The perimeter of a rectangular room is 32m.The length of a diagonal is 8m more than than the width.Find the dimensions of the room.

Answers

Answer 1
Answer:

Answer: 12m by 4m.

Step-by-step explanation: You are looking for the dimensions of the room here, also known as the length and width.

Let’s make width equal to x since we don’t know what the value is. Length is going to be x + 8 since the diagonal is 8m MORE than the width.

w = x

l = x + 8

Use the equation for the perimeter.

P = 2l + 2w

Plug in your values:

32 = 2(x + 8) + 2(x)

Now, solve for x! First start by distributing the 2:

32 = 2x + 16 + 2x

Next, add like terms:

32 = 4x + 16

Subtract 16 from both sides:

16 = 4x

Divide by 4 on both sides:

4 = x

Now we have x, but remember, x is equal to the width. We just solved for width so now we need length.

l = x + 8

Plug in your x and solve:

l = 4 + 8

l = 12

Your length is 12m and your width is 4m, therefore, the dimensions of the rectangular room are 12m by 4m.


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Simplify 16/3(6/8b+9/2).

Write in simplest form.

Answers

3/8 = 0.37500
hope its right...!!!!!
 16/3(6/8b+9/2) Final result : 4 • (b + 6)

Step by step solution :Step  1  : 9 Simplify — 2 Equation at the end of step  1  : 16 6 9 —— • ((— • b) + —) 3 8 2Step  2  : 3 Simplify — 4 Equation at the end of step  2  : 16 3 9 —— • ((— • b) + —) 3 4 2 Step  3  :Calculating the Least Common Multiple :

 3.1    Find the Least Common Multiple 

      The left denominator is :       4 

      The right denominator is :       2 

        Number of times each prime factor
        appears in the factorization of:
 Prime 
 Factor 
 Left 
 Denominator 
 Right 
 Denominator 
 L.C.M = Max 
 {Left,Right} 
2212 Product of all 
 Prime Factors 
424


      Least Common Multiple: 
      4 

Calculating Multipliers :

 3.2    Calculate multipliers for the two fractions 


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 1

   Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

 3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well. 

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respectiveMultiplier.

L. Mult. • L. Num. 3b —————————————————— = —— L.C.M 4 R. Mult. • R. Num. 9 • 2 —————————————————— = ————— L.C.M 4 Adding fractions that have a common denominator :

 3.4       Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3b + 9 • 2 3b + 18 —————————— = ——————— 4 4 Equation at the end of step  3  : 16 (3b + 18) —— • ————————— 3 4 Step  4  : 16 Simplify —— 3 Equation at the end of step  4  : 16 (3b + 18) —— • ————————— 3 4 Step  5  :Step  6  :Pulling out like terms :

 6.1     Pull out like factors :

   3b + 18  =   3 • (b + 6) 

Final result : 4 • (b + 6)

COMPLETE THE EXERCISE BELOW TO DECOMPOSE 930

Answers

I saw the complete problem:

complete the exercise below to decompose 930

930 = _____ tens = ____ x ____

My answer is:

930 = ninety-three tens or 93 tens = 93 x 10

1+3+5......+99 Si rezolvarea va rog fiindca nu inteleg !!

Answers

I hope this helps you

Find the answer to (6!) in math

Answers

\boxed{n!=1\cdot2\cdot3\cdot4\cdot...\cdot n}\n\n6!=1\cdot2\cdot3\cdot4\cdot5\cdot6=\boxed{720}
1*2*3*4*5*6=720.
Hope I helped

Find the zeros of the function h(x)=x^2-5x-50 by factoring

Answers

h(x)=x^2-5x-50=x^2-5x-25-25=x^2-25-5x-25\n\n=(x^2-25)-(5x+25)=(x^2-5^2)-5(x+5)\n\n=(x-5)\underline{(x+5)}-5\underline{(x+5)}=(x+5)(x-5-5)=(x+5)(x-10)\n\nAnswer:Zeros\ are\ x=-5\ and\ x=10.

It takes Tom 1 hour to lay 30 bricks. He has to lay 180 bricks.
Tom starts to lay the bricks at 9 a.m
He has half an hour break at 11 a.m
He has another half an hour break at 1 p.m

What time should Tom finish laying the 180 bricks?

Answers

he should finish laying the bricks at 3:00pm