MATHEMATICS HIGH SCHOOL

What fraction is equivalent to 1/8??

Answers

Answer 1
Answer:

Answer:

2/16

5/40

Step-by-step explanation:

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Divide.8.64÷(−0.27)Enter your answer in the box.

The diameter of a cylinder is 6 feet 6 inches. The height of a cylinder is 12 feet 3 inches.

What is the surface area?    (feet squared)

What is the volume?      (feet cubed)

Answers

d-the\ diameter\nr-the\ radius\nH-the\ height\n\nd=6ft\ 6

-4x-8 and -4(x-2) *
A: Yes, they are equivalent
B: No, they're not equivalent

Answers

Answer:

no

Step-by-step explanation:

The problem on the right works out to -4x+8 and the right is -4x-8

so one is + and one is -

Fill in all statements and reasond (geomety proof).​

Answers

Answer:

...

give me a sec to think

Step-by-step explanation:

Find 2 consecutive odd numbers given that difference between their resiprocal is 2/63

Answers

consecutive odd numbers are 2n+1, 2n+3

difference of reciprocals
1/(2n+1) - 1/(2n+3) = 2/63
((2n+3) - (2n+3))/(2n+1)(2n+3) =2/63
2/(4n^2 + 8n +3) =2/63
4n^2 + 8n +3 = 63
4n^2 + 8n -60 = 0
n^2 + 2n - 15 = 0
(n + 5)(n - 3) = 0
n = 3 (only positive)
numbers are 2(3)+1=7 and 9
Those odd numbers are nine and seven.

a recipe that makes 12 muffins calls for 2 1/2 cups of flour. how much flour is needed to make 18 muffins

Answers

Answer:  3(3)/(4) cups of flour

=============================

Work Shown:

A = 12 muffins

B = 2.5 cups of flour

C = 18 muffins

D = x cups of flour

A/B = C/D

12/2.5 = 18/x

12x = 2.5*18

12x = 45

x = 45/12

x = 3.75

x = 3(3)/(4)

So a 4 digit number is represented ABCD, they are not multiplied together, each letter represents 1 single , whole numberif ABCD times D=DCBA

solve for the values of A and B and C and D with full workings and solution (this problem is from my 5th grade math book, just for fun)

Answers

\overline{ABCD}=10^3A+10^2B+10C+D\n\n\overline{ABCD}* D=(10^3A+10^2B+10C+D)* D\n=10^3AD+10^2BD+10CD+D^2\n\n\overline{DCBA}=10^3D+10^2C+10B+A\n\n\overline{ABCD}* D=\overline{DCBA}\n\downarrow\n10^3AD+10^2BD+10CD+D^2=10^3D+10^2C+10B+A

one\ of\ the\ solutions\ of\ general:\n\n\#1\ AD=D\n\#2\ BD=C\n\#3\ CD=B\n\#4\ D^2=A\n\nfrom\ \#1\ and\ \#4\nAD=D\ and\ D^2=A\to\ conclusion:A=D=1\n\nfrom\ \#2\ and\ \#3\nBD=C\ and\ CD=B\to conclusion:B=C\n\ntherefore

\overline{ABCD}=\n1001\n1111\n1221\n1331\n1441\n1551\n1661\n1771\n1881\n1991
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