0.02 margin of error and use a confidence level of 99​%. Complete parts​ (a) through​ (c) below.a. Assume that nothing is known about the percentage to be estimated.n = ________b. Assume prior studies have shown that about 55% of​ full-time students earn​ bachelor's degrees in four years or less.n = _______c. Does the added knowledge in part​ (b) have much of an effect on the sample​ size?

Answers

Answer:

(a) The sample size required is 2401.

(b) The sample size required is 2377.

(c) Yes, on increasing the proportion value the sample size decreased.

Step-by-step explanation:

The confidence interval for population proportion p is:

CI=\hat p\pm z_(\alpha/2)\sqrt{(\hatp(1-\hat p))/(n)}

The margin of error in this interval is:

MOE=z_(\alpha/2)\sqrt{(\hatp(1-\hat p))/(n)}

The information provided is:

MOE = 0.02

z_(\alpha/2)=z_(0.05/2)=z_(0.025)=1.96

(a)

Assume that the proportion value is 0.50.

Compute the value of n as follows:

MOE=z_(\alpha/2)\sqrt{(\hat p(1-\hat p))/(n)}\n0.02=1.96* \sqrt{(0.50(1-0.50))/(n)}\nn=(1.96^(2)*0.50(1-0.50))/(0.02^(2))\n=2401

Thus, the sample size required is 2401.

(b)

Given that the proportion value is 0.55.

Compute the value of n as follows:

MOE=z_(\alpha/2)\sqrt{(\hat p(1-\hat p))/(n)}\n0.02=1.96* \sqrt{(0.55(1-0.55))/(n)}\nn=(1.96^(2)*0.55(1-0.55))/(0.02^(2))\n=2376.99\n\approx2377

Thus, the sample size required is 2377.

(c)

On increasing the proportion value the sample size decreased.