PHYSICS COLLEGE

A 1,200 kg car travels at 20 m/s. what is it’s momentum ?

Answers

Answer 1

Answer:

The momentum of the car is 24000 Kg•m/s

Momentum is defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, we can obtain the momentum of the car as follow:

Mass = 1200 Kg

Velocity = 20 m/s

Momentum =?

Momentum = mass × velocity

Momentum = 1200 × 20

Momentum of car = 24000 Kg•m/s

Learn more about momentum:

brainly.com/question/250648

Answer 2

Answer:

Answer:

24000 kg·m/s

Explanation:

Momentum is Mass x Velocity, so 1200 kg time 20 m/s = 24000 kg-ms/s

Related Questions

A rock is thrown from the top of a building 146 m high, with a speed of 14 m/s at an angle 43 degrees above the horizontal. When it hits the ground, what is the magnitude of its velocity (i.e. its speed).
Define reflection of sound?
What is matter? explain and give example
Convert this measurement664.2 km=____cm
Which of these objects are constantly in motion? Select all that apply.A.EarthB.PlanesC.TrainsD.BloodE.SunF.Cars

An interstellar space probe is launched from Earth. After a brief period of acceleration it moves with a constant velocity, 70.0% of the speed of light. Its nuclear-powered batteries supply the energy to keep its data transmitter active continuously. The batteries have a lifetime of 15.9 years as measured in a rest frame. (a) How long do the batteries on the space probe last as measured by mission control on Earth? yr
(b) How far is the probe from Earth when its batteries fail, as measured by mission control?
ly
(c) How far is the probe from Earth, as measured by its built-in trip odometer; when its batteries fail?
ly

Answers

Answer:

22.26 years

, 15.585 light years , 11.13 light years

Explanation:

$t' = t/(√(1-(v/(c*v)/c))$

= $15.9/√((1-0.7*0.7))$

= 22.26 years

0.7*c*22.26 years

=15.585 light years

0.7*c*15.9

=11.13 light years

A boy throws a 15 kg ball at 4.7 m/s to a 65 kg girl who is stationary and standing on a skateboard. After catching the ball, the girl is travelling at: a) 0.88 m/s b) 0 m/s c) 1.1 m/s d) 3.2 m/s

Answers

Answer:

$a)v_(f)=0.88m/s$

Explanation:

To solve this problem we use the Momentum's conservation Law, before and after the girl catch the ball:

$\n p_(1)=p_(2)\nm_(ball)*v_(o.ball)+m_(girl)*v_(o.girl) = m_(ball)*v_(f.ball) + m_(girl)*v_(f.girl)$ (1)

At the beginning the girl is stationary:

$v_(o.girl)=0m/s$ (2)

If the girl catch the ball, both have the same speed:

$v_(f.girl)=v_(f.ball)=v_(f)$ (3)

We replace (2) and (3) in (1):

$m_(ball)*v_(o.ball) = (m_(ball)+m_(girl))*v_(f) \n$

We can now solve the equation for v_{f}:

$v_(f)=(m_(ball)*v_(o.ball))/((m_(ball)+m_(girl)))=(15*4.7)/(15+65)=0.88m/s$

Let's say you have a plot for Pendulum experiment. Let's assume g for this experiment was measured (from the slope of the plot) to be 9.78 [ms^-2]. The vertical intercept, however, is 0.021 [s^2]. What might this translate to for a measurement of the length offset systematic in all the length measurements? Length Offset =[mm] .011

Answers

Answer:

The length is 5.2 mm.

Explanation:

Given that,

Time period T²= 0.021 s²

Gravity due to acceleration = 9.78 m/s²

We need to calculate the length

Using formula of time period of pendulum

$T=2\pi\sqrt{(l)/(g)}$

$l=(gT^2)/(4\pi^2)$

Where, l = length

g = acceleration due to gravity

T = time period

Put the value into the formula

$l=(9.78*0.021)/(4*\pi^2)$

$l=0.0052\ m$

$l=5.2\ mm$

Hence, The length is 5.2 mm.

A can of soup has a mass of 0.35 kg. The can is moved from a shelf that is 1.2 m off the ground to a shelf that is 0.40m off the ground. How does the gravitational potential energy of the can change?

Answers

Answer:

2.744 difference

Explanation:

Use Pe=mgh

So when the soup is at a height of 1.2m, its Pe is (.35kg)(9.8m/ $s^(2)$ )(1.2m)=4.116

when the soup is at a height of .40m, its Pe is (.35kg)(9.8m/ $s^(2)$ )(.40m)=1.372

So youre looking at a 2.744 difference in pe

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. Calculate the magnitude and direction of the net horizontal force on the rope.

Answers

In a game of tug of war the magnitude and direction of the net horizontal force on the rope is 74 N.

What is force?

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. The magnitude and direction of the net horizontal force on the rope is,

F = 182 - 108

F = 74 N

The magnitude and direction of the net horizontal force on the rope is 74 N.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ2

Answer:

74 N to the right

Explanation:

the forces are going in opposite horizontal directions, meaning that they are directly opposing each other. this means that you can subtract the force applied in the direction that is greater from the direction that is less to get the net force for the greater direction

this means 182 N - 108 N = 74 N to the right

Tripling the displacement from equilibrium of an object in simple harmonic motion will bring about a change in the magnitude of the object's acceleration by what factor?