Someone help me please

Step-by-step explanation:

a box (like a "deformed" die) has 6 sides.

and in case of such a rectangular box there are 3 pairs of equal sides.

the area of each side is a rectangle.

top and bottom : 19×12 times 2

front and back : 19×3 times 2

left and right : 12×3 times 2

so, we get

19×12×2 + 19×3×2 + 12×3×2 = 642 in²

and now, we need 10% more.

10% = 642/10 = 64.2 in²

the total is then

642 + 64.2 = 706.2 ≈ 706 in²

Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

Mass of drained water = 0.025 gram

Density

Answer:

Step-by-step explanation:

Using normal distribution,

z = (x - μ)/σ

μ= mean = 44 and

σ = standard deviation= 5.0

a) The probability that yield strength is at most 40=

P( x lesser than or equal to 40)

z = (40-44)/5= -0.8

Looking at the normal distribution table,

P( x lesser than or equal to 40) =0.2119

b) P(x greater than 62) = 1 - P(x lesser than or equal to 62)

z = (62-44)/5= 3.6

Looking at the normal distribution table,

P(x greater than 62) = 1 -0.99984

= 0.00016

c)P( 42 lesser than or equal to x lesser than or equal to 62)

= P(x lesser than or equal to 62) - P( x lesser than or equal to 40)

= 0.99987-0.2119= 0.78797

d) What yield strength value separates the strongest 75% from the others.

To get x for strongest 75, we get the z value corresponding to 0.75 from the table

z = 0.675= (x-44)/5

x = 3.375+44 = 47.375

The rest is 25% = 0.25

we get the z value corresponding to 0.25 from the table)

z = -0.67 = (x-44)/5

-3.35= x -44

x = -44+3.35= 40.65

yield strength value that separates the strongest 75% from the others

=47.375-40.65= 6.725

Final answer:

The probability that the yield strength is at most 40 is approximately 0.2119 and the probability that it is greater than 62 is approximately 0.0001. The yield strength value that separates the strongest 75% from the others is approximately 40.628 ksi.

Explanation:

This question is about calculating probabilities and percentiles using the properties of the normal distribution. The yield strength for the A36 grade steel is normally distributed with a mean (μ) of 44 and a standard deviation (σ) of 5.0.

(a) To find the probability that the yield strength is at most 40, we will need to calculate the Z-score value for the yield strength of 40. The Z-score can be calculated using the following formula: Z = (X - μ) / σ , where X is the observed value, μ is the mean, and σ is the standard deviation. For X = 40, μ = 44, and σ = 5.0, the Z-score is -0.8. Looking up the Z-score in the standard normal distribution table, the probability that the yield strength is at most 40 is approximately 0.2119. Using a similar process, we find that the probability that the yield strength is greater than 62 is less than 0.0001, very close to zero.

(b) To determine the yield strength value that separates the strongest 75% from the others, we find the Z-score that corresponds to a cumulative probability of 0.25 in the standard normal distribution table (because the strongest 75% corresponds to the weakest 25%). That Z-score is approximately -0.6745. Using the formula Z = (X - μ) / σ to solve for X gives us X = σZ + μ  = 5.0 * -0.6745 + 44 = 40.6275, which rounded to three decimal places is 40.628.

Learn more about Normal Distribution here:

brainly.com/question/34741155

#SPJ3

Answer:

8.5 or 8 1/2.

Step-by-step explanation:

To find the product of 2 5/6 and 3, you can multiply the two numbers together.

2 5/6 x 3 is equal to 8.5, therefore, the product of these two numbers is 8 1/2.