Answer:
19.3 m/s
Explanation:
Take down to be positive. Given:
Δy = 19 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (19 m)
v = 19.3 m/s
Answer:
Because of gender, caste, race, wealth, and religion etc.
Explanation:
Social stratification means society is divided in different categories, class, layers or groups due to gender, caste, race, wealth, and religion etc.
Society stratifies due to the following regions:
(1) Gender discrimination means male- female difference.
(2) Unequal distribution of income and wealth
(3) Different types of religions
(4) Racism
(5) Type of education
(6) Social status etc.
Societies stratify, or divide their members into distinct groups or layers, based on various factors such as wealth, income, cultural beliefs, and status. Factors like prestige or age are also influential in some societies. Stratification systems can be either closed, allowing little social mobility, or open, where movement between classes is possible.
Societies stratify, or categorize people into different social standings, for various reasons. In many societies, stratification is an economic system, predominantly determined by wealth and income. Often, people interact chiefly with others of the same social standing, allowing economic and cultural factors to organize individuals into distinct groups or layers.
Societal stratification can also be driven by cultural beliefs that place value on specific attributes or characteristics such as prestige or age. For example, in some cultures, the elderly are esteemed, while in other societies, they are overlooked. Such cultural attitudes play a significant role in reinforcing stratification systems.
Also, stratification occurs when there is a difference in status or power between various societal roles, leading to a hierarchical organization of different groups - an example is the clear socioeconomic status (SES) division within society where individuals with more resources are seen at the top layer.
Closed and open stratification systems present themselves in different societies. Closed systems offer little opportunity for change in social position, whereas open systems, like class systems, are based on achievement, allowing movement and interaction between layers and classes.
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Answer:
The current flows in the second wire is
Explanation:
Given that,
Upward current = 24 A
Force per unit length
Distance = 7.0 cm
We need to calculate the current in second wire
Using formula of magnetic force
Where,
=force per unit length
I₁= current in first wire
I₂=current in second wire
r = distance between the wires
Put the value into the formula
Hence, The current flows in the second wire is
Answer:
450 pm
Explanation:
The electron is held in orbit by an electric force, this works as the centripetal force. The equation for the centripetal acceleration is:
a = v^2 / r
The equation for the electric force is:
F = q1 * q2 / (4 * π * e0 * r^2)
Where
q1, q2: the electric charges, the charge of the electron is -1.6*10^-19 C
e0: electric constant (8.85*10^-12 F/m)
If we divide this force by the mass of the electron we get the acceleration
me = 9.1*10^-31 kg
a = q1 * q2 / (4 * π * e0 * me * r^2)
v^2 / r = q1 * q2 / (4 * π * e0 * me * r^2)
We can simplify r
v^2 = q1 * q2 / (4 * π * e0 * me * r)
Rearranging:
r = q1 * q2 / (4 * π * e0 * me * v^2)
r = 1.6*10^-19 * 1.6*10^-19 / (4 * π * 8.85*10^-12 * 9.1*10^-31 * (7.5*10^5)^2) = 4.5*10^-10 m = 450 pm
The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the capacitor is half-filled with the dielectric.
Answer:
U_eq = 1.99 * 10^(-10) J
Explanation:
Given:
Plate Area = 10 cm^2
d = 0.01 m
k_dielectric = 3
k_air = 1
V = 15 V
e_o = 8.85 * 10 ^-12 C^2 / N .m
Equations used:
U = 0.5 C*V^2 .... Eq 1
C = e_o * k*A /d .... Eq 2
U_i = 0.5 e_o * k_i*A_i*V^2 /d ... Eq 3
For plate to be half filled by di-electric and half filled by air A_1 = A_2 = 0.5 A:
U_electric = 0.5 e_o * k_1*A*V^2 /2*d
U_air = 0.5 e_o * k_2*A*V^2 /2*d
The total Energy is:
U_eq = U_electric + U_air
U_eq = 0.5 e_o * k_1*A*V^2 /2*d + 0.5 e_o * k_2*A*V^2 /2*d
U_eq = (k_1 + k_2) * e_o * A*V^2 / 4*d
Plug the given values:
U_eq = (3 + 1) * (8.82 * 10^ -12 )* (0.001)*15^2 / 4*0.01
U_eq = 1.99 * 10^(-10) J
Answer:
E = (0, 0.299) N
Explanation:
Given,
Let be the angle of the electric fields by first and second charge at the point A.
Electric field by charge at point A,
Electric field by the charge at point A,
Now,
Net electric field in horizontal direction at point A
Net electric field in vertical direction at point A.
Hence, the net electric field at point A,
The speed of the combined object after collision is 0 m/s.
Total momentum before collision = total momentum after collision
m₁u₁ + m₂u₂ = (m₁ + m₂)a
m₁ = object 1 mass = m, u₁ = velocity of object 1 before collision = v, m₂ = mass of object 2 = 3m, u₂ = velocity of object 2 before collision = -v/3, a = velocity after collision
mv + 3m(-v/3) = (m + 3m)a
mv - mv = 4ma
0 = 4ma
a = 0 m/s
The speed of the combined object after collision is 0 m/s.
Find out more at: brainly.com/question/17166755
Answer:
the answer is 0 m/s
Explanation:
This question is describing the law of conservation of momentum
First object has mass =m
velocity of first object = v
second object = 3m
velocity of second object = v/3
the law of conservation of momentum is expressed as
m1V1 - m2V2 = (m1+ m2) V
substituting the parameters given;
making V as the subject of formular
V =
V =
V =
= 0 m/s