How do you solve y=2.5x+5

Answers

Answer 1

Answer: if you are solving for x.
y=2.5x+5
you subtract 5 from both sides.
-5=2.5x
then divide both sides with 2.5
-5/2.5 2.5/2.5
the 2.5s will cancel each other out.
x=-2

Answer 2

Answer: $slope\ is\ for\ y=0\n\ny=2,5x+5\n0=2,5x+5\ \ \ | subtract\ 5\n-5=2,5x \ \ \ | divide\ by\ 2,5\nx=-2 ---> SLOPE\n\n\intercept\ is\ for\ x=0\n\ny=5----> INTERCEPT$

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What is the solution to4(2x– 3)= 2(3x+ 1)?

-5

1

7

10

Answers

4 (2x – 3)= 2( 3x + 1)
(4 (2x – 3)= 2( 3x + 1)) ÷ 2
2 (2x – 3) = (3x + 1)
4x - 6 = 3x +1
-3x -3x
__________
x - 6 = 1
+6 +6
______
x = 7

A student has earned the following scores on four 100-point tests this marking period: 63, 72, 88, and 91. What score must the student earn on the ﬁfth and ﬁnal 100-point test of the marking period to earn an averagetest grade of 80 for the ﬁve tests?

Answers

In order to have average 80 score from 5 tests, student needs to have 400 points (80%*500=0.8*500=400)
So far he has 63+72+88+91= 314
400-314=86

He needs to get 86 points from the last test.
Since he is obviously getting better at tests, i think he'll manage :)

1. Find the Least Common Multiple of these two monomials:
See picture

Answers

Answer:

The last choice is correct

$LCM=120a^4b^7c^5$

Step-by-step explanation:

Least Common Multiple (LCM)

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

$12a^4b^2c^5$

$40a^3b^7c^1$

The prime factors of the first monomial are:

$2^2,3,a^4,b^2,c^5$

The prime factors of the second monomial are:

$2^3,5,a^3b^7c^1$

LCM = Multiply $2^3*3*5*a^4*b^7*c^5$

These are all the factors the greatest number of times they occur.

Operating:

$LCM=8*15*a^4*b^7*c^5$

$\boxed{LCM=120a^4b^7c^5}$

The last choice is correct

If you were to roll the dice one time what is the probability it will NOT land on a 2? Put your answer in fraction form.

Answers

The probability that it will not land on a 2 is 5/6

Probability is the likelihood or chance that an event will occur.

It will land on 2, Prob (land on 2) = 1/6

It will not land on 2, the probability will be given as:

Prob (not land on a 2) = 1 - 1/6

Prob (not land on a 2) = 5/6

Hence the probability that it will not land on a 2 is 5/6

Learn more on Probability here: brainly.com/question/25870256

Answer:

5/6

Step-by-step explanation:

On a standard 6-sided die, there is only one 2. That means that there are 5 other numbers that it could land on (1, 3, 4, 5, 6).

Using that information, the probability of it not landing on a 2 is 5 out of 6 or 5/6. This is because you must do part over whole. The "part" in this situation is the 5 "wanted" numbers, and the "whole" is 6 because there are six potential numbers that it could land on.

I hope this helps.

What needs to be corrected in the following construction for copying ∠ABC with point D as the vertex?

Answers

To construct an angle bisector for ∠ABC, use a compass and straightedge to create intersecting arcs, connecting the vertex with the intersection point to form the bisector. Avoid changing compass width or inaccurate arc intersections.

Constructing an angle bisector for ∠ABC using only a compass and a straightedge involves a series of precise steps. Here are the instructions along with common mistakes to avoid:

Step-by-Step Instructions:

Draw ∠ABC: Begin by drawing the angle ∠ABC with the given vertex at point B.

Place Compass at Point B: Use your compass and place its needle point (the sharp end) at point B, the vertex of the angle.

Adjust Compass Width: Open the compass to a width that allows you to draw two arcs that intersect both rays of the angle. Ensure the compass width remains fixed during the construction.

Draw Arcs: With the compass set, draw an arc that intersects the first ray, AB. Keep the compass needle fixed at B, and draw another arc that intersects the second ray, BC. Label the points of intersection with the rays as D and E.

Connect B and E: Using your straightedge, draw a straight line that connects point B and point E.

Bisect the Angle: The line BE bisects angle ∠ABC, creating two equal angles, ∠ABE and ∠EBC. Angle ∠ABE is the bisector of ∠ABC.

Common Mistakes to Avoid:

Changing Compass Width: Keeping the compass width consistent is crucial. Changing it during the construction will result in an inaccurate angle bisector.

Inaccurate Arc Intersection: Ensure that the arcs drawn from points B intersect the rays AB and BC accurately at points D and E. Inaccurate intersection points will lead to an incorrect angle bisector.

Not Labeling the Bisector: It's essential to label the constructed angle bisector (∠ABE) to distinguish it from the original angles.

By following these steps carefully and avoiding common mistakes, you can accurately construct an angle bisector for ∠ABC using only a compass and a straightedge.

For more such information on:angle bisector

brainly.com/question/24334771

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The question probable may be:

How do you construct an angle bisector for ∠ABC using only a compass and a straightedge? Provide step-by-step instructions, and highlight any common mistakes to avoid in the construction.

From looking at both the pictures shown for the problems which can be found in the attachment below. I concluded that what needs to be corrected in the following construction for copying ∠ABC with point D as the vertex is answer choice:

C) The third arc should cross the second arc.

I hope this helps, Regards.

The greatest common factor of 3m2n + 12mn2 is

Answers

$3m^2n + 12mn^2=3mn\cdot(m+4n)$

$3m^(2)n + 12mn^(2)$

$3mn( m + 4n)$

So, $3mn$ is the greatest common factor of $3m^(2)n + 12mn^(2)$

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