The function y = -0.03(x - 14)^2 + 6 models the mump of a red kangaroo where x is the horizontal distance in meters and y is the vertical distance in meters for the height of the jump. What is the kangaroo's maximum height? How long is the kangaroo's jump?

Answers

Answer 1
Answer:
  • From the vertex of the quadratic equation, we find that: The kangaroos maximum height is of 6 meters.
  • From the roots of the equation, we find that: The kangaroo's jump is 28.14 meters long.

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Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^(2) + bx + c

It's vertex is the point (x_(v), y_(v))

In which

x_(v) = -(b)/(2a)

y_(v) = -(\Delta)/(4a)

Where

\Delta = b^2-4ac

If a<0, the vertex is a maximum point, that is, the maximum value happens at x_(v), and it's value is y_(v).

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^(2) + bx + c, a\neq0.

This polynomial has roots x_(1), x_(2) such that ax^(2) + bx + c = a(x - x_(1))*(x - x_(2)), given by the following formulas:

x_(1) = (-b + √(\Delta))/(2*a)

x_(2) = (-b - √(\Delta))/(2*a)

\Delta = b^(2) - 4ac

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The quadratic equation is:

y = -0.03(x - 14)^2 + 6

Placing in standard form:

y = -0.03(x^2 - 28x + 196) + 6

y = -0.03x^2 + 0.84x + 0.12

Thus, it has coefficients a = -0.03, b = 0.84, c = 0.12

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The kangaroo's maximum height is the y-value of the vertex, thus:

\Delta = b^2 - 4ac = (0.84)^2 - 4(-0.03)(0.12) = 0.72

y_(v) = -(\Delta)/(4a) = -(0.72)/(4(-0.03)) = 6

The kangaroos maximum height is of 6 meters.

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The length of the kangaroo's jump is the positive root. The roots are found at the values of x for which y = 0, thus, the solutions of the quadratic equation.

x_(1) = (-0.84 + √(0.72))/(2(-0.03)) = -0.14

x_(2) = (-0.84 - √(0.72))/(2(-0.03)) = 28.14

The kangaroo's jump is 28.14 meters long.

A similar question is given at brainly.com/question/16858635

Answer 2
Answer:

Answer:

Kangaroo's maximum height is 6 m and the kangaroo's jump is 28 m long

Step-by-step explanation:

Given :y = -0.03(x - 14)^2 + 6

To Find : What is the kangaroo's maximum height? How long is the kangaroo's jump?

Solution:

y = -0.03(x - 14)^2 + 6

x is the horizontal distance in meters

y is the vertical distance in meters for the height of the jump.

Substitute y = 0

0 = -0.03(x - 14)^2 + 6

0.03(x - 14)^2 = 6

(x - 14)^2 = (6)/(0.03)

(x - 14)^2 =200

(x - 14) =√(200)

(x - 14) =14.142

x =14.142+14

x =28.142

x≈ 28 m

Now the maximum height will be attained at mid point i.e. (28)/(2) =14

Now substitute x= 14

y = -0.03(14 - 14)^2 + 6

y = 6

So, kangaroo's maximum height is 6 m and the kangaroo's jump is 28 m long


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