The statement the Internet is considered a WAN is true.
We are given that;
The statement about WAN
Now,
A WAN, or a wide area network, is a computer network that spans over a large geographic area, such as regions, countries, or even the world.
The Internet is the largest and most well-known example of a WAN, as it connects millions of devices across the globe using various communication protocols and technologies.
A WAN can also be composed of smaller networks, such as local area networks (LANs) or metropolitan area networks (MANs), that communicate with each other.
Therefore, by WAN the answer will be true.
To learn more about WAN visit;
#SPJ6
Answer:
true. internet is definitely wan
Answer:
I'm not exactly sure on what the question is, but from reading it, I determined that you'll be creating 2 different designs using Inkscape/Photoshop. I'm leaving 2 of my designs in here for you to use on your project. Unknown on what to do about the design that wasn't created in an image-editing program.
Answer: The address of the cell is C2
Explanation:
In a worksheet like Microsoft Excel, there are rows and columns. It tags rows with numbers and tags columns with alphabet letters. For example, the first row is 1, the second row is 2, the third row is 3, and so on. Similarly, the first column is A, the second column is B and so on.
We want to know the address for the intersect of the second row i.e. 2, and the third column i.e. C in a worksheet. In other words, it might intersect column C and row 2.
A cell is a box where a row and column intersect. The address of the cell starts with the column, and next there is the row. In that case, we can conclude that the address of the cell is C2.
C2 or B3. This is if you are talking about Microsoft Excel.
Answer:
I am writing a Python program:
def string_finder(target,search): #function that takes two parameters i.e. target string and a search string
position=(target.find(search))# returns lowest index of search if it is found in target string
if position==0: # if value of position is 0 means lowers index
return "Beginning" #the search string in the beginning of target string
elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings
return "End" # returns end
elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1
return "Middle" #returns middle
else: #if none of above conditions is true return not found
return "not found"
#you can add an elif condition instead of else for not found condition as:
#elif position==-1
#returns "not found"
#tests the data for the following cases
print(string_finder("Georgia Tech", "Georgia"))
print(string_finder("Georgia Tech", "gia"))
print(string_finder("Georgia Tech", "Tech"))
print(string_finder("Georgia Tech", "Idaho"))
Explanation:
The program can also be written in by using string methods.
def string_finder(target,search): #method definition that takes target string and string to be searched
if target.startswith(search): #startswith() method scans the target string and checks if the (substring) search is present at the start of target string
return "Beginning" #if above condition it true return Beginning
elif target.endswith(search): #endswith() method scans the target string and checks if the (substring) search is present at the end of target string
return "End"#if above elif condition it true return End
elif target.find(search) != -1: #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string
return "Middle" #if above elif condition it true return End
else: #if none of the above conditions is true then returns Not Found
return "Not Found"
It should be noted that the number of thermal performance mode is 5.
From the complete information, it should be noted that there are five thermal performance control modes are there in Alienware Area 51m to support different user scenarios.
The modes are:
In conclusion, the correct option is 5
Learn more about modes on:
Answer:
3
Explanation:
The Dell Alienware Personal Computers refers to a range of PC's which are known for their strength, durability and most commonly their graphical performance. Th ecomputwrs are built to handle very high and intensive graphic demanding programs including gaming. The Alienware area 51m is a laptop which has been loaded with the capability and performance of a high graphic demanding desktop computers boasting massive memory size and greater graphic for better game play and high graphic demanding programs.
The laptop features an improved thermal and performance capability to handle the effect of different graphic demanding programs. Therfore, the laptop has 3 different thermal a d performance system modes which altenrtes depending on graphic demands in other to handle intensive demands.
Write the answers so we can answer your question
Answer:
Check the explanation
Explanation:
// Define a Square class with methods to create and read in
// info for a square matrix and to compute the sum of a row,
// a column, either diagonal, and whether it is magic.
//
// ****************************************************************
import java.util.Scanner;
import java.io.*;
public class Square {
int[][] square;
//--------------------------------------
//create new square of given size
//--------------------------------------
public Square(int size) {
square = new int[size][size];
}
//-----------------------------------------------
//return the sum of the values in the given row
//-----------------------------------------------
public int sumRow(int row) {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[row][i];
}
return sum;
}
//-------------------------------------------------
//return the sum of the values in the given column
//-------------------------------------------------
public int sumCol(int col) {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[i][col];
}
return sum;
}
//---------------------------------------------------
//return the sum of the values in the main diagonal
//---------------------------------------------------
public int sumMainDiag() {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[i][i];
}
return sum;
}
//---------------------------------------------------------------
//return the sum of the values in the other ("reverse") diagonal
//---------------------------------------------------------------
public int sumOtherDiag() {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[square.length - i - 1][i];
}
return sum;
}
//-------------------------------------------------------------------
//return true if the square is magic (all rows, cols, and diags have
//same sum), false otherwise
//-------------------------------------------------------------------
public boolean magic() {
// Add your code here. Check if the sum of main diagonal equals the other diagonal,
// also if all rows and all columns sums equal to the diagonal as well. Any uneuqal will
// terminate the comparison.
int d1 = sumMainDiag();
int d2 = sumOtherDiag();
if (d1 != d2) {
return false;
}
for (int i = 0; i < square.length; i++) {
if (d1 != sumRow(i) || d1 != sumCol(i)) {
return false;
}
}
return true;
}
//----------------------------------------------------
//read info into the square from the standard input.
