A small toy car costs $3 a large toy car costs 5 times as much as the small one Aaron want to buy 1 of each which equation can be used to find the cost a of the 2 cars
Answers
Answer:
$18
Step-by-step explanation:
small -$3
large - $15
3+15=18
Answer: The equation is $3 + ($3 x 5)
Step-by-step explanation:
You add $3 to 3 multiplied by 5 to get the cost of the second car which will then give you the cost of both cars. Then you simplify and get $3 + $15 which gives us the answer $18. So the cost of both the cars is $18.
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Answers
Answer:
d = 13 units
Step-by-step explanation:
calculate the distance d using the distance formula
d =
let (x₁, y₁ ) = (1, 8 ) and (x₂, y₂ ) = (6, - 4 )
substitute these values into the formula for d
d =
=
=
=
= 13 units
Answers
-- Mark a dot on the y-axis, at y = -5 .
-- From there, move 1 unit to the right and 2 units up and make a mark. If this
is too tiny for you, then you can move 7 units to the right and 14 units up, or
11 units to the right and 22 units up ... any way you want to do it, as long as
the distance 'up' is double the distance to the right, because the slope is 2 to 1.
Wherever you wind up, mark a dot.
-- Using your pencil and your ruler, draw a straight line between the two dots you have
marked. You may extend it as far as you wish in either or both directions.
Answers
Answer:
Step-by-step explanation:
Answers
I hope this helped! :D :) :P :3
Answers
There are 2 people involved Ann and Betty, Then divide the TOTAL AMOUNT BY THE NUMBER OF PEOPLE.
· Then it will look like $60÷2= $30 per person.
In this case everyone has equal amount of money, but the question say Ann has $9 more than Betty's. so, Ann≈ $30 +$9= $39.
Betty≈ $30-$9= $21
Because loses money because Ann has more,
TOTAL=Ann+Betty
$60= $39+$21
Final answer:
Betty has $17 and Ann has $43.
Explanation:
This problem is a basic algebraic equation. Let's denote Betty's amount as x. From the problem information, we know that Ann's amount is twice Betty's plus $9, so we can denote it as 2x + $9. It's also told in the problem that together they have $60, so we can form the equation: x (Betty's money) + 2x + $9 (Ann's money) = $60.
Solving this equation, we combine like terms, which gives us 3x + $9 = $60. Subtract $9 from both sides to get 3x = $51. Divide each side by 3, we get x = $17. So, Betty has $17. We substitute x = $17 into the equation 2x + $9 to find Ann's money, which gives us 2*$17 + $9 = $43. So, Ann has $43.
Learn more about Algebra here:
#SPJ11
Answers
We cannot say that the product of 4-digit number and a 1-digit number is always a 4-digit number.
Joe's statement does not make sense.
Given :
Joe says that the product of 4-digit number and a 1-digit number is always a 4-digit number.
Lets take an example and analyze Joe's statement
Let the 4 - digit number is 2131
and a one digit number is 5
Lets multiply it
We can see the the result is a 5-digit number
We cannot say that the product of 4-digit number and a 1-digit number is always a 4-digit number.
Joe's statement does not make sense.
Learn more : brainly.com/question/11262281
The correct answer is:
No.
Explanation:
The number of digits in the product depends completely on what digits are being multiplied. For instance, multiplying 2222 by 4 would result in a 4-digit number, 8888. However, if you multiply by 5, since 5(2) = 10, this will change the number of digits in the answer.