CHEMISTRY COLLEGE

In Natural selection, individuals whose unique characteristics are well-suited for an environment tend to survive and produce more offspring. true or false?

Answers

Answer 1
Answer:

Answer: True

Explanation:

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A solid is hard brittle and electrically nonconducting. it's melt ( the liquid form of the substance) and an aqueous solution containing the substance conduct electricity. classify solid.
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Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is 2.5 x 10-14. Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is a.2.5 x 10-14 M. b. 8.5 x 10-6 M c. 6.3 x 10-11 M d. 1.3 x 10-12 M e. 5.0 x 10-2 M f. 1.8 x 10-5 M
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The quantity of mass of an object contained within its volume is a measure of

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the answer is density
the quantity of mass of an object contained within its volume is a measure of density

Two identical sister chromatids are held together at whatregion on a duplicated chromosome?
a Chromatin
b Centromere
C Centriole
Check it

Answers

  • After DNA duplication, the chromosome becomes composed of two identical structures, called sister chromatids, which are joined at the centromere area.

Final answer:

Sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment. Chromatin and centrioles do not serve this function. The correct option is b) Centromere.

Explanation:

Two identical sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment for sister chromatids. During cell division, the spindle fibers attach themselves to the centromere to pull apart the sister chromatids into two separate cells. This process helps ensure that each new cell receives an identical and complete set of chromosomes. Neither chromatin nor centriole holds sister chromatids together. Chromatin refers to the material chromosomes are made up of, which includes DNA and protein, while centrioles are involved in cell division. In summary, the precise answer to your question is option b) Centromere.

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In 100 grams of sweet peas there are 14.5 carbohydrates,5.7 grams of sugars,5.1 grams of dietary fiber, 5.4 grams of protein and 0.4 grams of fat what is the percent composition of each?

Answers

14.5 % carb
5.7% sugar
5.1% fiber
5.4% protein
0.4% fat

Vinegar, the commercial name for acetic acid, HC2Hs02, is a monoprotic organic acid. A 5% (w/v) solution of vinegar is used to titrate a sample of an antacid that contains CaCO3 is the only basic component. If one antacid tablet contains 800 mg of CaCOs in it, then calculate how many milliliters of vinegar should be required to completely neutralize the CaCO3 present in one tablet of antacid?

Answers

19.2 g of vinegar solution

Explanation:

Here we have the chemical reaction between acetic acid (CH₃COOH) and calcium carbonate (CaCO₃):

2 CH₃COOH +  CaCO₃ → (CH₃COO)₂Ca + CO₂ + H₂O

number of moles = mass / molecular weight

number of moles of CaCO₃ = 0.8 / 100 = 0.008 moles

Knowing the chemical reaction, we devise the following reasoning:

if       2 moles of CH₃COOH react with 1 moles of CaCO₃

then X moles of CH₃COOH react with 0.008 moles of CaCO₃

X = (2 × 0.008) / 1 = 0.016 moles of CH₃COOH

mass = number of moles × molecular weight

mass of acetic acid (CH₃COOH) = 0.016 × 60 = 0.96 g

Now to find the volume of vinegar acid (solution of acetic acid) with a concentration of 5% (weight/volume) we use the following reasoning:

if there are         5 g of acetic acid in 100 mL of vinegar solution

then there are   0.96 g of acetic acid in Y mL of vinegar solution

Y = (0.96 × 100) / 5 = 19.2 g of vinegar solution

Learn more about:

weight/volume concentration

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What is the rate of effusion for a gas that has a molar mass twice that of a gas thateffuses at a rate of 3.6 mol/min?

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Explanation:

ans: o.o846

A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74 atm. When the experiment is repeated using 0.020 mol of ethanoic acid instead of methyl methanoate, the measured pressure is lower than 0.74 atm. The lower pressure for ethanoic acid is due to the following reversible reaction.CH3COOH(g)+CH3COOH(g) ⇋ (CH3COOH)2(g)+Assume that when equilibrium has been reached, 50 percent of the ethanoic acid molecules have reacted.i. Calculate the total pressure in the vessel at equilibrium at 450 K.ii. Calculate the value of the equilibrium constant, Kp, for the reaction at 450 K

Answers

Explanation:

Starting moles of ethanol acid = 0.020 mol

At the equilibrium 50 % of the ethanol acid molecules reacted

∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %

                                                                   = 0.010 mol

Moles of ethanol acid remain = 0.020 mol + 0.010 mol = 0.010 mol

Moles of the product (CH3COOH)^(2) gas formed are calculated as

0.010 mol CH3COOH * 1 mol (CH3COOH)^(2) / 2 mol CH3COOH

= 0.005 mol (CH3COOH)^(2)

Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol (CH3COOH)^(2)

That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol

Now Calculate the pressure  :

0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas

P1/n1 = P2/n2

P2 = P1*n2 / n1

      = 0.74 atm * 0.015 mol / 0.020 mol

     = 0.555 atm
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15) What is the hydronium ion concentration [H3O + ] of a 0.125 M hydrocyanic acid solution with Ka = 4.9 × 10-10? The equation for the dissociation of hydrocyanic acid is: HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN- (aq)
Ascorbic acid (vitaminc.Does not contain a traditional carboxylic acid group, but it is, nevertheless, still fairly acidic (pka = 4.2). Identify the acidic proton and explain your choice using resonance structures, if necessary:
Calculate the molar solubility of mercury (I) bromide, Hg2Br2, in 1.0 M KBr. The Ksp for Hg2Br2 is 5.6 X 10−23. (Hint: How would the Br− concentration from the sparingly soluble compound itself compare to the Br− concentration that comes from the KBr?