//----------------------------------------------------
public void readSquare(Scanner scan) {
for (int row = 0; row < square.length; row++) {
for (int col = 0; col < square.length; col++) {
square[row][col] = scan.nextInt();
}
}
}
//---------------------------------------------------
//print the contents of the square, neatly formatted
//---------------------------------------------------
public void printSquare() {
for (int row = 0; row < square.length; row++) {
for (int col = 0; col < square.length; col++) {
System.out.print(square[row][col] + "\t");
}
System.out.println();
}
}
}
// ****************************************************************
// SquareTest.java
//
// Uses the Square class to read in square data and tell if
// each square is magic.
//
// ****************************************************************
class SquareTest {
public static void main(String[] args) throws IOException {
File file = new File("magicData.txt");
Scanner scan = new Scanner(file);
int count = 1; //count which square we're on
int size = scan.nextInt(); //size of next square
//Expecting -1 at bottom of input file
while (size != -1) {
//create a new Square of the given size
Square magicSquare = new Square(size);
//call its read method to read the values of the square
magicSquare.readSquare(scan);
System.out.println("\n******** Square " + count + " ********");
//print the square
magicSquare.printSquare();
//print the sums of its rows
for (int row = 0; row < size; row++) {
System.out.println("Sum of row " + row + ": "
+ magicSquare.sumRow(row));
}
//print the sums of its columns
for (int col = 0; col < size; col++) {
System.out.println("Sum of column " + col + ": "
+ magicSquare.sumCol(col));
}
//print the sum of the main diagonal
System.out.println("Sum of the main diagonal: "
+ magicSquare.sumMainDiag());
//print the sum of the other diagonal
System.out.println("Sum of the other diagonal: "
+ magicSquare.sumOtherDiag());
//determine and print whether it is a magic square
if (magicSquare.magic()) {
System.out.println("It's a magic square!");
} else {
System.out.println("It's not a magic square!");
}
System.out.println();
//get size of next square
size = scan.nextInt();
count++;
}
}
}
Answer:
See explaination
Explanation:
/ Define a Square class with methods to create and read in
// info for a square matrix and to compute the sum of a row,
// a column, either diagonal, and whether it is magic.
//
// ************************************************************
import java.util.Scanner;
import java.io.*;
public class Square {
int[][] square;
//--------------------------------------
//create new square of given size
//--------------------------------------
public Square(int size) {
square = new int[size][size];
}
//-----------------------------------------------
//return the sum of the values in the given row
//-----------------------------------------------
public int sumRow(int row) {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[row][i];
}
return sum;
}
//-------------------------------------------------
//return the sum of the values in the given column
//-------------------------------------------------
public int sumCol(int col) {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[i][col];
}
return sum;
}
//---------------------------------------------------
//return the sum of the values in the main diagonal
//---------------------------------------------------
public int sumMainDiag() {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[i][i];
}
return sum;
}
//---------------------------------------------------------------
//return the sum of the values in the other ("reverse") diagonal
//---------------------------------------------------------------
public int sumOtherDiag() {
// Add your code here
int sum = 0;
for (int i = 0; i < square.length; i++) {
sum = sum + square[square.length - i - 1][i];
}
return sum;
}
//-------------------------------------------------------------------
//return true if the square is magic (all rows, cols, and diags have
//same sum), false otherwise
//-------------------------------------------------------------------
public boolean magic() {
// Add your code here. Check if the sum of main diagonal equals the other diagonal,
// also if all rows and all columns sums equal to the diagonal as well. Any uneuqal will
// terminate the comparison.
int d1 = sumMainDiag();
int d2 = sumOtherDiag();
if (d1 != d2) {
return false;
}
for (int i = 0; i < square.length; i++) {
if (d1 != sumRow(i) || d1 != sumCol(i)) {
return false;
}
}
return true;
}
//----------------------------------------------------
//read info into the square from the standard input.
//----------------------------------------------------
public void readSquare(Scanner scan) {
for (int row = 0; row < square.length; row++) {
for (int col = 0; col < square.length; col++) {
square[row][col] = scan.nextInt();
}
}
}
//---------------------------------------------------
//print the contents of the square, neatly formatted
//---------------------------------------------------
public void printSquare() {
for (int row = 0; row < square.length; row++) {
for (int col = 0; col < square.length; col++) {
System.out.print(square[row][col] + "\t");
}
System.out.println();
}
}
}
// ****************************************************************
// SquareTest.java
//
// Uses the Square class to read in square data and tell if
// each square is magic.
//
// ****************************************************************
class SquareTest {
public static void main(String[] args) throws IOException {
File file = new File("magicData.txt");
Scanner scan = new Scanner(file);
int count = 1; //count which square we're on
int size = scan.nextInt(); //size of next square
//Expecting -1 at bottom of input file
while (size != -1) {
//create a new Square of the given size
Square magicSquare = new Square(size);
//call its read method to read the values of the square
magicSquare.readSquare(scan);
System.out.println("\n******** Square " + count + " ********");
//print the square
magicSquare.printSquare();
//print the sums of its rows
for (int row = 0; row < size; row++) {
System.out.println("Sum of row " + row + ": "
+ magicSquare.sumRow(row));
}
//print the sums of its columns
for (int col = 0; col < size; col++) {
System.out.println("Sum of column " + col + ": "
+ magicSquare.sumCol(col));
}
//print the sum of the main diagonal
System.out.println("Sum of the main diagonal: "
+ magicSquare.sumMainDiag());
//print the sum of the other diagonal
System.out.println("Sum of the other diagonal: "
+ magicSquare.sumOtherDiag());
//determine and print whether it is a magic square
if (magicSquare.magic()) {
System.out.println("It's a magic square!");
} else {
System.out.println("It's not a magic square!");
}
System.out.println();
//get size of next square
size = scan.nextInt();
count++;
}
}
}