I have an exam for science edexcel pls help what should i revise its physics help plslslslslsl
Answers
~First, which topics that you very weak, revise it
~Don't read in sentence form , read in I-Think form
~Don't feel nervous and just be like normal
Hope it helps!! Good luck for your exam❤️
Related Questions
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.Is this exponential growth or decay? GrowthWhat is the rate of growth or decay?What was the initial amount? 120000What is the function?What is the population after 10 years? Round to the nearest whole number.
What is the greatest common factor of 8x and 40y? 8 8xy 320 320xy
Is it true that Confidence intervals are always close to their true population values?
What is the solution to 3/4 a>-16?O a>-21/3 O a<-21 O a> 21-1/ O a <21/13
b. An inch is 1/12 of a foot. How much has the angelfish grown in feet?
40 points!
Answers
A)
Earlier, The length of the angelfish = inches
Now, the length of angelfish = inches
We have to determine the grown length of angelfish
= -
=
LCM of '2' and '3' is '6',
=
= inch
Therefore, the angelfish has grown by inch.
B)
We have to determine the increased length of angelfish in feet.
Since foot
So,
= 0.069 foot.
2 1/3 - 1 1/2 = 2 2/6 - 1 3/6
= 2 + 6 / 6 - 1 3/6 = 8/6 - 1 3/6 = 5/6
The answer for B is 0.0694 feet.
Greetings!
Answers
The answer is B
^6 sqrt 200
Answers
Answer:
x<-0.5
Step-by-step explanation:
Answers
Answer:
- c = 135
- k = 0.42615
Step-by-step explanation:
We assume you want your model to be ...
p = c·e^(kt)
Filling in (t, p) values of (3, 484) and (5, 1135), we have two equations in the two unknowns:
484 = c·e^(3k)
1135 = c·e^(5k)
Taking logs makes these linear equations:
ln(484) = ln(c) +3k
ln(1135) = ln(c) +5k
Subtracting the first equation from the second, we have ...
ln(1135) -ln(484) = 2k
k = ln(1135/484)/2 ≈ 0.42615
Using that value in the first equation, we find ...
ln(484) = ln(c) +3(ln(1135/484)/2)
ln(c) = ln(484) -(3/2)ln(1135/484)
c = e^(ln(484) -(3/2)ln(1135/484)) ≈ 134.8
The initial number in the culture was 135, and the k-value is about 0.42615.
_____
I prefer to start with the model ...
p = 484·(1135/484)^((t-3)/2)
Then the initial value is that obtained when t=0:
c = 484·(1135/484)^(-3/2) = 134.778 ≈ 135
The value of k the log of the base for exponent t. It is ...
ln((1135/484)^(1/2)) = 0.426152
This starting model matches the given numbers exactly. The transformation to c·e^(kt) requires approximations that make it difficult to match the given numbers.
__
For this model, the base of the exponent is the ratio of the two given population values. The exponent is horizontally offset by the number of days for the first count, and scaled by the number of days between counts. The multiplier of the exponential term is the first count. The model can be written directly from the given data, with no computation required.
what is the amount of its total liabilities?
Answers
Answer:
Liabilities = 96,000
Step-by-step explanation:
Use the fundamental accounting equation
Assets = Liabilities + Equity
Substitute the information you are given
183,000 = Liabilities + 887,000
Isolate "Liabilities". Subtract 887,000 on both sides.
183,000 - 887,000 = Liabilities + 887,000 - 887,000
-704000 = Liabilities
This problem is impossible if the equity is 887,000 with 183,000 being the assets. The liabilities will be a negative number.
If the equity = 87,000, following the same steps:
Assets = Liabilities + Equity
183,000 = Liabilities + 87,000
183,000 - 87,000 = Liabilities + 87,000 - 87,000
96,000 = Liabilities
Liabilities = 96,000
Therefore, the total liabilities amount to $96,000.