A line graph usually reveals a relationship between which factors

Answers

Answer 1

Answer:

Answer:

variables on the horizontal and vertical axis (slope, outliers, +/- correlation, etc)

Explanation:

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Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. Howfar away must he and Marty stand to allow the car to accelerate from rest to a speedof 39.2 m/s?

In which example is government encouraging innovation?Pollution permits are issued by the government.

A government agency constructs a dam.

Patents and copyrights are issued by the government.

Regulations require that cigarette packages advise consumers of health risks.

Answers

The correct answer is PATENTS AND COPYRIGHTS ARE ISSUED BY THE GOVERNMENT.

A government is said to be encouraging innovation if it takes special steps to encourage the citizen to be creative in their endeavors. Innovation is one of the key ingredient that a nation needs to grow and it is the responsibility of the government to promote it. By issuing patents and copyright, a government can encourage the citizen to be original in their works and to produce new things.

a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

Answers

The expression for the bullet's speed vbullet is $v=\sqrt{(2\mu_k (m+M)gd)/(m)}$ and the speed of a 9.0 g bullet is v=16.8 m/s

Explanation:

A bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

The initial kinetic energy of the bullet is given by

$K_i = (1)/(2)mv^2$

where

m is the mass of the bullet

v is the initial speed of the bullet

The expression for the bullet's speed vbullet is

$F=\mu_k (m+M) g$

where

$\mu_k$ is the coefficient of kinetic friction

g is the acceleration of gravity

The work done by the force of friction is

$W=-Fd = -\mu_k (m+M)g d$

where d is the displacement of the block+bullet.

Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:

$W=K_f - K_i = -K_i$

And so

$-\mu_k (m+M) g d = -(1)/(2)mv^2$

By solving for v, the solution for the bullet speed:

$-\mu_k (m+M) g d = -(1)/(2)mv^2\nv=\sqrt{(2\mu_k (m+M)gd)/(m)}$

The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.

We have:

the mass of the bullet, m = 9.0 g = 0.009 kg

the mass of the block, M = 12 kg

the distance covered by the block+bullet, d = 5.4 cm = 0.054 m

the coefficient of friction, $\mu_k = 0.20$

the acceleration of gravity, $g = 9.8 m/s^2$

By substituting, we got

$v=\sqrt{(2 (0.20) (0.009 kg+12 kg)(9.8 m/s^2)(0.054 m))/(0.009 kg)}=16.8 m/s$

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uk=2m*the normal force
the distance d is needed only if you were asked about work

Calculate the velocity of a 1650 kilogram satellite.

Answers

There's not enough information given to do that calculation.

-- The question doesn't specify whether the satellite is on the
shelf in the Vehicle Assembly Building before being installed
onto the booster, or inside the nose-cone as the rocket is slowly
being rolled to the launch-pad, or on its ascent to orbit after launch,
or in orbit. Its velocity in each of these situations is different.

-- The question reveals only the satellite's mass, but the answer
doesn't depend on that number. The satellite's velocity depends
on the speed of the truck or the rocket carrying it, or the size of
the orbit it's in. The question doesn't give any of these.

==> In particular, the size of a satellite's orbit, or its speed in that
orbit, DO NOT depend on its mass.

For example:
There are hundreds of TV satellites ... the ones that match the
Earth's rotation and appear motionless in the sky. They have
many different sizes, shapes, and masses, but they're all in the
same geostationary orbit, 22,000 miles above the equator, and
they all have the same average orbital velocity, zero displacement
per (23 hours 56 minutes 4 seconds).

Which phrase is not an example of intracellular communication? A. molecular movement within a cell
B. reaction to pheromones
C.molecule in a cell changes function of cell
D. control of cell division

Answers

The phrase which is not an example of intracellular communication is :

C) Molecule in a cell changes function of cell.

"Intracellular communication"

The phrase which is not an example of intracellular communication is the molecule in a cell changes function of cell.

The intracellular communication could be a sort of communication which takes put inside a cell or interior a cell.

The intracellular speaks to inside a cell, subsequently, the development of the particle inside a cell may be with cytoplasmic gushing, cargo vesicle transport or any other instrument will speak to the intracellular communication.

Thus, the correct answer is C.

Learn more about "Intracellular communication":

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Answer:

The answer is C

Explanation:

I ave K12 and i just finished it.

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