Draw area model of 4.6 and 3

Answers

Answer 1

Answer: 54 Is the answer to that

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Pls help these are my teachers instructionsI decided to do the first problem on the test for you! Get out your red pen! I made a mistake What did I do wrong? Explain my mistake and fix it!

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Answer:

The x^6 should be on the bottom because when you attempt to bring x^12 on top, you are essentially doing the equation x^6-x^12 which would equal x^-6 and if you have x^-6, you must bring it down to the denominator so the final answer for question 1 is 27/4x^6y^8

Step-by-step explanation:

Find the measure of angle x in the figure below:A:35
B:48
C:69
D:78

Answers

The best way to solve for x is to first solve for y and then subtract values. The top of "line" of the 3 angles togethers add up to 180 degrees. So from this, you can deduct this equation into $52+59+y=180$ . To solve for y, subtract $52$ and $59$ from the left hand side and rights hand side of the equation. now you know the value is $y=180-52-59=69$ . So the value of y is 69 degrees.
Now you know two angles of a triangle and the sum of the angles in a triangle is 180 degrees. So the equation is $x+69+63=180$ . To solve for x, subtract $69+63$ from both sides. $x=180-69-63=48$ . So you know that $x=48$ degrees.

Answer:

the answer is b X=48 degrees

Why are (4,6) and (6,4) not at the same point on a grid? explain.

Answers

This is because for the first coordinate goes over 4 up 6 and the other goes over 6 up 4

It is on a different axis

A camera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell for $18each. a. How many cameras must the company sell in one day to equal its daily costs? b. If the manufacturer can increase production by 50
cameras per day, what would their daily profit be?

Answers

Amount of money spent per day = $1800

Cost of overhead expenses per day for labor and materials = $9

Selling price of each camera = $18

a. Let us assume the number of cameras manufactured per day = x dollars

Then

Cost of cameras sold in 1 day = 18x

18x = 1800 + 9x

18x - 9x = 1800

9x = 1800

x = 200

From the above deduction, we can conclude that the number cameras sold per day is 200

b. Daily selling amount of 250 cameras = 250 * 18

= 4500 dollars

Daily manufacturing price of 250 cameras = 1800 + (9 * 250)

= 4050 dollars

Then

Daily profit = 4500 - 4050

= 450 dollars

7. A $300 suit is marked down by 20%. Find the
sale price rounded to the nearest dollar.

Answers

Final answer:

The sale price of the suit is calculated by multiplying the original price by the percentage discount to find the amount of the discount, then subtracting that number from the original price. In this case, the suit is marked down by $60, and the sale price is $240.

Explanation:

This problem deals with calculating the sale price of an item after a percentage discount. To start with, you need to compute the amount of the discount first. The discount is 20% of the initial price, which means we multiply 0.20 (the decimal representation of 20%) by $300. That gives you $60.

Next, to find the sale price, you subtract the discount from the original price. That is $300 - $60 = $240. Thus, the sale price of the suit, after a 20% discount, is $240.

Learn more about Percentage Discount Calculation here:

brainly.com/question/32602544

#SPJ3

Answer:

$240

Step-by-step explanation:

$300 x .20 = $60

$300 - $60 = $240

a sum of RS 500 is in the form of denominators of RS5 & RS 10..if the total no. of notes is 90 ,find the no. of notes of each type................ do it by process will be mark as best

Answers

let rs.5 denominations be x , then rs 10 denominations will be 90-x

then total amount 5x + 10(90-x) which is rs.500

5x + 10(90-x) = 500

900 - 5x = 500
400 = 5x
therefore x = 80
therefore no. of rs.5 is 80
no. of rs.10 is 90-x = 90-80 = 10

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