MATHEMATICS HIGH SCHOOL

Ninth grade algebra.i am solving for x​
ninth grade algebra.i am solving for x​ - 1

Answers

Answer 1
Answer:

Answer: x = 1

Step-by-step explanation:

So you need to get x completely alone, so take c out of it by subtracting c

-3x = -3 -2c

x = 1 +2/3c

so you would plug that in to solve for C

So you know what x is (or the substitute for it right now)

-3(1 + 2/3c) + 2c = -3

multiply or add

-3 - 2c + 2c = -3

c is 0 when you combine

-3x + 0 = -3

-3x = -3

x = 1

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Graph x2 + y2 = 9. What are its lines of symmetry?

Answers

            Equation given in the question represents a circle.

            Therefore, there will be infinite lines of symmetry.

Line of symmetry of a figure:

  •  Line of symmetry of a figure is the line over which half of the figure overlaps the other half.

Given in the question,

  •  Graph represented by the equation → x² + y² = 9

Equation given in the question is in the form of

(x-0)^2+(y-0)^2=3^2

Since, general equation of a circle is given by,

(x-h)^2+(y-k)^2=r^2        

Therefore, given equation represents a circle.

By definition, a circle has infinite lines of symmetry passing through the center.

      Therefore, given equation will have infinite lines of symmetry.

Learn more about the lines of symmetry here,

brainly.com/question/1968732?referrer=searchResults

Answer:

It has infinitely many line of symmetry. All diameters are line of symmetry.

Step-by-step explanation:

Given: Equation is x² + y² = 9

To find: line of symmetry of given equation

Given equation is the equation of circle.

x² + y² = 9

re write,

(x-0)² + (y-0)² = 3²

by comparing given equation with standard equation of circle ,

(x-h)² + (y-k)² = r²

we get, h = 0 , k = 0 , r = 3

⇒ Centre of circle = ( 0 , 0 ) and radius of circle = 3 unit

Since It is a circle. so it has Infinitely many line of symmetry

Also, All diameters of this circle are line of symmetry for this circle.

Some equation of line of symmetry,

x-axis : y = 0

y-axis : x = 0

Simplify completely quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36 .1. 2 open parentheses 13 x plus 5 close parentheses over 5 x minus 9
2. 2 open parentheses x plus 10 close parentheses over x minus 9
3. quantity 2 x plus 5 over x minus 9
4. quantity 13 x plus 5 over 5 x minus 9

Answers

Answer:

  • (2x + 5)/(x - 9)
  • 3. quantity 2 x plus 5 over x minus 9

Step-by-step explanation:

Quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36

  • (2x² + 13x + 20)/(x² -5x - 36) =
  • (2x²+ 5x + 8x + 20)/(x² - 9x + 4x -36)=
  • (2x + 5)(x + 4)/(x - 9)(x + 4) =
  • (2x + 5)/(x - 9)

Correct option is option 3

Given that (-1,3) is on the graph of f(x), find thecorresponding point for the function
f(x - 1).

Answers

I tried helping but I cant figure it out let me see..

Answer: 0,3

Step-by-step explanation:

Assume that the box contains 11 balls: 4 red, 4 blue, and 3 yellow. As in the text, you draw one ball, note its color, and if it is yellow replace it. If it is not yellow you do not replace it. You then draw a second ball and note its color.(1) What is the probability that the second ball drawn is yellow?

(2) What is the probability that the second ball drawn is red?

Answers

1)
(3)/(11) * (3)/(11) + (8)/(11) * (3)/(10)= (9)/(121)+ (24)/(110) =0.29

2)
(3)/(11) * (4)/(11) +(8)/(11) * (3)/(10) +(8)/(11) * (4)/(10) = (12)/(121)+ (24)/(110) + (32)/(110) = 0.61

Find the area of sector AOB. Enter your answer in terms of a fraction of π and rounded to the nearest tenth.The area of sector AOB is _____ π ≈ _____ mm2.

Answers

40/360 = 1/9

Sector AOB is 1/9 of the total circle.

A = pi x 3^2

A = 9pi

9pi / 9 = 1pi

The area of sector AOB is 1pi = approximately 3.1 mm^2.

Hope this helps!! :)

Find a cofunction with the same value as the given expression. csc 52°A. sec 52°
B. sec 38°
C. sin 52°
D. sec 142°

Answers

To find a cofunction with the same value as the expression csc 52*, you would use the formula like this.  csc (x) = sec (90-x). So if you use csc(52) that equals sec(90-52). This in turn, equals sec(38). So the answer is B.
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