The Tacoma narrows bridge collapsed due to?A. Refraction
B. Reflection
C. Diffraction
D. Resonance
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Which is a property of a neutron?A) 0 charge B) +1 charge C) -1 Charge D) Essentially no mass
Part AGiven the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ Calculate ΔG°rxn for the following reaction. 18 NO(g) → 6 N2O(g) + 6 NO2(g) Answer Choices To Choose From: A) -3.83 kJ B) -138 kJ C) -23.0 kJ D) 23.0 kJ E) 138 kJ Part B CO2(g)→C(s)+O2(g)ΔH∘rxn= +393.5 kJ (ΔSsys<0, ΔSsurr<0) In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part D will be spontaneous A) The reaction is spontaneous at all temperatures. C) The reaction is spontaneous at high temperatures. D) The reaction is nonspontaneous at all temperatures.
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The balanced chemical reaction is:
N2 + 3H2 = 2NH3
We are given the amount of ammonia formed from the reaction. This is where we start our calculations.
0.575 g NH3 (1 mol NH3 / 17.03 g NH3) (3 mol H2 / 2 mol NH3) ( 2.02 g H2 / 1 mol H2) = 0.10 g H2
Answer:
Answer is 0.102.
Explanation:
no subscripts
no 1's for coefficients
WILL GIVE BRAINLIEST!
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Answer:
I kinda forgot. I'm sorry if I didn't answer your question.
Explanation:
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An oxidation reaction involves the loss of electrons or an increase in the oxidation state of an element. Options B, C, and D represent oxidation reactions, while option A does not.
Let's analyze the given options:
A. AuCl₄⁻ → AuCl₂⁻
In this reaction, the gold atom goes from a +3 oxidation state (AuCl₄⁻) to a +1 oxidation state (AuCl₂⁻). This means the gold atom gains two electrons, indicating a reduction rather than oxidation. Therefore, option A is not an oxidation reaction.
B. Mn⁷⁺ → Mn²⁺
In this reaction, the manganese atom goes from a +7 oxidation state to a +2 oxidation state. This indicates a decrease in the oxidation state, which means the manganese atom gains electrons. Therefore, option B represents an oxidation reaction.
C. Co³⁺ → Co²⁺
In this reaction, the cobalt atom goes from a +3 oxidation state to a +2 oxidation state. Similar to option B, this indicates a decrease in the oxidation state, representing an oxidation reaction.
D. Cl₂ → ClO₃⁻
In this reaction, the chlorine molecule (Cl₂) is converted to a chlorate ion (ClO₃⁻). Here, the chlorine atom undergoes an increase in oxidation state, changing from an oxidation state of 0 in Cl₂ to an oxidation state of +5 in ClO₃⁻. This indicates the loss of electrons by chlorine, making option D an oxidation reaction.
Therefore, options B, C, and D represent oxidation reactions, while option A does not.
Learn more about oxidation reaction from the link given below.
#SPJ2
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Answer is: scientists use different types of model to show different characteristics (chemical properties) of compound.
For example, ball and stick model gives informations about bond lenght and space filling model gives information about space occupied by atoms.
In chemistry, the ball-and-stick model is a molecular model of a chemical substance which is to display both the three-dimensional position of the atoms and the bonds between them. The atoms are represented by spheres, connected by rods which represent the bonds. Every ball represent one atom in one molecule and they have different colors for different atoms (for example, carbon is black, hydrogen is white, nitrogen is blue).
There also other models: skeletal models, polyhedral models, composite models, computer-based models.
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Answer: The dissociation of the base will be further suppressed.
Explanation: Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
For the given equation:
If an excess of ammonium salt, such as (which ionizes to give
(aq) ions)
If the concentration of that is the product is increased, so according to the Le-Chatelier's principle, the equilibrium will shift in the direction where decrease of concentration of
takes place. Therefore, the equilibrium will shift in the backward direction and the ions will start associating to form
.