MATHEMATICS COLLEGE

Find the product (-2)(3)

Answers

Answer 1

Answer:

Answer:

- 6

Step-by-step explanation:

Step 1:

( - 2 ) ( 3 ) Equation

Step 2:

- 2 × 3 Open Parenthesis

Answer:

- 6 Multiply

Hope This Helps :)

Answer 2

Answer:

Answer:

Multiply -2 with 3

Step-by-step explanation:

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Find the y intercept of the following equation y = 7/2 x - 10/7

A. 7/2
B. -7/2
C. 10/7
D. -10/7

Answers

Answer : D. -10/7
Steps:
y-intercept is y value when x=0.

y = 7/2 (0) - 10/7 =-10/7

Amy goes to a pumpkin patch and picks out a pumpkin that weighs 3,550 grams. If 1 gram = 0.0352 ounces, how many ounces does the pumpkin weigh? A) 124.56 ounces
B) 124.96 ounces
C) 125.56 ounces
D) 125.96 ounces

Answers

9514 1404 393

Answer:

B) 124.96 ounces

Step-by-step explanation:

To find ounces, multiply the number of grams by the number of ounces in each gram.

3550 × 0.0352 = 124.96 . . . ounces

Angela can swim 480 meters in 40 minutes. What units are used to determine Angela's rate?

Answers

Answer:

Meters Per Minute (12 meters per minute)

Step-by-step explanation:

480/40 = 12

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of error: seven percentage points, confidence level 95%, from a prior study,^p is estimated by the decimal equivalent of 42%n=_____ (round to the nearest integer.)

Answers

Answer: 191

Step-by-step explanation:

Formula to find the minimum sample size required to estimate a population proportion or percentage:

$n= \hat{p}(1-\hat{p})((z^*)/(E))^2$

, where $\hat{p}$ = proportion estimated by prior study.

E= Margin of error.

z* = Critical z-value.

Given : Confidence level = 95%

Critical value for 95% confidence = z*=1.96

$\hat{p}=\ 42\%=0.42$

E= 7%= 0.07

Then, $n= 0.42(1-0.42)((1.96)/(0.07))^2$

$n= 0.42(0.58)(28)^2$

$n= 0.2436(784)=190.9824approx191$

Hence, the minimum sample size required=191

11 The net force on a vehicle that is accelerating at a rate of 1.5 m/s² is 2,800 newtons. What isthe mass of the vehicle to the nearest kilogram?

Answers

Answer:

$Mass = 1867kg$

Step-by-step explanation:

Given

$Force = 2800N$

$Acceleration = 1.5m/s^2$

Required

Determine the mass of the vehicle

This question will be answered using Newton's second law

$Force = Mass * Acceleration$

Substitute values for Force and Acceleration

$2800 = Mass * 1.5m/s^2$

Make Mass the subject

$Mass = (2800N)/(1.5m/s^2)$

$Mass = 1866.6667kg$

$Mass = 1867kg$ ---- approximated

Hence, the mass of the vehicle is 1867kg

Helppp ME PLSSSS

PLS

Answers

Answer:

ok so the bottom of this shape is 4

the sides are 5 and there is two of them

and then if we count if looks like there is 2 going down and two going up so

4+5*2+2*2

4+10+2*2

4+10+4

14+4

18

Hope This Helps!!!

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Q 3.28: To create a confidence interval from a bootstrap distribution using percentiles, we keep the middle values and chop off a certain percent from each tail. Indicate what percent of values must be chopped off from each tail for a 97% confidence level. A : We keep the middle 97% of values by chopping off 1.5% from each tail. B : We keep the middle 1.5% of values by chopping off 97% from each tail. C : We keep the middle 3% of values by chopping off 97% from each tail. D : We keep the middle 3% of values by chopping off 1.5% from each tail. E : We keep the middle 97% of values by chopping off 3% from each tail.

4. Simplify the following.3a. 2-X5-:113x5567

If two objects travel through space along two different curves, it's often important to know whether they will collide. (Will a missile hit its moving target? Will two aircraft collide?) The curves might intersect, but we need to know whether the objects are in the same position at the same time. Suppose the trajectories of two particles are given by the vector functions for t 0. Do the particles collide? If they collide find t. If not enter NONE.r1(t)=r2(t)=<9t-14,t^2,13t-42>t=