The side length of a square is 5 feet. A. What is the perimeter of the square? B. What is the area of the square?
Answers
Answer:
A. 20 B. 25
Step-by-step explanation:
A. Perimeter equals the all the side lengths added together, so 5+5+5+5=20
B. Area equals (for a square) two side lengths multiplied by one another, so 5x5=25
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The probability is 1 in 4,011,000 that a single auto trip in the United States will result in a fatality. Over a lifetime, an average U.S. driver takes 46,000 trips.(a) What is the probability of a
True
O False
Answers
Answer:
this is false. hope this helps
Answer:
False.
Step-by-step explanation:
1.4 x 105 = 147 which is not 140,000
6 StartRoot 2 EndRoot cm
12 cm
12 StartRoot 2 EndRoot cm
Answers
Answer:
D. 12 square root 2 cm
Step-by-step explanation:
edge2021
Answers
Answers
The required sum of -3x, 5x + y, and 7x - 8 - 3y in descending order is 9x - 2y - 8.
What is simplification?
Simplification involves applying rules of arithmetic and algebra to remove unnecessary terms, factors, or operations from an expression. The goal is to obtain an expression that is easier to work with, manipulate, or solve.
Here,
To add -3x, 5x + y, and 7x - 8 - 3y, we can first combine like terms.
Group the x-terms together:
-3x + 5x + 7x = 9x
Group the y-terms together:
y - 3y = -2y
Group the constants together:
-8
Putting it all together, we get:
9x - 2y - 8
Therefore, the sum of -3x, 5x + y, and 7x - 8 - 3y in descending order is 9x - 2y - 8.
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F I N A L A N S W E R
Answers
Answer:
Step-by-step explanation:
Hello!
You have two surveys that measure the weight of six-year-old girls in the USA,
1) 1999-2002
μ= 49.3 pounds
(I'll take this mean as the population value since it can be considered "historical data" or point of comparison to make the test.)
2)2003-2006
sample n= 190
sample mean x[bar]= 46 pounds
population standard deviation σ= 17 pounds
Assuming that the study variable X" Weight of six-year-old girls between 2003 - 2006" (pound) has a normal distribution.
If you need to test that the children are heavier now (2003-2006) than in the past (1999-2002) the test hypothesis is:
H₀: μ ≤ 49.3
H₁: μ > 49.3
α: 0.10
The statistic is Z= (x[bar]-μ) ~N(0;1)
(δ/√n)
The critical region is one-tailed to the right.
So you'll reject the null hypothesis if the calculated statistic is equal or greater than 1.28.
Z= 46 - 49.3 = -2.67
17/√190
Since the calculated value -2.67 is less than 1.28 you do not reject the null hypothesis. In other words, the six-year-old girls from 2003-2006 are thinner than the girls from 1999-2002.
I hope it helps!
Answers
Answer:
no more than 7 hours
Step-by-step explanation:
You want p(h) ≥ 3, so ...
p(h) ≥ 3
-2/7h +5 ≥ 3
2 ≥ 2/7h . . . . . . add 2/7h -3
7 ≥ h . . . . . . . . . multiply by 7/2
The worker's shift should be 7 hours or less.
Final answer:
The equation is solved by equating it to 3 and solving for h (hours). It results in a maximum work shift of 7 hours to maintain an average productivity of at least 3 pairs of shoes per hour.
Explanation:
The question deals with a linear function that models the productivity rate of workers in a shoe factory. The function is p(h) = -2/7h + 5 which presents the productivity (p) in pairs of shoes per hour, depending on the hours worked (h). If the company requires a minimum productivity of 3 pairs of shoes per hour to stay profitable, we want to find the maximum value of h such that p(h) is equal to or greater than 3.
To solve, equate the function to 3, that is: 3 = -2/7h + 5. By simplifying, you obtain: -2/7h = 3 - 5 = -2. Then, divide both sides by -2/7, we get h = -2 / (-2/7) = 7 hours.
Therefore, for the company to stay profitable, the worker's shift should not exceed 7 hours.
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