MATHEMATICS HIGH SCHOOL

While hiking, Grace went up 647 meters above sea level. At the same time, her friend was scuba diving 293meters below sea level. How far apart were they in elevation?
___ meters

Answers

Answer 1

Answer:

Answer:

940 meters apart

Step-by-step explanation:

Step 1:

Grace = + 647

Friend = - 293

Step 2:

| 647 + ( - 293 ) |

Answer:

940

Hope This Helps :)

Answer 2

Answer:

Answer:

940 m

Step-by-step explanation:

Above sea level is measured as positive and below sea level is measured as negative.

In order to find the distance between both we need to find the difference between their elevation and depression.

Distance between Grace and her friend

= 647 - (-293)

= 647 + 293

= 940 m

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What is the mode of the following data values?87, 29, 21, 52, 21

A. 42
B. 31
C. 21
D. 29

Answers

the mode of the following data values would be 21.
mode is usually a number that is repeated more than once, and in this case, 21 appears twice.
your answer is c

Your answer is 21.

Hope this helps.

The graph shows the value of an investment after x years. the initial amount of the investment is $___ , the investment grows at the rate of ___% each year, and the value of the investment after 10 years is $___
NEED HELP!!! I WILL GIVE POINTS IF HELP IS GIVEN!!

Answers

Answer:

$500
6%
$895.42

Step-by-step explanation:

The graph shows the value of an investment after x years.

The initial amount of the investment is $500, the investment grows at the rate of 6% each year, and the value of the investment after 10 years is $895.42

0.083 repeding as a percentage?

Answers

0.083 as a percentage would be 8.3% with a horizontal bar on top of the three to indicate that it is repeating.

To find percentage, multiply a decimal by 100.

Hope it helps

19x – y – 2z + x + 5y + 2z

Answers

$19x - y - 2z + x + 5y + 2z \n \n (19x + x) + (-y+5y) + (-2z + 2z) \ / \ gather \ like \ terms \n \n 20x + 4y \ / \ simplify \n \n Answer: \fbox {20x + 4y}$

A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates worth 90¢ a pound. How many pounds of the $1.50 chocolate were used to make the mixture?A)15
B)10
C)12

Answers

$x-chocolate\ worth\ 1,50\$ \ per\ pound\n y-chocolate\ worth\ 0,9\$\ per\ pound\n \n\n \left \{ {{x+y=30} \atop {30*1,10=x*1,50+y*0,9}} \right.\n\n \left \{ {{x=30-y} \atop {33=1,5x+0,9y}} \right. \n\n Using \ substitution\ method:\n\n33=1,5(30-y)+0,9y\n\n 33=45-1,5y+0,9y\n\n -12=-0,6y\ |:-0,6\n\n y=20\n x=10$

Sphere A has a diameter of 2 and is dilated by a scale factor of 3 to create sphere B. What is the ratio of the volume of sphere A to sphere B?A 2:6

B 4:36

C 1:3

D 1:27

Answers

Scaled figures are zoomed in or zoomed out (or just no zoom) versions of each other. The correct option is D.

What are Scaled figures?

Scaled figures are zoomed in or zoomed out (or just no zoom) versions of each other. They have scaled versions of each other, and by scale, we mean that each of their dimension(like height, width etc linear quantities) are constant multiple of their similar figure.

So, if a side of a figure is of length L units, and that of its similarfigure is of M units, then:

$L = k * M$

where 'k' will be called a scale factor.

The linear things grow linearly like length, height etc.

The quantities which are squares or multiple linear things twice grow by the square of the scale factor. Thus, we need to multiply or divide by k²

to get each other corresponding quantities from their similar figures' quantities.

So the area of the first figure = k² × the area of the second figure

Similarly, increasing product-derived quantities will need increased power of 'k' to get the corresponding quantity. Thus, for volume, it is k cubed. or

The volume of the first figure = k³ × volume of the second figure.

It is because we will need to multiply 3 linearquantities to get volume, which results in k getting multiplied 3 times, thus, cubed.

Given that the diameter of sphere A is 2 units, it is dilated by a scale factor of 3 to create sphere B. Therefore, the diameter of sphere B is,

Diameter of sphere B = 3 × Diameter of sphere A

= 3 × 2 units

= 6 units

Now, the ratio of diameters of the sphere and the volume of the sphere can be written as,

$(\frac{\text{Diameter of sphere A}}{\text{Diameter of sphere B}})^3 = \frac{\text{Volume of sphere A}}{\text{Volume of sphere B}} \n\n\n((2)/(6))^3 = \frac{\text{Volume of sphere A}}{\text{Volume of sphere B}}\n\n\n\frac{\text{Volume of sphere A}}{\text{Volume of sphere B}} = (1)/(27)$