Answer:
29-(2c+3)=2(c+3)+c=
We move all terms to the left:
29-(2c+3)-(2(c+3)+c)=0
We get rid of parentheses
-2c-(2(c+3)+c)-3+29=0
Step-by-step explanation:
Answer:
Solution for 29-(2c+3)=2(c+3)+c equation:
Simplifying
29 + -1(2c + 3) = 2(c + 3) + c
Reorder the terms:
29 + -1(3 + 2c) = 2(c + 3) + c
29 + (3 * -1 + 2c * -1) = 2(c + 3) + c
29 + (-3 + -2c) = 2(c + 3) + c
Combine like terms: 29 + -3 = 26
26 + -2c = 2(c + 3) + c
Reorder the terms:
26 + -2c = 2(3 + c) + c
26 + -2c = (3 * 2 + c * 2) + c
26 + -2c = (6 + 2c) + c
Combine like terms: 2c + c = 3c
26 + -2c = 6 + 3c
Solving
26 + -2c = 6 + 3c
Solving for variable 'c'.
Move all terms containing c to the left, all other terms to the right.
Add '-3c' to each side of the equation.
26 + -2c + -3c = 6 + 3c + -3c
Combine like terms: -2c + -3c = -5c
26 + -5c = 6 + 3c + -3c
Combine like terms: 3c + -3c = 0
26 + -5c = 6 + 0
26 + -5c = 6
Add '-26' to each side of the equation.
26 + -26 + -5c = 6 + -26
Combine like terms: 26 + -26 = 0
0 + -5c = 6 + -26
-5c = 6 + -26
Combine like terms: 6 + -26 = -20
-5c = -20
Divide each side by '-5'.
c = 4
Simplifying
c = 4
Answer:
b = 12
Step-by-step explanation:
The mistake Megan has made is that she has squared the lengths and then added it instead of taking away the squared length's. The method she used was to work out the hypotenuse, so the correct method would be as follows:
a² + b² = c²
→ Substitute in the values
5² + b² = 13²
→ Simplify the equation
25 + b² = 169
→ Minus 25 from both sides to isolate b²
b² = 144
→ Square root both sides to find the value of b
b = 12