Ms. Howard wrote a test. Part A had true/false questions, each worth points. Part B had multiple choice questions, each worth points. She made the number of points for Part A equal the number of points for Part B. It was the least number of points for which this was possible.
Answers
Full question attached
Answer and explanation:
Since x = number of true or false questions correct
And y = number of multiple choice questions correct
And each question for x =2 points
each question for y=3 points
since she then needs a total score of more than 93 to pass, we add up total correct questions and
Inequality equation = 2x +3y >93
Final answer:
To find the least number of points for which the number of points for Part A is equal to the number of points for Part B, we need to find the least common multiple (LCM) of the values of points for true/false questions and multiple choice questions.
Explanation:
To find the least number of points for which the number of points for Part A is equal to the number of points for Part B, we need to find a common multiple of the values of points for true/false questions and multiple choice questions. Let's assume the number of points for true/false questions is x and the number of points for multiple choice questions is y. We need to find the least common multiple (LCM) of x and y. Once we find the LCM, that will be the minimum number of points for which the number of points in Part A is equal to the number of points in Part B.
For example, if the number of points for true/false questions is 4 and the number of points for multiple choice questions is 6, we can find the LCM as follows:
- List the multiples of 4: 4, 8, 12, 16, 20, 24, ...
- List the multiples of 6: 6, 12, 18, 24, 30, ...
- Find the smallest number that appears in both lists: 12
Therefore, the least number of points for which the number of points in Part A is equal to the number of points in Part B is 12.
Learn more about Least Common Multiple (LCM) here:
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Related Questions
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URGENT PLEASE HELP ME WITH THIS MATH QUESTION
Henry drew a rectangle with a length 5 times as long as its width. Which expression can be used to find the perimeter of the rectangle?a. 5w + w b. 5w + 5w c. 2(5w + w) d. 2(5w + 5w)
Put 983 in scientific notation.
f(4) is_______
f(x) = 4 when x is_________
Answers
Answer:
- 1/2
- 8
Step-by-step explanation:
x = domain, f(x) = range
Look for matching numbers:
- f(4) = 1/2
- f(x) = 4 when x = 8
Answers:
f(4) is 1/2
f(x) = 4 when x is 8
====================================
Explanation:
Saying f(4) means f(x) when x = 4.
Locate 4 in the domain bubble. It points to 1/2 in the range bubble. This means x = 4 and y = 1/2 pair up. So f(4) = 1/2.
--------
When we're told f(x) = 4, we're given that y = 4 since y = f(x). So we need to find the x value that gets us to y = 4.
Locate y = 4 in the range. Trace the arrow in reverse to get to x = 8
f(8) = 4
Answers
mainn factor, intrest
6
9
27
Answers
The value under the radical is 3
Explanation
9^(2/3) This means 9 squared then find find the cube root of the answer.
9^(2/3)=∛(9^2 )
= ∛81
= ∛(3×3×3×3) = ∛(3)³ ₓ ∛3
= 3∛3
The value under the radical is 3
I hope this now shows clearly the number under the radical is 3.
Answer:
The value remains under the radical is 3
Step-by-step explanation:
Given the expression
We have to find the value remains under the radical.
It can be written as
⇒
⇒
⇒
Hence, the value remains under the radical is 3
Answers
Answer:
School needs to collect at least 144 box tops each day to meet their goal.
Step-by-step explanation:
The total requirement of box tops = 2,000
The number of box tops they have already received = 872
So, the box tops left = Total number required- Number of tops received
=2,000 - 872
= 1,128 box tops are left so far.
Number of days left = 8
So, number of minimum tops needed each day =
=
Hence, they need to collect at least 144 box tops each day to meet their goal.
Select the appropriate response
A) x≥5
B) x≥7
C) x≥4
D) x≥9
Answers
Answer:
C) x≥4 and x ≤ -4
Step-by-step explanation:
| 8x | ≥ 32
To remove the absolute values, we get two equations, one positive and one negative
8x ≥ 32 and 8x ≤ -32
Divide each side by 8
8x/8 ≥ 32/8 and 8x/8 ≤ -32/8
x ≥ 4 and x ≤ -4
north. Find the magnitude of the
car's resultant vector.
Answers
Answer:
73.2km
Step-by-step explanation:
first you have to decompose 46 km into y and x components.
x=sin40°*46km
x=0.64*46km
x=29.44km
y=cos40°*46km
y=0.76*46km
y=34.96
now you add the y components together
32+34.96=66.98
finally use Pythagorean thereom to find the resultant vector.
a*a+ b*b=c*c
66.98*66.98+29.44*29.44=c*c
c*c= 4486.3+866.7
c=√5353
c=73.2 km this is the approximate value