O rotation of the Moon on its axis
O revolution of the Moon around Earth
O revolution of the planets around the Sun
Answer:
revolution of the planets around the Sun.
Explanation:
The revolution of the planets around the Sun is a result of the gravitational force exerted by the Sun. The Sun's gravitational pull attracts the planets, causing them to move in an elliptical orbit around it. This motion is known as the revolution of the planets around the Sun. The other options listed (rotation of the planets on their axes, rotation of the Moon on its axis, and revolution of the Moon around Earth) are also related to motion and gravity, but they are different phenomena.
The statement made by the martian when he accidentally landed on Venus was that "I didn't planet (plan) it this way".
The question simply relates to a riddle. A riddle simply means a statement, phrase, or question that has a double or veiled meaning that is put forth as a puzzle to be solved by others.
It should be noted that the statement made by the martian when he accidentally landed on Venus was that "I didn't planet (plan) it this way".
Read related link on:
Answer:
A. 45 degrees
Explanation:
A projectile travels the farthest when it is launched at an angle of 45 degrees.
The maximum range is 45 degrees, ignoring air resistance.
sin(2θ) = 1
∴ 2θ = π/2.
(2θ)/2 = (π/2)/2
θ = π/4
π/4 or 45°
Answer:
A. 45 degrees
Explanation:
Given:
V1 = 4m3
T1 = 290k
P1 = 475 kpa = 475000 Pa
V2 = 6.5m3
T2 = 277K
Required:
P
Solution:
n = PV/RT
n = (475000 Pa)(4m3) / (8.314 Pa-m3/mol-K)(290k)
n = 788 moles
P = nRT/V
P = (788 moles)(8.314 Pa-m3/mol-K)(277K)/(6.5m3)
P = 279,204 Pa or 279 kPa
Answer:
1069.38 gallons
Explanation:
Let V₀ = 1.07 × 10³ be the initial volume of the gasoline at temperature θ₁ = 52 °F. Let V₁ be the volume at θ₂ = 97 °F.
V₁ = V₀(1 + βΔθ) β = coefficient of volume expansion for gasoline = 9.6 × 10⁻⁴ °C⁻¹
Δθ = (5/9)(97°F -52°F) °C = 25 °C.
Let V₂ be its final volume when it cools to 52°F in the tank is
V₂ = V₁(1 - βΔθ) = V₀(1 + βΔθ)(1 - βΔθ) = V₀(1 - [βΔθ]²)
= 1.07 × 10³(1 - [9.6 × 10⁻⁴ °C⁻¹ × 25 °C]²)
= 1.07 × 10³(1 - [0.024]²)
= 1.07 × 10³(1 - 0.000576)
= 1.07 × 10³(0.999424)
= 1069.38 gallons
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. Using the equation for volume expansion, we can calculate this change in volume to be approximately 258 gallons.
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. We can use the equation for volume expansion to calculate this change in volume:
ΔV = V₀ * β * ΔT
Where ΔV is the change in volume, V₀ is the initial volume, β is the coefficient of volume expansion, and ΔT is the change in temperature.
In this case, the initial volume V₀ is 1.07 * 10³ gallons, the coefficient of volume expansion β is 9.6 * 10⁻⁴ (°C)⁻¹, and the change in temperature ΔT is (52.0°F - 97.0°F) = -45.0°F.
Converting the change in temperature to Celsius: ΔT = (45.0°F) * (5/9) = -25.0°C.
Plugging in these values into the equation, we get:
ΔV = 1.07 * 10³ * 9.6 * 10⁻⁴ * -25.0 = -258 gallons.
Therefore, when the gasoline is poured into the tank, approximately 258 gallons will be poured out of the truck.
#SPJ3