Which construction is partially represented by the diagram on the baseball field? Explain the next set of instructions to correctly finish the construction.
Which construction is partially represented by the diagram on the - 1

Answers

Answer 1
Answer:

Answer:

Construction of an angle bisector is partially represented by the diagram on the baseball field.

Step-by-step explanation:

Angle bisector of an angle bisects it into two equal angles.

Construction of an angle bisector is partially represented by the diagram on the baseball field.

Consider the figure:

From point B, draw an arc by opening the compass up to the same extend as we did while drawing arc from point A.

Take the point of intersection of both the arcs as C.

Join OC.

OC is the angle bisector of the angle.


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If f(x) = x2 + 2x + 1 and g(x) = 3(x + 1)2, which is anequivalent form of f(x) + g(x)?
O x2 + 4x + 2
O 4x2 + 2x + 4
O 4x2 + 8x + 4
o 10x2 + 20x + 1

Answers

The equivalent form of f(x) + g(x), if  f(x) = x² + 2x + 1 and g(x) = 3(x + 1)² is

4x² + 8x + 4, so option C is correct.

What is a function?

In the case of a function from one set to the other, each element of X receives exactly one element of Y. The function's domain and co-domain are respectively referred to as the sets X and Y as a whole.

Given:

f(x) = x² + 2x + 1 and g(x) = 3(x + 1)²

Calculate the equivalent form as shown below,

f(x) + g(x) = x² + 2x + 1 + 3(x + 1)²

Simplify the above equation,

f(x) + g(x) = x² + 2x + 1 + 3(x² + 2x + 1)

f(x) + g(x) = x² + 2x + 1 + 3x² + 6x + 3

f(x) + g(x) = 4x² + 8x + 4

To know more about function:

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the answer should be C

(4m+3)9+6m +10n
Simplifeid

Answers

Answer:

42m+10n+27

Step-by-step explanation:

Adding like terms

Answer: look at the picture

Step-by-step explanation: Hope this help :D

Julie started solving the equation 3x=4+2(3-x)

Answers

Answer:

x=2

Step-by-step explanation:

3x=4+2(3-x)

Distribute 2 to 3 and x

3x=4+6-2x

Add 2 to both side of the equal sign and combine 4 and 6

5x=10

divide both sides by 5

x=2

The population of a city (in millions) at time t (in years) is P(t)=2.6 e 0.005t , where t=0 is the year 2000. When will the population double from its size at t=0 ?

Answers

Answer:

  year 2139

Step-by-step explanation:

The population will double when the factor e^(.005t) is 2.

  e^(.005t) = 2

  .005t = ln(2)

  t = ln(2)/0.005 = 138.6

The population will be double its size at t=0 when t=138.6. That is the population will be about 5.2 million in the year 2139.

The population will double by the year 2139 from its value of 2.6 million in year 2000.

Population function :

P(t) = 2.6 {e}^(0.005t)

Population size at t = 0

P(0) = 2.6 {e}^(0.005(0))  = 2.6(1) = 2.6

Population at t = 2.6 million.

For the population to double ;

2.6 × 2 = 5.2 million :

5.2 = 2.6 {e}^(0.005t)

We solve for t

(5.2)/(2.6) =  {e}^(0.005t)

2 =  {e}^(0.005t)

Take the In of both sides

ln(2)  = 0.005t

t \:  =  ln(2)  / 0.005 = 138.629

The population will double after 139 years

Therefore, the population will double by the 2139 (Year 2000 + 139 years) = year 2139.

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Safegate Foods, Inc., is redesigning the checkout lanes in its supermarkets throughout the country and is considering two designs. Tests on customer checkout times conducted at two stores where the two new systems have been installed result in the following summary of the data.System System B
n1=120 n2=100
x1=4.1 minutes x2=3.4 minutes
σ1=2.2minutes σ2= 1.5 minutes

Test at the 0.05 level of significance to determinewhether the population mean checkout times of the two newsystems differ. Which system is preferred?

Answers

Answer:

We conclude that the population means checkout times of the two new systems differ.

Step-by-step explanation:

We are given the result in the following summary of the data;

System          System B

n1=120             n2=100

x1=4.1 min       x2=3.4 min

σ1=2.2 min     σ2= 1.5 min

Let \mu_1 = population mean checkout time of the first new system

\mu_2 = population mean checkout time of the second new system

So, Null Hypothesis, H_0 : \mu_1=\mu_2      {means that the population mean checkout times of the two new systems are equal}

Alternate Hypothesis,H_A : \mu_1\neq \mu_2      {means that the population mean checkout times of the two new systems differ}

The test statistics that will be used here is Two-sample z-test statistics because we know about population standard deviations;

                          T.S.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{(\sigma_1^(2) )/(n_1) + (\sigma_2^(2) )/(n_2)} }  ~ N(0,1)

where, \bar X_1 = sample mean checkout time of the first new systems = 4.1 min

\bar X_2 = sample mean checkout time of the second new systems = 3.4 min

\sigma_1 = population standard deviation of the first new systems = 2.2 min

\sigma_2 = population standard deviation of the second new systems = 1.5 min

n_1 = sample of the first new systems = 120

n_2 = sample of the second new systems = 100

So, the test statistics =  \frac{(4.1-3.4)-(0)}{\sqrt{(2.2^(2) )/(120) + (1.5^(2) )/(100)} }  

                                    =  2.792

The value of z-test statistics is 2.792.

Now, at 0.05 level of significance, the z table gives a critical value of -1.96 and 1.96 for the two-tailed test.

Since the value of our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the population mean checkout times of the two new systems differ.

90 percent confidence interval for the proportion difference p1−p2 was calculated to be (0.247,0.325). Which of the following conclusions is supported by the interval?A. There is evidence to conclude that p1>p2 because 0.325 is greater than 0.247.
B. There is evidence to conclude that p1C.There is evidence to conclude that p1>p2 because all values in the interval are positive.
D. There is evidence to conclude that p1E. There is evidence to conclude that p2>p1 because 0.247 and 0.325 are both greater than 0.05.

Answers

You can use the fact that the 90% confidence interval given is all positive value for the test statistic being the difference of p_1 and p_2.

The conclusion that is supported by the given confidence interval is given by:

Option C: There is evidence to conclude that p_1 > p_2 because all values in the interval are positive.

How can we conclude that there is evidence that  p_1 > p_2?

Since it is given that the difference is measured by p_1 - p_2,

and  since the given confidence interval at 90% confidence for that difference is obtained to be (0.247,0.325), thus we can say that 90% difference value of   p_1 - p_2, will be lying in that given interval.

Since the interval is all positive, thus we can say that 90% of the times, the difference  p_1 - p_2 will be positive which indicates that p_1 > p_2

Thus, the conclusion that is supported by the interval is given by:

Option C: There is evidence to conclude that p_1 > p_2 because all values in the interval are positive.

Learn more about confidence interval here:

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Answer:

C

Step-by-step explanation:

Statistics!!

When we have a confidence interval for the difference in proportions or means, our null hypothesis is always that there's no difference. (H0 = p1-p2 = 0.)

If the difference is positive, that means we have sufficient evidence p1>p2.

If it's negative, then we have sufficient evidence p2>p1.

Why not A: incorrect interpretation of the interval

Why not B: doesn't look like a complete answer

Why not D: also doesn't look like a complete answer

Why not E: this confuses the definition of alpha-level and p-value with confidence interval values. If those were p-values and greater or less than an alpha-level, we would reject or fail to reject the null hypothesis. That isn't the case here.