Why does chlorine have a higher ionization energy than aluminum

Answers

Answer 1

Answer: Hi okay so the answer to question is

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Which substance is always a product when an Arrhenius acid in an aqueous solution reacts with an Arrhenius base in an aqueous solution?(1) HBr (3) KBr(2) H2O (4) KOH
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Determine the mass 2 mol Li??

Answers

You can look on the periodic table for the number of automic mass units in each element.

1 mole Li = 6.94 amu
6.94 • 2 = 13.9 amu

There are 13.9 amu in 2 moles of Li

Molar mass Li = 6.94 g/mol

1 mol --------- 6.94 g
2 mol --------- ?

Mass Li = 2 * 6.94 / 1

Mass Li = 13.88 g

hope this helps!

Which of the following is a property of a metal? Low melting point

Permeability

Ductility

Not able to conduct heat

Answers

The correct answer is the 3rd option Ductility is a property of a metal. It is the ability of a material to deform under tensile stress.It is characterized by the ability to be stretched into wire-like form which is an ability of metals.

Electronegativity is a measure of an atoms ability to

Answers

Electronegativity is the measure for an atom to attract a bonding pair of electrons in a covalent bond.

Final answer:

Electronegativity is a measure of an atom's ability to attract electrons in a bond. It determines the distribution of shared electrons and can result in polar or nonpolar bonds.

Explanation:

Electronegativity is a measure of the tendency of an atom to attract electrons towards itself in a bond. It determines how the shared electrons are distributed between the two atoms. The more electronegative an atom is, the stronger it attracts electrons, resulting in a more polar bond.

For example, in the bond between hydrogen and chlorine (H-Cl), chlorine is more electronegative than hydrogen. Therefore, chlorine attracts the shared electrons more strongly, giving it a partial negative charge while hydrogen has a partial positive charge.

Learn more about Electronegativity here:

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Why does the temperature of heated water change when you increase the volume?

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By heating the water the temperature of 0C to 4C, one can observe a decrease in its volume. In this temperature range, there is the phenomenon of anomalous thermal expansion of water.
The volume of water in the range of 0C to 4C decreases and 4C to 100C from growing. This anomalous behavior of water is associated with the fact that liquid water a temperature slightly above 0C, there are remnants of the loose structure of the ice. The temperature increase destroys this structure, allowing denser packing of the molecules, and thus the volume of water decreases.

Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 g $CO_(2)$ and 1.3102 g $H_(2)O$ . Find the empirical formula of the compound.The answer I got was $CH_(16)O$ , but I'm not sure if I did it right or not. Can someone confirm this for me?

Answers

Answer:

The empirical formula of the compound is $C_4H_8O_1$

Explanation:

Moles of carbon dioxide = $(3.2007 g)/(44 g/mol)=0.07274 mol$

Moles of carbon in sample = $1* 0.07274 mol=0.07274 mol$

Moles of water = $(1.3101 g)/(18 g/mol)=0.07279 mol$

Moles of hydrogen in sample = $2* 0.07279 mol=0.14558 mol$

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of oxygen

Mass of oxygen =

1.3109 g - (12 g/mol × 0.07274 mol) - (1 g/mol× 0.14558 mol)

Mass of oxygen = 0.29244 g

Moles of oxygen in sample = $(0.29244 g)/(16 g/mol)=0.01828 mol$

For empirical formula divide the moles of element which are is less amount with all the moles of every element.

Carbon = $(0.07274 mol)/(0.01828 mol)=3.9\approx 4$

Hydrogen = $(0.14558 mol)/(0.01828 mol)=7.9\approx 8$

oxygen= $(0.01828 mol)/(0.01828 mol)=1$

The empirical formula of the compound is $C_4H_8O_1$

Answer:

The answer to your question is: C₃H₃O This is my answer.

Explanation:

Data

Sample = 1.3109 g

CxHyOz

CO₂ = 3.2007 g

H₂O = 1.3102 g

Empirical formula = ?

MW CO2 = 44 g

MW H2O = 18 g

For Carbon

44 g -------------------- 12 g

3.2007 g ------------ x

x = (3.2007 x 12) / 44

x = 0.8729 g of Carbon

12 g of C -------------- 1 mol

0.8729 g -------------- x

x = (0.8729 x 1) / 12

x = 0.0727 mol of Carbon

For Hydrogen

18 g ---------------------- 1 g

1.3102 g ------------------- x

x = (1.3102 x 1) / 18

x = 0.0727 g of Hydrogen

1 g ------------------------ 1 mol

0.0727g ---------------- x

x = (0.0727 x 1)/1

x = 0.0727 mol of Hydrogen

For oxygen

g of Oxygen = g of sample - g of Carbon - g of hydrogen

g of Oxygen = 1.3109 - 0.8709 - 0.0727

g of Oxygen = 0.3673

16 g of Oxygen ------------- 1 mol of O

0.3673 g --------------------- x

x = (0.3673 x 1)/ 16

x = 0.0230 mol of Oxygen

Divide by the lowest number of moles

Carbon 0.0727 / 0.023 = 3.1 ≈ 3

Hydrogen 0.0727 / 0.023 = 3.1 ≈ 3

Oxygen 0.0230 / 0.023 = 1

C₃H₃O

2. A sample of iron has the dimensions of 2.0 cm x 3.0 cm x2.0 cm. It has a mass of 94.0 grams. What is the density of
iron? (8 points)

Answers

Answer:

first change cm to m and g to kg so you will find the volume first which is 0.02 by 0.03 by 0.02 your answer is 0.000012 m . using the formula density=mass/volume take 0.094/ 0.00012 then divide

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