Which expression is equivalent to 10q^5w^7/2w^3•4(q^6)^2/w^-5
Answers
The expression is equivalent to 20q^17w^19.
What is an expression?
Expression in mathematics is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
We are given that;
10q^5w^7/2w^3•4(q^6)^2/w^-5
Now,
To simplify the expression, we can use the following rules of exponents:
To multiply two powers with the same base, add their exponents
Therefore, by the expression the answer will be 20q^17w^19.
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Answer:
213 crates
Step-by-step explanation:
There is enough space for 26000 kg - 13200 kg = 12800 kg. Divide this by 60 and you get 213 and 1/3. You cannot put 1/3 of a crate, so it is 213 crates.
Answers
Answer:
x=16
Step-by-step explanation:
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Answer: zoe ran 24 miles
Answers
Answer:
The expected value of the game is $0.33.
Step-by-step explanation:
There are N = 36 outcomes of rolling two 6-sided fair dice.
The sample for the sum of two numbers to be 7 is:
S = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2) and (6, 1)}
n (S) = 6
It is provided that there is a 7 to 1 odds against rolling a sum of 6 with the roll of two fair dice.
That is, you win $7 if you succeed and you lose $1 if you fail.
Compute the expected value of the game as follows:
Thus, the expected value of the game is $0.33.
Answers
Answer: the answer is an equation
Step-by-step explanation:
Answers
Answer:
18 = number of players
Step-by-step explanation:
Giving the following information:
Members of a softball team raised $2039.50 to go to a tournament. They rented a bus for $1157.50 and budgeted $49 per player for meals.
To calculate the total number of players they can bring, we need to use the following formula:
Total amount of money= fixed cost + unitary variable cost*number of players
2,039.5= 1,157.5 + 49*number of players
882/49= number of players
18 = number of players
The team can bring a maximum of 18 players to the tournament given the amount they raised and the budgeted expenses.
Let's use "x" to represent the number of players the team can bring to the tournament.
The total amount raised by the team is $2039.50,
and they rented a bus for $1157.50. Each player's meal will cost $49.
The total amount spent on the bus and meals for x players can be represented as follows:
Total Expenses = Bus Cost + (Number of Players) * (Cost per Player's Meal)
= $1157.50 + x * $49
Since the team's total expenses should not exceed the total amount raised,
$2039.50 ≥ $1157.50 + x * $49
$2039.50 - $1157.50 ≥ x * $49
$882 ≥ x * $49
Now, divide both sides by $49 to solve for x:
x ≤ $882 / $49
x ≤ 18
So, the team can bring a maximum of 18 players.
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