MATHEMATICS HIGH SCHOOL

How do I solve 1/7 +2/7

Answers

Answer 1

Answer: 1/7+2/7=3/7 because you only add the numerator not the denominator

Answer 2

Answer:

Answer: 3/7

Here are two methods to solve this problem.

1. Count on, since you have the same denominator.

1/7, 2/7, 3/7.

2. Add, but not counting on.

1 + 2 = 3

3 = 3/7.

Hope it helps!

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Factor the following equation to solve for "x"; x^{2} - 8x - 20 = 0

Answers

x² - 8x - 20 = 0

Factor the left side:

(x + 2) (x - 10) = 0

That's a true statement if (x = -2) or if (x= 10), so those are your solutions.

x = -2
x = 10

By the way ... you don't factor an equation. You can only factor an expression.

Brandon mixed 6.83 lb of cashews with 3.57 lb of pistachios. after filling 6 bags of same size and mixture, he had 0.35 lb left. what's the weight of each bag? use tape diagram

Answers

Not sure what a tape diagram is but i can solve and explain for you....
weight in total = 6.83 + 3.57 = 10.4 lb
x = weight for one bag
6x = weight for all 6 bags

Then form an equation that will allow you to work out x

6x + 0.35 = 10.4
subtract 0.35 from both sides
6x = 10.05
then divide both sides by 6 to get x on its own
x = 1.675
one bag weighs 1.675 lb

The weight of each bag filled by Brandon, is $\fbox{\bf1.675\,lb}$ .

Further explanation:

The amount of cashews and pistachios mixed are $6.83\,lb$ and $3.57\,lb$ respectively then the total weight of mixture is the sum of cashews and pistachios.

After the above nut mixture created by mixing cashews and pistachios is filled in six bags, the weight of remaining nuts is $0.35\,lb$ .

Therefore, the total mixture that is filled in 6 bags is obtained as the difference of total amount and the remaining mixture amount.

$\begin{aligned}{\text{Total mixture filled in six bags}}&=6.83+3.57-0.35\n&=10.4-0.35\n&=10.05\n\end{aligned}$

Now, this obtained amount of mixture weighing $10.05\,lb$ is filled equally in 6 bags as the size of bags is same then the amount of mixture in one bag or each bag is calculated as,

$\begin{aligned}{\text{Total mixture filled in each bags}}&=\frac{{10.05}}{6}\n&=1.675\n\end{aligned}$

Thus, the weight of each of the six bags that Brandon fills, is $\fbox{\bf1.675\,lb}$ .

Learn more:

1. Linear equation application brainly.com/question/2479097

2. Composite functions brainly.com/question/2142762

3. Linear equation application brainly.com/question/2479097

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Mixtures and ratios

Keywords: cashews, pistachios, one bag, six bag, each bag, weight, Brandon, same size, mixture, nuts, 6.83lb, 3.57lb, 0.35lb, total mixture, amount of mixture, remaining amount, remaining weight, total weight, nut mixture.

Each Friday, the school prints 400 copies of the school newsletter. The equation c = 400w models the relationship between the number of weeks and the total number of copies of the newsletters printed. What is true of the graph of this scenario

Answers

A viable point on the graph is ( 8, 3200 )

The values of w must be... Any WHOLE number.

C=400w can be written as y=400x. This is the equation of a line with slope 400 and y-intercept of 0.
The slope of positive 400 represents the number of copies printed each week. Since the slope is positive, the number of copies increases each week.

How many leaves on a tree diagram are needed to represent all possible combinations tossing a coin 4 times?

Answers

Answer with explanation:

When you toss a coin once , total possible outcome =2={H, T}

When you toss a coin twice , total possible outcome =2²=4={HT,TH,T T,H H}

When you toss a coin thrice , total possible outcome =2³=8

={T T T,T TH, T HT,H T T,H HT,H TH,T H H,H H H}

When you toss a coin 4 times , total possible outcome

$2^4=16$

={T T T T, T T TH, H T T T,T H T T,T T HT,T T H H,H H T T,T H HT,H T TH,H TH T,T H TH, H H HT,H T H H,TH H H,H H TH,H H H H}

=16

There are 16 possible outcomes in all.

So, total number of leaves needed on the tree Diagram = 16 Leaves

1/2 x 1/2 x 1/2 x 1/2 = 1/16

Answer: 16

How do I answer #38? I was thinking 1/4...

Answers

look at the attached picture

Solve 2cos^2x+3cosx-2=0

Answers

$\bf 2cos^2(x)+3cos(x)-2=0\impliedby \textit{so, notice is just a quadratic} \n\n\n\ [2cos(x)~~-~~1][cos(x)~~+~~2]=0\n\n -------------------------------\n\n 2cos(x)-1=0\implies 2cos(x)=1\implies cos(x)=\cfrac{1}{2} \n\n\n \measuredangle x=cos^(-1)\left( (1)/(2) \right)\implies \measuredangle x= \begin{cases} (\pi )/(3)\n\n (5\pi )/(3) \end{cases}\n\n -------------------------------\n\n cos(x)+2=0\implies cos(x)=-2$

now, for the second case, recall that the cosine is always a value between -1 and 1, so a -2 is just a way to say, such angle doesn't exist.

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