Stephanie took a science exam that had two parts. Part 1: She got 16 questions correct, which was 45 of the number of part 1 questions. Part 2: She got 16 questions correct, which was 23 of the number of part 2 questions. What was the total number of questions on Stephanie's exam?

Answers

Answer 1
Answer:

Given :

Stephanie took a science exam that had two parts. Part 1: She got 16 questions correct, which was 4/5 of the number of part 1 questions. Part 2: She got 16 questions correct, which was 2/3 of the number of part 2 questions.

To Find :

The total number of questions on Stephanie's exam.

Solution :

Let, number of questions in Part 1 is x :

16=(4)/(5)x\n\nx=20

Let, number of questions in Part 2 is y :

16=(2)/(3)y\n\ny=24

Therefore, total number of questions on Stephanie's exam are 20 + 40 = 60.

Hence, this is the required solution.


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K³-4j+12 when k=8, j=2​

Answers

k³-4j+12 = (8)³ - 4(2) + 12
= 512 - 8 + 12
= 516


Therefore, the value of the expression k³-4j+12 when k=8 and j=2 is 516.

conjectures math statement 2(x^2+5)=60 what is the reason? 2x^2+10=60 what is the reason? 2x^2=50 what is the reason? x^2=25 what is the reason? x=+ minus 5.

Answers

2(x^2+5)=60 to 2x^2+10=60
distributive property (a(b+c)=ab+ac)

2x^2+10=60 to 2x^2=50
property of equality or something like thht (a=a and b=b, so a-b=a-b) and also
 addative inverse (a+-a=0) (added -10 to both sides)

2x^2=50 to x^2=25
propery of euality and multiplicative inverse (a times 1/a=1) and one produce property (1 times a=a)

x^2=25 to x=+/-5
property of equality and something else

Answer:

2(x^2+5)=60 to 2x^2+10=60

distributive property (a(b+c)=ab+ac)

2x^2+10=60 to 2x^2=50

property of equality or something like thht (a=a and b=b, so a-b=a-b) and also

 addative inverse (a+-a=0) (added -10 to both sides)

2x^2=50 to x^2=25

propery of euality and multiplicative inverse (a times 1/a=1) and one produce property (1 times a=a)

x^2=25 to x=+/-5

property of equality and something else

Step-by-step explanation:

HELPP!!
Select the correct answer.
What is the value of arcsin ?

Answers

For this case we have that by definition, it is called arcsine (arcsin) from a number to the angle that has that number as its sine.

We must find the arcsin (\frac {\sqrt {2}} {2}). Then, we look for the angle whose sine is \frac {\sqrt {2}} {2}.

We have to, by definition:

Sin (45) = \frac {\sqrt {2}} {2}

So, we have to:

arcsin (\frac {\sqrt {2}} {2}) = 45

Answer:

Option B

Answer:

Choice B

Step-by-step explanation:

An option is to find the the square root of 2 in decimals is (1.414213562)/(2) ≈ <strong>0.7071067812</strong>

Now we can use the arc sine, which is the inverse of a sin.

To do this we must use a scientific calculator. By pressing the arc sin button and entering in 0.7071067812, we can find the arc sin, which is 45°.

4 ÷ 5 can be written as a fraction represented by which of the following?

Answers

is this a multiple choice question? Strange wording, but I believe the answer is (4)/(5)

Find the greatest number you can add to 4315 without having to regroup

Answers

  4315
+5684
 9999    So 5684 is the greatest number you can write.

Final answer:

The greatest number that can be added to 4315 without having to regroup is 5644. When added together, the sum doesn't result in a carryover to the next place value.

Explanation:

In Mathematics, particularly arithmetic, regrouping is the process of making groups of tens when adding or subtracting two numbers. When the question asks for the greatest number that can be added to 4315 without having to regroup, we are essentially looking for a number that when added to 4315 doesn't result in a carryover to the next place value.

Considering the number 4315, you would notice that the units digit is 5, the tens digit is 1, the hundreds digit is 3, and the thousands digit is 4. This means for each position we can add a number up to 9 without needing to regroup. Hence, the greatest number you can add to 4315 without needing to regroup would be 5644 (which gives 9 in the units place, 1+5=6 in the tens place, 3+4=7 in the hundreds place, and 4+4=8 in the thousands place).

Learn more about Arithmetic here:

brainly.com/question/29116011

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Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 per 5 minutes of childcare. Which comparison of the childcare costs is accurate?

Answers

Answer:

Gym B and Gym A charge the same hourly rate for the children.

Step-by-step explanation:

They are the same amount. if you divide 60 by 5 it is 12 and when you multiply .75 by 12 it equals 9. so Both are $9.00 an hour.