PHYSICS HIGH SCHOOL

The worker’s pull on the handle of the cart can best be described as a force havingGroup of answer choices

magnitude, only

neither magnitude nor direction

direction, only

both magnitude and direction

Answers

Answer 1
Answer:

Answer:

both magnitude and direction

Explanation:

The worker's pull on the handle of the cart is best described as the force having both magnitude and direction.

  • This is a vector quantity
  • The force is channeled to move the cart in a specific direction.
  • Also, the pull on the cart can be quantified, and so it have magnitude.
  • Most physical properties either have magnitude or direction or both.

In this case, the worker is pulling the cart towards a specified direction.

Therefore, the fitting choice is both magnitude and direction.

Answer 2
Answer:

Final answer:

The pull on a cart's handle by a worker is a force, which in physics, has both magnitude and direction. The magnitude is how hard the pull is and the direction is where the pull is heading to.

Explanation:

In physics, the worker’s pull on the handle of the cart can best be described as a force having both magnitude and direction. Force is a vector quantity, meaning it has both magnitude (the strength of the force) and direction. For instance, when pulling a cart, the force magnitude would relate to how hard you are pulling, while the direction would be the way you are pulling towards. Without both components, the force cannot be fully described or accurately calculated.

Learn more about Physics Force here:

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A person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.A) What is her average speed over the entire trip?B) What is her average velocity over the entire trip?

Answers

Answer:

A.) 3.975 m/s

B.) 0.925 m/s

Explanation:

Given that a person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.

A) What is her average speed over the entire trip?

The average speed = (4.90 + 3.05)/2

Average speed = 7.95/2

Average speed = 3.975 m/s

B) What is her average velocity over the entire trip?

Since velocity is a vector quantity, that is, we consider both the magnitude and direction

Average velocity = ( 4.90 - 3.05)/2

Average velocity = 1.85/2

Average velocity = 0.925 m/s

A 24 kg box is being pulled across a floor by a horizontal rope. What is the Normal force?

Answers