Write a real world problem that could be modeled by a linear function whose x-intercept is 5 and y-intercept is 60.
Answers
The real-world problem that could be modeled by a linear function will be y = 60 - 12x.
What is a linear equation?
A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
x/a + y/b = 1
Where 'a' is the x-intercept of the line and ‘b’ is the y-intercept of the line.
The linear function whose x-intercept is 5 and y-intercept is 60. Then the equation is given as,
x/5 + y/60 = 1
Convert the equation into a slope-intercept form. Then we have
x/5 + y/60 = 1
12x + y = 60
y = 60 - 12x
The real-world problem that could be modeled by a linear function will be y = 60 - 12x.
More about the linear equation link is given below.
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Answers
if an angle measures 56 degrees less than 90 degrees that means that it is 90- 56= 34
so, therefore the measure of each angle is 34 degrees.
Final answer:
To find the measure of each angle, assume the measure of one angle is x degrees. The other angle measures 56° less than the measure of its complementary angle. Solve the equation to find the measures of the angles.
Explanation:
To find the measure of each angle, let's assume the measure of one angle is x degrees.
According to the problem, the other angle measures 56° less than the measure of its complementary angle, which means it is 90 - x - 56 = 34 - x degrees.
Since two angles are complementary, their sum should be equal to 90 degrees.
Therefore, x + (34 - x) = 90.
Solving the equation, we get x = 28 degrees and 34 - x = 34 - 28 = 6 degrees.
So, the measure of each angle is 28 degrees and 6 degrees, respectively.
Learn more about Complementary angles here:
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Answers
simplify fraction
set deonmenator equal to zero
that value is VA
cannot cross VA
fidn HA
if the degree of the numerator is less than the degree of the denomenator, then the HA is y=0
if the degree is equal, then divide he leading coeficient of the numerator by the leading coeficient of the deonmenator
to find if the fn crosses the HA, set the HA equaal to the reduced fn and solve, if you get a false statement, then it does not cross
holes are found by where if you have the numberator and deonmentoar are the same degree and they have a factor of same multiplicity example
f(x)=
there is a hole at x=3 and to find the y coordinate, subsitute x=3 into reduced fraction
so
14.
make one fraction
f(x)=(2x-1)/(x-1)
x and y intercept
xint is f(x)=0
xintercept= 1/2 (1/2,0)
y intercept is when x=0 so set x=0
-1/-1=1
yintercept is y=1 aka (0,1)
VA set denom to zeero
x-1=0
x=1
VA at x=1
HA degree is same so divide leading coefs
2/1=2
HA at y=2
crosses HA?
2=(2x-1)/(x-1)
2x-1=x-1
x-1=-1
x=0
crosses ha at x=0 and
f(x)=(2(0)-1)/(0-1)=-1/-1=1
crosses HA at (0,1)
no holes
find where the fn is negative and positive
(2x-1) is zero at x=1/2
x-1 is zero at x=1
so in between, those, (1/2 and 1), the graph is negative (positive/negative=negative)
outside of that interval, the graph is positive (positive/positive=positive, negative/negative=negative) so graph is drawn on attachment
15. factor
f(x)=(x-2)/[(x-4)(x+1)]
VA set denom to zero
x-4=0
x+1=0
VAs at x=4 and -1
HA
degree of numberateor is smaller to HA is y=0
crosses HA?
0=(x-2)/(x^2-3x-4)
0=x-2
2=x
yes, at (2,0)
holes? no
find positive and negative
graph included
16.
VA=x is x=1
x=1
x-1=0
reduced denom is (x-1)
HA is y=2
degrees are same
2/1=2
(2x+something)/(x-1)
xint at -4,=
deonm when set to zero, etuals -4
2x+something=0 yeilds x=-4 so
2(-4)+something=0
-8+something=0
something=8
(2x+8)/(x-1)
hole at (6,4)
factored out bit is x=6
x=6
x-6=0
multiply whole equation by (x-6)/(x-6)
the function is
f(x)=
f(x)=
17.
factor
f(x)=
x+5=0
x=-5
hole at x=-5
sub into reduced fn (f(x)=
4/7
hole at (-5,4/7)
degree is same so divide leading coeficients
1/1=1
HA=1
VA is set reduced denom to zero
(x-2) is reduced
x-2=0
x=2
VA is at x=2
B.4/12
C.7/12
D.8/12
Answers
Answers
First we need a conversion equations to get from pounds to ounces
1pound=16ounce
2pounds=2*16=32 ounces of cucumber
3pounds=3*16=48 ounces of lettuce
Now that all of the vegetables are in ounces, we can solve for their total weight.
x=32+8+48+15=103 ounces
He bought 103 ounces of vegetables in total.
1 pound equals to 16 ounces.
2 pounds + 8 ounces + 3 pounds + 15 ounces = 2 * 16 + 8 + 3 * 16 + 15 = 32 + 8 + 48 + 15 = 103 ounces
Result: Simon bought 103 ounces in total.
Answers
V=LWH
Vbin=20*18*14
Vbin=5040 in^3
Vcloset=60*36*72
Vcloset=155520 in^3
how many Vbins=1Vcloset?
how many 5040=155520
divide both sides by 5040
how many=30.8
round up
31 bins will hold all stuff
but only 30 can fit in closet, but will not hold al stuf
is the answere that i had gottent
Answers
8/2=4
now, if each student wanted to paint part of a board and there are four students then divide 1 by 4
1/4=.25 or 1/4
so 4 students can paint one board while the other 4 students pain the other board