Please hurry need help

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Answer 1

Answer:

Answer:

-11

Step-by-step explanation:

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Paired t‐Test for Mean Comparison with Dependent Samples To study the effects of an advertising campaign at a supply chain, several stores are randomly selected with the following observed before‐ and after‐advertising monthly sales revenues: Store number 1 2 3 4 5
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Answers

Answer:

a) $t=(\bar d -0)/((s_d)/(√(n)))=(0.7 -0)/((0.678)/(√(5)))=2.308$

$p_v =P(t_((4))>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

b) The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

1=test value old , 2 = test value new

1: 5.2 6.5 7.2 5.7 7.6

2: 6.4 7.8 6.8 6.5 8.2

The system of hypothesis for this case are:

Null hypothesis: $\mu_2- \mu_1 \leq 0$

Alternative hypothesis: $\mu_2 -\mu_1 >0$

The first step is calculate the difference $d_i=y_i-x_i$ and we obtain this:

d: 1.2, 1.3, -0.4, 0.8, 0.6

The second step is calculate the mean difference

$\bar d= (\sum_(i=1)^n d_i)/(n)=0.7$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =(\sum_(i=1)^n (d_i -\bar d)^2)/(n-1) =0.678$

The 4 step is calculate the statistic given by :

$t=(\bar d -0)/((s_d)/(√(n)))=(0.7 -0)/((0.678)/(√(5)))=2.308$

The next step is calculate the degrees of freedom given by:

$df=n-1=5-1=4$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_((4))>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

Part b

The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

Help please i need all

Answers

Answer:

What grade are you in?

Step-by-step explanation:

6. 16 divided by 4 is 4

Then your keep going like 8 is 25 divided by 5 which is 5.

9. 120 divided by 4 is 30

10. 36 divided by 6 is 6

If you use a calculator it will be easier

A set of data whose histogram is extremely skewed yields a sample mean and standard deviation of 69.5 and 10.75, respectively. What is the minimum percentage of observations that:A. are between 48 and 91.

and

B. are between 37.25 and 101.75

Answers

I am a beautiful person who can help you with the new one of those who are interested

Find the solutions to x2-2x+10=0. The quadratic formula has been started for you.

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Answer

The solution to the quadratic equation is

$x=1\pm3i$

EXPLANATION

Problem Statement

The question gives us the beginning of the application of the Quadratic formula on a quadratic equation. We are required to simplify the expression and get in more certain terms, the values of x.

The expression given is:

$\begin{gathered} x^2-2x+10=0 \n \n x=\frac{2\pm\sqrt[]{(-2)^2-(4)(1)(10)}}{2} \end{gathered}$

Solution

Let us begin to simplify the expression below:

$\begin{gathered} x=\frac{2\pm\sqrt[]{(-2)^2-(4)(1)(10)}}{2} \n \n x=\frac{2\pm\sqrt[]{(-2*-2)^{}-(4*1*10)}}{2} \n \n x=\frac{2\pm\sqrt[]{4-40}_{}}{2} \n \n x=\frac{2\pm\sqrt[]{-36}}{2} \n \n \text{From the laws of indices, we have:} \n \sqrt[]{a* b}=\sqrt[]{a}*\sqrt[]{b} \n \n x=\frac{2\pm\sqrt[]{-1*36}}{2} \n \n x=\frac{2\pm(\sqrt[]{-1})(\sqrt[]{36})}{2} \n \n \text{ We know that, } \n \sqrt[]{-1}=i \n \n x=(2\pm(i)(6))/(2) \n \n x=(2\pm6i)/(2) \n \n x=(2(1\pm3i))/(2) \n \n 2\text{ Crosses out} \n \n x=1\pm3i \end{gathered}$

Final Answer

The solution to the quadratic equation is

$x=1\pm3i$

What is the relationship between 0.04 and 0.004?

Answers

I think the answer is that both are fractions whose denominators are powers of ten. 0.04 is 4 out of 100 and 0.004 is 4 out of 1000

Please answer this correctly

Answers

Answer:

# of roses # of bushes

2 4

3 5

Step-by-step explanation:

If you count, 4 times the data showed 2 and 5 times the data showed 3.

Answer:

max001 is a spammer

Step-by-step explanation:

2 roses = 4 bushes

3 roses = 5 bushes

Mark me brainleist plz

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